Draw the resonance structure indicated by the arrows. 1). 2). 3). Label each atom with the correct hybridization. 4). sp 3. sp 3. sp 3. sp 3. sp 3. sp 3. 5). sp 3. sp 2. sp 2. sp 3. sp 2. 6). sp 2. sp. sp. sp 3. 7) Draw H 2 NCH 2 + in its second best resonance structure.
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Label each atom with the correct hybridization.
8) Draw the best Lewis structure for CH3CHO, a neutral molecule
10) Draw the Lewis structure for N2H2, a neutral molecule.
11) Draw in the electron flow arrows in on the left hand structure that lead to the resonance structure on the right.
12) In the empty box, draw the best resonance structure of the left-hand compound, and draw one or more electron-flow arrows on the preexisting structure that lead to the new structure.
Calculate the formal charge of nitrogen in each of the following compounds.
FC = 5 – (4 + (1/2(4))) = -1
FC = 5 – (2 + (1/2(6))) = 0
FC = 5 – (0 + (1/2(8))) = +1
Draw all possible isomers of C2H4O.
Neither, different formulas
Isomers, same formula but different arrangement of atoms.
Draw a resonance structure of each, and identify which is the major contributor.
Draw all possible resonance structures of the compound below and it’s resonance hybrid.
A is the weakest bond due to it being composed of a sp3 and sp2 hybridized orbital, thus having the least amount of S character
B is the weakest, b/c bond strength increases across a row in the periodic table and N is to the left of O.
HBr, HCl or HF
HF, b/c it is the weakest acid.
Identify the most acidic hydrogen.
C is the most acidic hydrogen b/c it’s bonded to an sp hybridized carbon.
Draw the products of each reaction and label the starting materials as a Lewis acid and base.
2) Complete the following acid-base reaction. Draw only the organic products.
4) Choose the strongest acid.
Both Cl and Br are further right than S. And Br is further down than Cl. So most acidic.
Both O and S are further right than P. And S is further down than O. So most acidic.
6) Choose the weakest acid.
C is further left than O and S so weakest acid.
7) The following compound has two stereoisomers. One has a dipole of 0 D, and the other has a dipole moment of 2.95 D. Draw the structure of the stereoisomer with dipole moment of 2.95 D.
We know Si is more acidic than C because it is below C in the same column. Although Si and O can’t be compared directly, O is much more acidic.
Acidity is based on the electron withdrawing effect of the four different substituents. O is the most electronegative, furthest up and to the right, and thus gives the most acidic compd. And Cl is more electronegative than Br b/c electronegativity increases up the column.
10) Draw the electron-flow arrows that lead from starting materials to products in this acid–base reaction.
2) Draw an ester.
RCOOR or RCO2R
4) Draw 1,1-dimethylcyclohexane.
6) Draw trans-1,3-dibromocyclobutane.
8) Draw sec-butylcycloheptane
10) Draw the structural formula of an alkane that has eight carbons and only primary hydrogens.
Primary hydrogens are attached to carbons attached to only one other carbon.
11) Draw the conformation favored by 1,2-dichloroethane at equilibrium in the liquid phase by following this procedure.
The gauche conformer is favored in the liquid phase due to a polar effect. However, for this class I would accept the anit conformer as your answer, which would be correct if in the gas form.
12) Draw cis-3-ethyl-1-isopropylcyclohexane in its lowest energy conformation
13) Draw trans-1-bromo-3-methylcyclohexane in its lowest energy conformation
2) What is the formal charge of the following compound?
FC = 4 – (2 + (1/2)(6)) = -1
5) Which of the following compounds has the largest net dipole? Draw the contributing dipoles of the compound you choose.
CO2 H2O CHCl3
6) Draw the product of the following reaction. (Label the Lewis Acid and Base)
7) Which molecule plays the role of acid?
HNO3 + H2SO4 → HSO4– + H2NO3+
8) Using pKa values from the table, determine if the following reaction will occur.
pKa of the conjugate acid is larger than that of the acid so the reaction favors the products.
LiOH LiF LiCH3
LiCH3 is the strongest base because the acid it forms when the anion is protonated is very weak.
10) What intermolecular forces does the following molecule exhibit?
It possesses Van der Waals and dipole-dipole interactions.
CBr3CH3 CH3OCH3 CH3NH2
CH3NH2 has the highest boiling point because it possesses the same intermolecular forces as the first two molecules, but also has hydrogen bonding capabilities.
12) Label the electrophile and nucleophile. Then if the reaction occurs, draw the products.
14) Which of the following has the highest melting point? Why?
c) 2,2',3,3'-tetramethylbutane has the highest metlign point due to its high symmetry giving it the ability to pack close together in the crystal lattice.
Draw the most stable form of trans-1-bromo-3-ethylcyclohexane.
Using Newman projections, draw all the staggered conformations of 1-chloropropane, label the anti and gauche forms.