Loading in 5 sec....

6.3 Two-Sample Inference for MeansPowerPoint Presentation

6.3 Two-Sample Inference for Means

- 85 Views
- Uploaded on
- Presentation posted in: General

6.3 Two-Sample Inference for Means

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

6.3 Two-Sample Inference for Means

November 17, 2003

- Matched Pairs Design
- experimental plan where the experimental units are divided into halves and two treatments are randomly assigned to the halves

- Attempting to determine if there is a significant difference between the mean responses of the treatments

- Obtain the difference between responses for each experimental unit
- Analyze the differences using a one-sample approach
- If a large sample is obtained, use critical values from the Standard Normal distribution (z)
- Otherwise, use critical values from the corresponding t distribution

- Students worked with a company on the monitoring of the operation of an end-cut router in the manufacture of a wood product. They measured the critical dimensions of a number of pieces of a type as they came off the router. Both a leading-edge and a trailing-edge measurement were made on each piece. Both were to have a target value of .172 in.

- Is there a significant difference between the measurements at α =.01?
- Ho: µ = 0
- Ha: µ ≠ 0

- The goal of this type of inference is to compare the mean response of two variables (or treatments) when the data are not paired or matched
- A key assumption that will be made is that the separate samples used to collect information concerning the two variables are independent
- One sample does not influence the other sample in any way

- Furthermore, one must assume that both sampled populations are normally distributed

- The quantity of interest is a linear combination of population means, namely µ1 - µ2
- The above quantity will be estimated by
- As a result, various quantities of the sampling distribution of the difference, under the assumption of equality between the means, need to be developed
- Ho: µ1 - µ2 = #
- Ha: µ1 - µ2 ≠ #

- A company research effort involved finding a workable geometry for molded pieces of a solid. A comparison was made between the weight of molded pieces and the weight of irregularly shaped pieces that could be poured into the same container. A series of 30 attempts to pack both the molded and the irregular pieces of the solid were compared. Is there enough evidence to suggest that the irregular pieces produced higher weights?

1 = molded

n1 = 30

s1= 9.31

= 164.65

2=irregular

n2 = 30

s2= 8.51

= 179.65

- If at least one sample size is small, then use critical values from a t distribution for constructing confidence intervals and performing hypothesis tests with degrees of freedom obtained by Satterthwaite’s Approximation

- The data shown gives spring lifetimes under two different levels of stress (900 and 950 N/mm2). Do the data give evidence of a significant difference at α = .05?

Descriptive Statistics: 950, 900

Variable N Mean Median TrMean StDev SE Mean

950 10 168.3 166.5 167.6 33.1 10.5

900 10 215.1 216.0 211.5 42.9 13.6

- Page 385: #3, #4