Download
1 / 5
70 likes | 212 Views
This guide explains the concept of linear interpolation using a distance vs. time scenario. It outlines how to estimate values between known data points by utilizing straight lines. The process includes identifying relevant points, plotting them to create triangles, labeling all known values, and solving ratios to find unknown distances and times. For instance, it demonstrates how to determine the distance at 35 seconds and when a distance of 200 meters occurred. This approachable method encourages readers to practice interpolation through guided examples.
E N D
Linear Interpolation (a quick how-to) Wendi Morrison 2010
Situation Distance vs. Time • Start with data, not necessarily linear. What was the distance at 35 s? • Use a straight line to estimate a value between known data. When was the distance 200 m?
What was the distance at 35 s? • Choose the two points that capture 35 s. • Plot the points to make a triangle. • Label what you know. 160 • Make a smaller triangle. • Label the triangle sides. 90 + x 70 x x The triangle is this shape because the graph goes up… 90 30 5 35 40 • Solve the ratio: 10 Round to the same precision as 35 s. • Add x to the lower value: • 90 + 35 = 125 The distance at 35 s was about 125 m.
When was the distance 200 m? • Choose the two points that capture 200 m. • Label what you know. • Plot the points to make a triangle. 250 • Make a smaller triangle. • Label the triangle sides. 200 90 40 160 • Solve the ratio: 40 x 40 + x 50 10 Round to the same precision. • Add x to the lower value: • 40 + 4 = 44 The distance was 200 m at about 44 s.
