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Tai Wai Station. Kowloon Tong Station. Ch.1 Distance ( 距離 ) & Displacement ( 位移 ). displacement 4 km to the north. distance 4.4 km. Class Exercise 1.1. Distance travelled = ?. Class Exercise 1.1. Distance travelled = 12 + 98 + 70 = 180 m. Displacement ( 位移 ) = change in position
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Tai Wai Station Kowloon Tong Station Ch.1 Distance (距離) & Displacement (位移) displacement 4 km to the north distance 4.4 km
Class Exercise 1.1 Distance travelled = ?
Class Exercise 1.1 Distance travelled = 12 + 98 + 70 = 180 m
Displacement(位移) = change in position The change in position is a straight line joining the start position (起點) and the end position (終點). Magnitude (量值): Length of the straight line joining the start position and the end position. Direction (方向): Direction of the straight line from the start position to the end position.
North (北) West (西) East (東) South (南)
N 40° Direction = ?
N 50 ° 40° E Direction = 50°
N 60° Direction = ?
N 90° + 60° = 150° E 60° S Direction = 150°
N 40° Direction = ?
N 90° + 90° + 50° = 230 ° W 40° 50° S Direction = 230 °
N 40° Direction = ?
N 40° W 270° + 50° = 320° Direction = 320°
Class Exercise 1.2 Magnitude of displacement = ? Direction of displacement = ?
Class Exercise 1.2 Magnitude of displacement = 128 m Direction of displacement = 180º + 40° =220°
Class Exercise 1.3 (a) & (b) 6 m 6 m East (90°) East
Class Exercise 1.3 (c) & (d) 6 m 6 m East East
Note: If the starting position and the end position are the same, the displacement is the same.
Class Exercise 1.4 (a) You walk from LPSMC to the Entrance C of the Tsuen Wan MTR station. Find the magnitude and direction of your displacement.
Class Exercise 1.4 (a) 6.2 cm 3.2 cm Magnitude = ? Direction = ?
Class Exercise 1.4 (a) 6.2 cm 78° 3.2 cm Magnitude = (6.2 ÷ 3.2 ) × 100 = 194 m Direction = 180° + 77° = 257°(S 77 W)
Class Exercise 1.4 (b) You meet your friend, Tommy, at Entrance C. He is going to the YMCA in Luk Yeung Sun Chuen. What is his displacement from Entrance C to the YMCA?
Class Exercise 1.4 (b) 3.7 cm Magnitude = ? Direction = ? 3.2 cm
Class Exercise 1.4 (b) Magnitude = (3.7 ÷ 3.2 ) × 100 = 116 m Direction = 50° (N 50 E) 3.7 cm 50° 3.2 cm
Class Exercise 1.5 Mr. Chan walks 3 m from A to the East. He turns 90 and walks 6 m to the South. Finally he walks a further distance of 9 m to the West. (a) In the space below, draw arrows to represent these displacements. (Use 1 cm to represent 1 m.)
Class Exercise 1.5 (b) (b) direction and magnitude of the total displacement = ?
Class Exercise 1.5 (b) 45° magnitude of the total displacement = 8.5 m direction of the total displacement = 180° + 45° = 225°
Class Exercise 1.6 (a) East 12 m 33
Class Exercise 1.6 (a) East 12 m East 6 m 34
Class Exercise 1.6 (a) East 12 m East 6 m 18 m East
S Class Exercise 1.6 (b) 37
S Class Exercise 1.6 (b) -10 m or 10 m (West)
S Class Exercise 1.6 (b) -10 m or 10 m (West) 8 m (East) 39
S Class Exercise 1.6 (b) -10 m or 10 m (West) 8 m (East) 28 m 40
Class Exercise 1.7 distance = 3 + 4 = 7 m
Class Exercise 1.7 53° magnitude = m direction = 90° + 37° = 127° (S 53 E)
Class Exercise 1.7 62° P
Class Exercise 1.7 62° P -4.0 m or 4.0 m (West) 3.0 m (South)
Homework: Assignment Book 1. Chapter 1: Distance & Displacement Q.1 – Q.6 (p.1-5) 2. Deadline: 2011 - - ____