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Feedback: Principles & Analysis

Feedback: Principles & Analysis. Dr. John Choma, Jr. Professor of Electrical Engineering University of Southern California Department of Electrical Engineering-Electrophysics University Park; Mail Code: 0271 Los Angeles, California 90089-0271 213-740-4692 [OFF]

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Feedback: Principles & Analysis

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  1. Feedback: Principles & Analysis Dr. John Choma, Jr. Professor of Electrical Engineering University of Southern California Department of Electrical Engineering-Electrophysics University Park; Mail Code: 0271 Los Angeles, California 90089-0271 213-740-4692 [OFF] 626-915-7503 [HOME] 626-915-0944 [FAX] johnc@almaak.usc.edu (E-MAIL) EE 448 Feedback Principles & Analysis Fall 2001

  2. Overview Of Lecture • Feedback • System Representation • System Analysis • High Frequency Dynamics • Open And Closed Loop Damping Factor • Open And Closed Loop Undamped Natural Frequency • Frequency Response • Phase Margin • High Speed Transient Dynamics • Step Response • Rise Time • Settling Time • Overshoot 65

  3. Open Loop Model • Gain: • Parameters •  Zero Frequency Gain •  Frequency Of Zero •  Frequency Of Dominant Pole •  Frequency Of Non–Dominant Pole • Frequency Of Zero Can Be Positive (RHP Zero) Or • Negative (LHP Zero) • Note That A Simple Dominant Pole Model Is Not Exploited • Input And Output Variables • Input Voltage Or Current Is X(s) • Output Voltage Or Current Is Y(s) 66 3

  4. s s 1 – A (0) 1 – z z ol o o A (s) = A = ol ol s s 2 2  s 1 + 1 + ol p p 1 + s + 1 2  2  nol nol p p 1 2 1  = + ol 2 p p 1 2  = p p nol 1 2  ol  ol  ol Open Loop Transfer Function (0) • Damping Factor: • Measure Of Relative Stability • Measure Of Step Response Overshoot And Settling Time • Undamped Natural Frequency: • Measure Of Steady State Bandwidth • Measure Of "Ringing" Frequency And Settling Time • Poles • Dominant Pole Implies • Complex Poles Imply • Identical Poles Imply >> 1 < 1 = 1 67 4

  5. s s f A (0) 1 – T (0) 1 – z z ol o o T (s) = f A (s) = = ol s s 2 2  s 1 + 1 + ol p p 1 + s + 1 2  2  nol nol s A (0) 1 – z cl o A (s) = cl 2 2  s cl 1 + s +  2  ncl ncl Closed Loop Transfer Function • Loop Gain (Return Ratio w/r To Feedback Factor, f ): • Closed Loop Gain: Obtained Through Substitution Of Open Loop Gain Relationship Into Closed Loop Gain Expression 68

  6. s s 1 – A (0) 1 – z z ol o o A (s) = A = ol ol s s 2 2  s 1 + 1 + ol p p 1 + s + 1 2  2  nol nol s A (0) 1 – z cl o A (s) = cl 2 2  s cl 1 + s +  2  ncl ncl   T (0) ol nol  = – T f A cl ol 2 z 1 + T (0) 1 + T (0) o  =  1 + T (0) ncl nol 1 A (0)  cl f Closed Loop Parameters (0) • Closed Loop Damping Factor: • Closed Loop Undamped Frequency: • "DC" Closed Loop Gain: • T(0) Large For Intentional Feedback • T(0) Possibly Large For Parasitic Feedback (0)  (0) 69

  7.  T (0) ol nol  = –  =  1 + T (0) cl ncl nol 2 z 1 + T (0) 1 + T (0) o Closed Loop General Comments • Damping Factor • Potential Instability Increases With Diminishing Damping Factor • Potential Instability Strongly Aggravated By Large Loop Gain • Note: Open Loop Damping Attenuation By Factor Of • Square Root Of One Plus "DC" Loop Gain • For Intentional Feedback Having Closed Loop Gain Of (1/f ), • Worst Case Is Unity Gain (f = 1), Corresponding To Maximal T(0) • Open Loop Zero • Closed Loop Damping Diminished, Thus Potential Instability • Aggravated, For Right Half Plane Open Loop Zero • Closed Loop Damping Increased, Thus Potential Instability • Diminished, For Left Half Plane Open Loop Zero • Undamped Frequency • Measure Of Closed Loop Bandwidth • Closed Loop Bandwidth Increases By Square Root Of One Plus • "DC" Loop Gain, In Contrast To Increase By One Plus "DC" Loop • Gain Predicted By Dominant Pole Analysis 70

  8. n Step Response Example Of Damping Factor Effect Transmission Zero Assumed To Lie At Infinitely Large Frequency t 71

  9.   –1 –1 –1  ) = – tan – tan – tan z p p o 1 2   T(0) p u 1  u k k – 1 p o z = k  p = k  o o u 2 p u k + k p o 1 + k T(0) –1 –1  tan tan m T(0) – k k k o p Phase Margin ( v • Unity Loop Gain Frequency • Assumes Frequencies Of Zero And Second Pole Are Larger Than • Substitutions: • Phase Margin • Difference Between Actual Loop Gain Phase Angle And –180; • A Safety Margin For Closed Loop Stability • Approximate Phase Margin: • Since Can Be Negative, k Can Be A Negative Number • Result Is Meaningful Only For  k   (k)  > 1 72

