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Lecture 5: Introduction to Physics PHY101. Chapter 2: Distance and Displacement, Speed and Velocity (2.1,2.2) Acceleration (2.3) Equations of Kinematics for Constant Acceleration (2.4). Displacement and Distance.

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lecture 5 introduction to physics phy101
Lecture 5: Introduction to Physics PHY101

Chapter 2:

  • Distance and Displacement, Speed and Velocity (2.1,2.2)
  • Acceleration (2.3)
  • Equations of Kinematics for Constant

Acceleration (2.4)

displacement and distance
Displacement and Distance
  • Displacement is the vector that points from a body’s initial position, x0, to its final position, x. The length of the displacement vector is equal to the shortest distance between the two positions.

x = x –x0

Note:

The length of xis (in general) not the same as distance

traveled !

average speed and velocity
Average Speed and Velocity
  • Average speed is a measure of how fast an object moves on average:

average speed = distance/elapsed time

Average speed does not take into account the direction of

motion from the initial and final position.

average speed and velocity4
Average Speed and Velocity
  • Average velocity describes how the displacement of an object changes over time:

average velocity = displacement/elapsed time

vav = (x-x0) / (t-t0) = x/ t

Average velocity also takes into account the direction of

motion.

Note:

The magnitude of vav is (in general) not the same as the

average speed !

instantaneous velocity and speed
Instantaneous Velocity and Speed
  • Average velocity and speed do not convey any information about how fast the object moves at a specific point in time.
  • The velocity at an instant can be obtained from

the average velocity by considering smaller and smaller time intervals, i.e.

Instantaneous velocity:

v = lim  t-> 0x/ t

Instantaneous speed is the magnitude of v.

concept question
Concept Question
  • If the average velocity of a car during a trip along a straight road is positive, is it possible for the instantaneous velocity at some time during the trip to be negative?

1 - Yes

2 - No

correct

If the driver has to put the car in reverse and back up some time

during the trip, then the car has a negative velocity. However,

since the car travels a distance from home in a certain amount of

time, the average velocity will be positive.

acceleration
Acceleration
  • Average acceleration describes how the velocity

of an object moving from the initial position to

the final position changes on average over time:

aav = (v-v0) / (t-t0) = v/ t

  • The acceleration at an instant can be obtained from

the average acceleration by considering smaller and smaller time intervals, i.e.

Instantaneous acceleration:

a = lim  t-> 0v/ t

concept question8
Concept Question
  • If the velocity of some object is not zero, can its acceleration ever be zero ?

1 - Yes

2 - No

correct

If the object is moving at a constant velocity,

then the acceleration is zero.

concept question9
Concept Question
  • Is it possible for an object to have a positive velocity at the same time as it has a negative acceleration?

1 - Yes

2 – No

correct

An object, like a car, can be moving forward

giving it a positive velocity,

but then brake, causing deccelaration which is

negative.

kinematics in one dimension constant acceleration
Kinematics in One DimensionConstant Acceleration
  • Simplifications:

In one dimension all vectors in the previous equations

can be replaced by their scalar component along one axis.

For motion with constant acceleration, average and

instantaneous acceleration are equal.

For motion with constant acceleration, the rate with which

velocity changes is constant, i.e. does not change over time.

The average velocity is then simply given as

vav = (v0 +v)/2

kinematics in one dimension constant acceleration11
Kinematics in One DimensionConstant Acceleration

Consider an object which moves from the initial position x0, at time t0

with velocity v0, with constant acceleration along a straight line.

How does displacement and velocity of this object change with time ?

a = (v-v0) / (t-t0) => v(t) = v0 + a (t-t0) (1)

vav = (x-x0) / (t-t0) = (v+v0)/2 => x(t) = x0 + (t-t0) (v+v0)/2 (2)

Use Eq. (1) to replace v in Eq.(2):

x(t) = x0 + (t-t0) v0 + a/2 (t-t0) 2 (3)

Use Eq. (1) to replace (t-t0) in Eq.(2):

v2 = v02 + 2 a (x-x0 ) (4)

summary of concepts
Summary of Concepts
  • kinematics: A description of motion
  • position: your coordinates
  • displacement: x = change of position
  • velocity: rate of change of position
    • average : x/t
    • instantaneous: slope of x vs. t
  • acceleration: rate of change of velocity
    • average: v/t
    • instantaneous: slope of v vs. t