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Drill:. List five factors & explain how each affect reaction rates. Review Drill & Check HW. CHM II HW. Review PP-19 & 20 Complete the attached worksheet & turn it in tomorrow Lab Thursday. Are there any questions on previous material?. Chemical Equilibria. Equilibrium.
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Drill: • List five factors & explain how each affect reaction rates
CHM II HW • Review PP-19 & 20 • Complete the attached worksheet & turn it in tomorrow • Lab Thursday
Equilibrium • The point at which the rate of a forward reaction = the rate of its reverse reaction
Equilibrium • The concentration of all reactants & products become constant at equilibrium
Equilibrium • Because concentrations become constant, equilibrium is sometimes called steady state
Equilibrium • Reactions do not stop at equilibrium, forward & reverse reaction rates become equal
Reaction • aA(aq)+ bB(aq) pP(aq)+ qQ(aq) • Ratef = kf[A]a[B]b • Rater = kr[P]p[Q]q • At equilibrium, Ratef = Rater • kf[A]a[B]b = kr[P]p[Q]q
At equilibrium, Ratef = Rater kf[A]a[B]b = kr[P]p[Q]q kf /kr = ([P]p[Q]q)/ ( [A]a[B]b) kf /kr = Kc = Keq in terms of concentration Kc = ([P]p[Q]q)/ ( [A]a[B]b)
All Aqueous aA + bB pP+ qQ
Equilibrium Expression ( Products)p (Reactants)r Keq=
Drill: Solve Rate Expr: X + Y M + N fast 3M + N 2G fast 2N K fast 2G + K Prod. slow
Drill: Solve Rate Expr: X + Y M + N fast 3M + N 2G fast 2N K fast 2G + K Prod. slow
Drill: Solve Rate Expr: X + Y M + N fast 3M + N 2G fast 2N K fast 2G + K Prod. slow
Drill: Solve Rate Expr: X + Y M + N fast 3M + N 2G fast 2N K fast 2G + K Prod. slow
Drill: Solve Rate Expr: 3X + 3Y 3M + 3N 3M + N 2G fast 2N K fast 2G + K Prod. slow
Solve Rate Law A + B C + D fast 4 C + A 2G fast 2 K 4D + B fast G + K 2 Q + 2 W fast Q + W Prod. slow
Drill: Solve Rate Law A + B C + D fast 4 C + A 2G fast 2 K 4D + B fast G + K 2 Q + 2 W fast Q + W Prod. slow
Drill: Solve Rate Law A + B C + D fast 4 C + A 2G fast 4 D + B 2K fast G + K 2 Q + 2 W fast Q + W Prod. slow
Drill: Solve Rate Law A + B C + D fast 4 C + A 2G fast 4 D + B 2K fast G/2 + K/2 Q + W fast Q + W Prod. slow
Reverse Rxn 3Divide Rxn 4 by 2 & cancelDivide Rxns 2 & 3 by 4 & cancel
Drill: Solve Rate Law A + B C + D fast C + A/4 G/2 fast D + B/4 K/2 fast G/2 + K/2 Q + W fast Q + W Prod. slow
Reverse Rxn 3Divide Rxn 4 by 2 & cancelDivide Rxns 2 & 3 by 4 & cancelAdd the rxns
CHM II HW • Review PP-19 & 20 • Remember M. S.
Equilibrium Applications • When K >1, [P] > [R] • When K <1, [P] < [R]
Equilibrium Calculations • Kp = Kc(RT)Dngas
Equilibrium Expression • Reactants or products not in the same phase are not included in the equilibrium expression
Equilibrium Expression aA(s)+ bB(aq) cC(aq)+ dD(aq) [C]c [D]d [B]b Keq=
Reaction Mechanism • When one of the intermediates anywhere in a reaction mechanism is altered, all intermediates are affected
Reaction Mechanism • 1) A + B <---> C + D • 2) C + D <---> E + K • 3) E + K <---> H + M • 4) H + M <----> P
Lab Results • % 100 80 60 40 • RT 5.21 8.42 11.9 21.7 • WR 2.75 4.23 7.96 11.2
aA(aq) + bB(aq) pP(aq) + qQ(aq) ReactionQuotient where [A], [B], [P], and [Q] are molarities at any time. Q = K only at equilibrium.
Drill: NH3 H2 + N2 At a certain temperature at equilibrium Pammonia = 4.0 Atm, Phydrogen = 2.0 Atm, & Pnitrogen = 5.0 Atm. Calculate Keq:
CHM II HW • Review PP 19 & 20 • Complete the attached assignment & turn it in tomorrow
aA(aq) + bB(aq) pP(aq) + qQ(aq) ReactionQuotient where [A], [B], [P], and [Q] are molarities at any time. Q = K only at equilibrium.
Equilibrium Applications • When K > Q, the reaction goes forward • When K < Q, the reaction goes in reverse