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convert the following: 4.0 x 10 6  0.02 = _____ Find the gfw of KOH How many grams are in 0.10 moles of KOH? ACT-prep question: The moon rotates once while going around the earth once. As a result. the moon follows an elliptical path The sun is eclipsed by the moon every seven years.

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## Quiz:

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convert the following:

4.0 x 106 0.02 = _____

Find the gfw of KOH

How many grams are in 0.10 moles of KOH?

ACT-prep question:

The moon rotates once while going around the earth once. As a result.

the moon follows an elliptical path

The sun is eclipsed by the moon every seven years.

Only one side of the moon faces the Earth.

Every fourth year is a leap year.

March 3, 2005

Quiz:

2 x 108

K = 39 amu, 0 = 16 amu, H = 1 amu

1(39) + 1(16) + 1(1) =56 amu

or 56 g/mole

0.10 moleKOH_56g KOH_

1mole KOH

5.6 g KOH

http://www.uccs.edu/~tchriste/courses/PES105/105lectures/105lecmotions.htmlhttp://www.uccs.edu/~tchriste/courses/PES105/105lectures/105lecmotions.html

here’s a link for anyone interested in planetary motions and the relationship

between the earth and sun.

Molarity = moles solute dm3 of solution

HW 16: #42 49 page 205; #95, 98

page 218; H#96,100

Should be completed today!

Tonight’s e.c. HW is # 17

?grams  moles

1000 cm3  dm3

Multiply the

Numerator –

Divide the

Denominator

Underline the

important

information.

What is the

definition of

Molarity?

Ca = 40.0

2H = 2(1)

O= 2(16)

74 g/mole Ca(OH)2

M = moles

dm3

1mole Ca(OH)2

74 g Ca(OH)2

1000 cm3

1dm3

M =2.0 g Ca(OH)2

500 cm3

0.054 mole/dm3

or 0.054 M Ca(OH)2

Since you don’t have moles

or dm3, look for units that can

easily be converted to moles or to dm3

Describe the preparation of the following solution: 1.00 dm3 of 0.3M NiCl2

Underline

important

information

Use the

quantity of

the given

solution

as

numerator

To figure

out what

to do with

0.3M, you need

to know what

it means!

Since you

can’t measure

out a mole,

you will

need to find

grams.

0.3 moles

dm3

129.5 g NiCl2

mole NiCl2

1.00 dm3

M = moles

dm3

Find gfw of

NiCl2

Ni =58.7

2 Cl = 2(35.4)

129.5 g/mole

Dissolve 38.8 g NiCl2 in

enough water to get

a volume of 1.00 dm3

Convert

cm3 to

dm3

Describe the preparation of the following solution: 2.50 x 103 cm3 of 0.400M NiCl2

Underline

important

information

Use the

quantity of

the given

solution

as

numerator

To figure

out what

to do with

0.3M, you need

to know what

it means!

Since you

can’t measure

out a mole,

you will

need to find

grams.

2.50 x 103 cm3 = 2500 cm3 = 2.50 dm3

1000 cm3/dm3

0.400 moles

dm3

129.5 g NiCl2

mole NiCl2

2.50 dm3

M = moles

dm3

Find gfw of

NiCl2

Ni =58.7

2 Cl = 2(35.4)

129.5 g/mole

Dissolve 130 g NiCl2 in

enough water to get

a volume of 2.50 dm3

16, #42 49 page 205; #95, 98 page 218; H#96,100First find moles, then find molarity.
• Each Group of two students will come up to the board and explain one problem. This is required, and is worth 10 points. We have no more than 2 days to do this.
• EXTRA CREDIT ASSIGNMENT:
• Build a mobile showing all of the conversions which are possible from moles to other units. The mobile must be attractive and helpful from 10 feet away. This is worth 25 points.

gram formula weight

M

 volume

6.02x 1023

molecules

HW 17: #50-55 page 208; #101p218
• % = the proportion out of 100 pieces
• If there were 100, how much would be …
• In a package of M&Ms 15 were brown, 6 were yellow, and 4 were blue. What % were brown?
• 15 + 6 + 4 = total number of M&Ms = 25
• 15/25 = the fraction which are brown.
• 60% are brown

15 x 100%

25

Find the % nitrogen in ammonia.
• NH3 = ammonia

N = 14.0

3H = 3 x 1.0

17.0 amu

100%

14.0 amu N

17.0 amu NH3

= 82.4% N in

NH3

http://www.ausetute.com.au/percentc.html Tutorial for extra help

6.00 g Fe(NO3)2 are dissolved in 100.0 cm3 of solution. What is the molarity of this solution?

6.00 g Fe(NO3)2

1 moleFe(NO3)2

1000 cm3

Underline the

important

information. Then,

determine

what you

know, and

want to know.

The Molarity is

defined as

moles per unit

volume, so

find moles

and divide

volume!

Multiply the

Numerator –

Divide the

Denominator

100.0 cm3

180 g Fe(NO3)2

1 dm3

= 0.334 M Fe(NO3)2

Fe = 56

N = 14

O = 16

1 Fe = 1(56)

2 N = 2(14)

6 O = 6(16)

56

28

96

180.g/mole

H = 2(1.01)

O = 16.0

H2O = 18 g/mole

% H = 0.112 x 100%

11.2% H

% O = 0.889 x 100%

88.9% O

To find the % composition of H2O

%H = 2.02 g H2

18 g/mole H2O

%O = 16.0 g H2

18 g/mole H2O