  10. Phase Margin Characteristic Phase Margin (deg.) 120 100 T(0) = 1 80 T(0) =5 60 40 20 T(0) = 100 0 k -1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 2.2 2.4 2.6 2.8 3 -20 -40 -60 73

  11. s p = k  A (0) 1 –  T(0) p z = k  2 p u z cl u 1 o o u o A (s) = k k – 1 cl 2 p o 2  s cl 1 + s + k + k  p o 2  ncl ncl p p 1 2 1  = + ol 2 p p 1 2  p p  =  1 + T (0) nol 1 2 ncl nol k 1 1 1 p  = k T(0) 1 – + 1 1 – cl p k 2 k 2 k T (0) 1 + T (0) o o p k 1 + T (0) p  =   k ncl u u p T(0) 1 + k T(0) –1 –1  tan tan m T(0) – k  Circuit Response Parameters k  = l Closed Loop Damping Factor: l Closed Loop Undamped Frequency: l Phase Margin:     (k) 74

  12. /  > 1 2 cl k 1 1 p   1 –   k > 3.125 cl p 2 k 2 o k k – 1 p o k =  k = 1.8 k + k p o 1 + k T(0) –1 f  tan  f  63.2 8 m m T(0) – k • Given: • Desire Maximally Flat Closed Loop Response, Which • Implies • Computations: • Requisite Phase Margin: • In Practical Electronics, Phase Margins In The 60s Of Degrees • Are Usually Mandated, Which Requires That The Non-Dominant • Pole Frequency Be 2.5 -To- 4 Times Larger Than The Unity • Gain Frequency Closed Loop Example Calculation 75

  13. s A (0) 1 – z cl o A (s) = cl 2 2  s cl 1 + s +  2  ncl ncl 2   1 –  dcl ncl cl z k o o M  k ncl p x  ncl y (t) y n A (0) cl y (t)  1 – A (0) cl s 1 – z Y (s) o Y = n A (0) 2 2  s cl cl s 1 + s +  2  ncl ncl Closed Loop Step Response: Problem Formulation • Problem Setup: • (Damped Frequency Of Oscillation) • Normalized Variables: • (Normalized Time Variable) • (Output Normalized To Steady–State Response) • (Error Between Steady State And Actual • Output Responses)     t (t)  (t)  (s)  76

  14. s 1 – z o Y (s) = n 2 2  s cl s 1 + s +  2  ncl ncl  y (t) = 1 – n 1/2 2 1 + 2 M  + M  – x 2  cl e (x) = Sin x 1 –  +  cl cl 2 2 M 1 –  cl x  ncl z k o o M  k ncl p 2 M 1 –  –1 cl = tan 1 + M  cl  cl z +   > 0 o cl ncl Closed Loop Step Response: Solution (t) • Solution: • Assumptions: • (Underdamped Closed Loop Response) • (Satisfied For Right Half Plane Zero)  t    < 1 77

  15. Closed Loop Step Response Example #1 M = 1 78

  16. Closed Loop Step Response Example #2 M = 5 79

  17. 1/2 2 1 + 2 M  + M  – x 2  cl e (x) = Sin x 1 –  +  cl cl 2 2 M 1 –  cl  y (x) = 1 – n x m m   m m Closed Loop Settling Time (x) • Observations • Magnitude Of Error Term Decreases Monotonically With x • Maxima Of Error Determined By Setting Derivative Of Error • Term With Respect To x To Zero • Maxima Are Periodic With Period  • First Maximum Of Error Establishes Undershoot Point • Determine Second Maximum And Constrain To Desired Minimal Error • Procedure • Let Be The Normalized Time Corresponding To Second • Error Maximum • Let Be The Magnitude Of Error Corresponding To • If Is The Desired Settling Error, Represents The Settling Time • Of the Circuit x 80

  18. 1/2 2 1 + 2 M  + M  – x 2  cl e (x) = Sin x 1 –  +  cl cl 2 2 M 1 –  cl  y (x) = 1 – n 2 1 –  1 –1 cl x =  + tan m  + M 2 1 –  cl cl 2 1 + 2 M  + M  – x  cl e = cl m m M  2  x m 4 – k 2 1 –  p cl k p  exp –  m 4 – k p Closed Loop Settling Time Results (x) • Results: • For Large M (Far Right Half Plane Zero):    81

  19. k p  exp –  k p m 4 – k p 2  x =  t  2  m ncl m ncl 4 – k p   k  2  ncl u p u –1 f tan ( k m p Closed Loop Settling Time Example • Requirements • Settling To Within One Percent In 1 nSEC • Assume Zero Is In Far Right Half Plane (Reasonable • Approximation For Common Gate And Compensated Source • Follower; First Order Approximation For Common Source) • Assume Very Large "DC" Loop Gain • Computations • Second Pole Must Be At Least 2.7 Times Larger Than • Unity Gain Frequency • Required Phase Margin:   0.01  > 2.73 ;  = 5.575   (887.2 MHz) ;    (537 MHz)   ) = 69.9 82

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