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Learn about the properties of acids and bases, operational definitions, and how compounds can be classified based on their observable characteristics. Explore Arrhenius acid/base definitions and pH calculations.
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Acids and Bases Operational definitions are based on observed properties. Compounds can be Classified as acid or base by observing these sets of properties.
Properties of Acids • Taste sour (acere – Latin for sour) (Lemons, vinegar) • Cause certain organic dyes to change colour (Turns blue litmus paper to red – BAR) • Acid properties are destroyed by Bases (React with bases to form a salt and water) • Acid solutions are Electrolytes (substance in solution that conduct an electric current – Acids can be strong or weak electrolytes) • Acids react (corrode) with active metals (Group I and II as well as Zn and Aluminum) (Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)) • Acids react with carbonates (CO32-) and hydrogen carbonates (HCO31-) to produce carbon dioxide gas {2HCl(aq) + Na2CO3(s) → 2NaCl(aq) + H2O(l) + CO2(g)} • Certain nonmetal oxides will dissolve to produce acid solutions. (SO3(g) + H2O → H2SO4(aq) (SO3(g) is the acid anhydride – without water)
Properties of Bases • Bases taste bitter; mustard and soap • Bases cause weak organic acids (dyes) to change colour (red litmus paper to blue {BB} Basic Blue • Acids destroy base properties - react with acids to form salts and water • Bases are electrolytes {strong or weak} • Feel soapy, slippery • Bases are formed when the oxide of some metals dissolve in water (CaO(s) + H2O → Ca(OH)2(aq) {CaO is the base anhydride}
Acid/Base definitions • Definition #1: Arrhenius (traditional) • Acids are compounds with ionizable hydrogen– produce H+ ions (or hydronium ions H3O+) in solution • Bases are compounds that produce OH- ions in solution (problem: some bases don’t have hydroxide ions!) The reaction between an acid and a base:H+(aq) + OH-(aq) → H2O (l)
Arrhenius acid is a substance that produces H+ (H3O+) in water. The HCl molecule is ionized. (ionization) Arrhenius base is a substance that produces OH- in water. The ions are dissociated. (dissociation)
Some acids have more than one ionizable hydrogen • H2SO4 → H+(aq) + HSO41-(aq • HSO41- → H+(aq) + SO42-(aq) H2SO4 is diprotic • H3PO4(aq) → H+(aq) + H2PO41-(aq) • H2PO41-(aq) → H+(aq) + HPO42-(aq) • HPO42-(aq) → H+(aq) + PO43-(aq) Phosphoric acid is a triprotic acid.
Water self-ionization H2O ↔ H+(aq) + OH-(aq) [H+] = [OH-] = 10-7Mat SATP Keq = [H+][ OH-] [H2O(l)] Kw = [H+][ OH-] = 10-7 x 10-7 (at 25ºC) Kw = 10-14 at SATP
H2O ↔ H+(aq) + OH-(aq) What happens to this equilibrium if HCl(g) dissolves in the water? HCl(g) + H2O(l) → H3O+(aq) + Cl-(aq) • Increasing Decreasing • H2O ↔ H3O+(aq) + OH-(aq) • [H+] > [OH-] = acidic • What happens when sodium hydroxide dissolves? NaOH(s) + H2O → Na+(aq) + OH-(aq) • Decreasing Increasing • H2O ↔ H3O+(aq) + OH-(aq) • [H+] < [OH-] = basic (alkaline solution) If [H+] = 10-7 then [OH-] = 10-7 solution is neutral (SATP)
pH and logs • [H+] is important in the study of acid-base chemistry. pH is the widely used scale to show [H+]. • pH = -log[H+] or pH = 1 . log[H+] [H+] = 10 – pH (the antilog) A logarithm is the power to which ten must be raised to get a number. log1000 = log(103) = 3
pH calculations • For a neutral solution • pH = -log[H+] • pH = -log [10-7] • pH = - [-7] • pH = 7 at SATP • Example: • [H+] = 5 x 10-3 • pH = -log [5 x 10-3] • pH = -log [0.005] • pH = - (-2.3) = 2.3
