Download Presentation
## CHI SQUARE

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -

**CHI SQUARE**GOODNESS OF FIT**RESEARCH QUESTION**• Is the proportion of number of students occupying the Emotional Intelligence level for moderate and high is equal?**HYPOTHESIS**• Null hypothesis : n1 = n2 The number of students for both medium and high level of Emtional Intelligence is equal, where:n1 = the number students in the range of moderate Emotional Intelligence (EI)n2 = the number students in the range of high Emotional Intelligence (EI) • Alternative hypothesis: n1 ≠ n2The number of students for both moderate and high level of Emotional Intelligence (EI) is not the same.**TEST OF NORMALITIES BASED ON KOLMOGOROV-SMIRNOV**• Since our subjects is more than 100, so we use Kolmogorov-Smirnov Normality Test. • From the table, for both moderate and high EI, the Sig. is 0.200 which is more than the α = 0.05. Therefore, the test is not statistically significant.**CHI-SQUARE TEST**The case summary processing indicates that the data from 133 cases were included in these analyseswith 106 for moderate EI and 27 for high EI**GOODNESS OF FIT CROSSTABULATION**• From the table, we can see that the observed N is unequal proportion for moderate and high EI**TEST STATISTIC**• Asymp. Sig is less than 0.01 • So, Asymp. Sig is < 0.05 when compared to (0.05), therefore we say that the observed frequencies is significantly different from the expected frequencies. • Note below informs us that 0% of categories had expected frequencies below five, and as it is less than 4454.5, therefore the expected frequencies assumption has not been violated.**CHI-SQUARE TEST FOR GOODNESS OF FIT:EFFECT SIZE**• Effect size • w = √ X² N • w = √ 4150.697² 133 = 31.208 (this is a mediumeffect)**CONCLUSION**• The CHI-SQUARE Goodness of Fit test (with α = 0.05) was used to evaluate whether the proportion of students with moderate EI and high EI of the biomedical students is equal or not. • The chi-square test was not statistically significant, p = 0.200. • Therefore, we do not accept Null hypothesis. • We can conclude that the proportion of students with moderate EI and high EI is not equal and this is proven by the test statistic with • Moderate EI = 7495 • High EI = 1414 • This show the unequal proportion of the number of students.