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# Do Now - PowerPoint PPT Presentation

Do Now. Find the GCF of each set of numbers. 34, 51 36, 72 21, 42, 56. Finding the GCF. For variables that ALL terms have in common, the GCF is always the smallest exponent that you have of each variable. 1) x 3 , x 5 2) z 4 , z 2. 3) 12a 5 , 18a 2 4) 18xy, 36y 2

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## PowerPoint Slideshow about ' Do Now' - calista-osborne

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Presentation Transcript

Find the GCF of each set of numbers.

• 34, 51

• 36, 72

• 21, 42, 56

Finding the GCF

For variables that ALL terms have in common, the GCF is always the smallest exponent that you have of each variable.

1) x3, x5

2) z4, z2

3) 12a5, 18a2

4) 18xy, 36y2

5) 36x2y, 54 xy2z

6) 12a5c7, 24a3b2c, 18a10b4c3

Factoring with a GCF is basically the opposite of using the distributive property.

4a (3a + 4)

12a2

+ 16a

and end up with: 4a (3a + 4)

Steps:

• Find the GCF of ALL of the terms. The GCF will be on the outside of the ( ).

• Divide each original term by the GCF to get each term inside the ( ).

* You always have to have the same number of terms inside the ( ) as you started with.

• FACTOR 25a2 + 15a.

Find the GCF and divide each term

25a2 + 15a = 5a ( ___ + ___ )

18x2 - 12x3 = 6x2 ( ___ – ___ )

2) Factor 18x2 – 12x3.

3) Factor 28a2b + 56abc2.

28a2b + 56abc2 = 28ab ( __ + ___ )

4) Factor 28a2 + 21b – 35b2c2

28a2 + 21b - 35b2c2 = 7 ( ___ + ___ – ____ )

3x2y – 27x5y3z + 18x3y7z2

Factor 16xy2 - 24y2z + 40y2

• 2y2(8x – 12z + 20)

• 4y2(4x – 6z + 10)

• 8y2(2x - 3z + 5)

• 8xy2z(2 – 3 + 5)

Factor 20x2 - 24xy

• x(20 – 24y)

• 2x(10x – 12y)

• 4(5x2 – 6xy)

• 4x(5x – 6y)

Chapter 9 Packet

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