pH and pOH • pOH = - log [OH-] or [OH-] = 10 - pOH • Kw = [H+] x [OH-] = 1 x 10-14 (at 25ºC) • pKw= pH + pOH • 14= pH + pOH • Example: • If pH = (2.3) what is the [OH-]? • pH + pOH = 14 • pOH = 14 – pH • pOH = 14 – 2.3 • pOH = 11.7 • pOH = -log [OH-] • [OH-] = inverse log -11.7 or (10 - 11.7) • [OH-] = 2.0 x 10-12
[H3O+], [OH-] and pH • What is the pH of the 0.0010 M NaOH solution? • [OH-] = 0.0010 (or 1.0 X 10-3 M) • pOH = - log 0.0010 • pOH = 3 • pH + pOH = 14 • pH = 14 – 3 = 11 • OR Kw = [H3O+] [OH-] • 1.0 x10-14 = [H3O+] x 1.0 X 10-3 • [H3O+] = 1.0 x 10-11 M • pH = - log (1.0 x 10-11) = 11.00
Problem 1:The pH of rainwater collected in a certain region of the northeastern New Brunswick on a particular day was 4.82. What is the H+ ion concentration of the rainwater? [H+] = 1.51 x 10-5 Problem 2:The OH- ion concentration of a blood sample is 2.5 x 10-7M. What is the pH of the blood? pOH = 6.6 pH = 7.4 Problem 3: A chemist dilutes concentrated hydrochloric acid to make two solutions: (a) 3.0 M and (b) 0.0024 M. Calculate the [H3O+], pH, [OH-], and pOH of the two solutions at 25°C. b) [H3O+] = [2.4x10-3], pH = 2.62, pOH = 11.38, [OH-] = 4.2 x 10-12 a) [H3O+] = [3.0], pH = - 0.48, pOH = 14.48, [OH-] = 3.3 x 10-15 Problem 4: What is the [H3O+], [OH-], and pOH of a solution with pH = 3.67? Is this an acid, base, or neutral? [H3O+] = 2.14 x10-4, pOH = 10.33, [OH-] = 4.68x 10-11 It is an acid. Problem 5: Problem #4 with pH = 8.05? [H3O+] = 8.92 x10-9, pOH = 5.95, [OH-] = 1.12x 10-6 It is an acid.
Definition #2: Brønsted – Lowry Acids – proton donor A “proton” is a hydrogen ion (the atom lost it’s electron) Bases – proton acceptor (accepts a hydrogen ion) No longer needs to contain the OH- ion Acid/Base Definitions
A Brønsted-Lowry acid is a proton donor A Brønsted-Lowry base is a proton acceptor acid conjugateacid conjugatebase base
+ + + H H O H O Cl Cl H H H The Bronsted-Lowry concept base conjugate acid conjugate base acid conjugate acid-base pairs • Acids and bases are identified based on whether they donate or accept H+. • “Conjugate” acids and bases are found on the products side of the equation. A conjugate base is the same as the starting acid minus H+.
Practice problems Identify the acid, base, conjugate acid, conjugate base, and conjugate acid-base pairs: CH3OOH(aq) + H2O(l) CH3COO–(aq) + H3O+(aq) conjugate base conjugate acid acid base conjugate acid-base pairs OH–(aq) + HCO3–(aq) CO32–(aq) + H2O(l) base acid conjugate base conjugate acid conjugate acid-base pairs
Base Conjugate acid \ \ NH3(g) + H2O(l) ↔ NH4+(aq) + OH-(aq) / / Acid Conjugate Base HCl(aq) + H2O(l) ↔ H3O+(aq) + Cl-(aq) Acid Base Conjugate Conjugate Acid Base The water has acted as both an acid and a base, depending on what it is mixed with. Substances that can act as both an acid and a base are amphoteric (also called amphiproteric).
Strong acid and base : HA(aq) + H2O(l) ↔ H3O+(aq) + A-(aq) B(aq) + H2O(l) ↔ BH+(aq) + OH-(aq) At equilibrium the ionic form is favored Weak acid and base : HA(aq) + H2O(l) ↔ H3O+(aq) + A-(aq) B(aq) + H2O(l) ↔ BH+(aq) + OH-(aq) At equilibrium the molecular form is favored
CH3COOH(aq) + H2O(l) ↔ H+(aq) + CH3COO-(aq) Keq= [H+] [CH3COO-] . [CH3COOH] [H2O(l)] [H2O] is a constant, so collect the constants (Keq)[H2O(l)] = [H+] [CH3COO-] [CH3COOH] (Keq)[H2O] is represented Ka(ionization constant for an acid) Ka = [H+] [CH3COO-] = 1.8 x 10-5 [CH3COOH] Ka < 1 weak acid General Formula for the ionization constant of a weak acid.