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Unit 3: Geometry

Unit 3: Geometry. Lesson #6: Triangles & Pythagorean Theorem. Find missing sides in right triangles To determine if a triangle is right or not To explain Pythagorean theorem To explain how to and when to use the Pythagorean theorem. LEARNING GOALS. Equilateral:. A. A. B. C. C.

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Unit 3: Geometry

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  1. Unit 3: Geometry Lesson #6: Triangles & Pythagorean Theorem

  2. Find missing sides in right triangles • To determine if a triangle is right or not • To explain Pythagorean theorem • To explain how to and when to use the Pythagorean theorem LEARNING GOALS

  3. Equilateral: A A B C C BC = 3.55 cm B BC = 5.16 cm G H I HI = 3.70 cm Scalene: A triangle in which all 3 sides are different lengths. AC = 3.47 cm AB = 3.47 cm AB = 3.02 cm AC = 3.15 cm Isosceles: A triangle in which at least 2 sides are equal. Classifying Triangles by Sides • A triangle in which all 3 sides are equal. GI = 3.70 cm GH = 3.70 cm

  4. A triangle in which all 3 angles are less than 90˚. G ° 76 ° ° 57 47 H I A ° 44 ° 108 ° 28 C B Acute: Obtuse: • A triangle in which one and only one angle is greater than 90˚& less than 180˚ Classifying Triangles by Angles

  5. Right: • A triangle in which one and only one angle is 90˚ Equiangular: • A triangle in which all 3 angles are the same measure. Classifying Triangles by Angles

  6. polygons triangles scalene isosceles equilateral Classification by Sides with Flow Charts & Venn Diagrams Polygon Triangle Scalene Isosceles Equilateral

  7. polygons triangles right acute equiangular obtuse Classification by Angles with Flow Charts & Venn Diagrams Polygon Triangle Right Obtuse Acute Equiangular

  8. Pythagoras • Lived in southern Italy during the sixth century B.C. • Considered the first true mathematician • Used mathematics as a means to understand the natural world • First to teach that the earth was a sphere that revolves around the sun

  9. Right Triangles • Longest side is the hypotenuse, side c (opposite the 90o angle) • The other two sides are the legs, sides a and b • Pythagoras developed a formula for finding the length of the sides of any right triangle

  10. The Pythagorean Theorem • “For any right triangle, the sum of the areas of the two small squares is equal to the area of the larger.” • a2 + b2 = c2

  11. Pythagoras’ Theorem This is the name of Pythagoras’ most famous discovery. It only works with right-angled triangles. The longest side, which is always opposite the right-angle, has a special name: hypotenuse

  12. Pythagoras’ Theorem c a b c²=a²+b²

  13. Pythagoras’ Theorem c²=a²+b² c c b a y a a b b a c c

  14. Using Pythagoras’ Theorem 1m 8m What is the length of the slope?

  15. Using Pythagoras’ Theorem c a= 1m b= 8m c²=a²+ b² ? c²=1²+ 8² c²=1 + 64 c²=65

  16. Using Pythagoras’ Theorem We need to use the square root button on the calculator. √ √ c²=65 How do we find c? It looks like this = , Enter65 Press So c= √65 = 8.1 m (1 d.p.)

  17. 9cm 12cm Example 1 c c²=a²+ b² b c²=12²+ 9² a c²=144 + 81 c²= 225 c = √225= 15cm

  18. 4m 6m s Example 2 a b c²=a²+ b² s²=4²+ 6² c s²=16 + 36 s²= 52 s = √52 =7.2m (1 d.p.)

  19. Finding the shorter side 7m h 5m c c²=a²+ b² 7²=a²+ 5² a 49=a² + 25 ? b

  20. Finding the shorter side + 25 49 = a² + 25 We need to get a² on its own. Remember, change side, change sign! 49 - 25= a² a²= 24 a = √24 = 4.9 m (1 d.p.)

  21. 13m 6m 169 = a² + 36 w Change side, change sign! Example 1 c c²= a²+ b² 13²= a²+ 6² b 169 = w² + 36 a 169 – 36 = a² a²= 133 a = √133 = 11.5m (1 d.p.)

  22. The Pythagorean theorem has far-reaching ramifications in other fields (such as the arts), as well as practical applications. • The theorem is invaluable when computing distances between two points, such as in navigation and land surveying. • Another important application is in the design of ramps. Ramp designs for handicap-accessible sites and for skateboard parks are very much in demand. Applications

  23. A baseball “diamond” is really a square. You can use the Pythagorean theorem to find distances around a baseball diamond. Baseball Problem

  24. The distance between consecutive bases is 90 feet. How far does a catcher have to throw the ball from home plate to second base? Baseball Problem

  25. Baseball Problem To use the Pythagorean theorem to solve for x, find the right angle. Which side is the hypotenuse? Which sides are the legs? Now use: a2 + b2 = c2

  26. Baseball ProblemSolution • The hypotenuse is the distance from home to second, or side x in the picture. • The legs are from home to first and from first to second. • Solution: • x2 = 902 + 902 = 16,200 • x = 127.28 ft

  27. Ladder Problem • A ladder leans against a second-story window of a house. If the ladder is 25 meters long, and the base of the ladder is 7 meters from the house, how high is the window?

  28. Ladder ProblemSolution • First draw a diagram that shows the sides of the right triangle. • Label the sides: • Ladder is 25 m • Distance from house is 7 m • Use a2 + b2 = c2 to solve for the missing side. Distance from house: 7 meters

  29. Ladder ProblemSolution • 72 + b2 = 252 • 49 + b2 = 625 • b2 = 576 • b = 24 m • How did you do?

  30. Success Criteria • I can identify a right-angle triangle • I can identify Pythagorean theorem • I can identify when to use Pythagorean theorem • I can use Pythagorean theorem to find the longest side • I can use Pythagorean theorem to find the shortest side • I can solve problems using Pythagorean theorem

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