1 / 20

Open Channel

The Islamic University of Gaza Faculty of Engineering Civil Engineering Department Hydraulics - ECIV 3322. Open Channel. Chapter 6. Example 1. Open channel of width = 3m as shown, bed slope = 1:5000, d=1.5m find the flow rate using Manning equation, n=0.025. Example 2.

noah-mcleod
Download Presentation

Open Channel

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. The Islamic University of GazaFaculty of EngineeringCivil Engineering DepartmentHydraulics - ECIV 3322 Open Channel Chapter 6

  2. Example 1 Open channel of width = 3m as shown, bed slope = 1:5000, d=1.5m find the flow rate using Manning equation, n=0.025.

  3. Example 2 Open channel as shown, bed slope = 69:1584, find the flow rate using Chezy equation, C=35.

  4. Example 3 Circular open channel as shown d=1.68m, bed slope = 1:5000, find the Max. flow rate & the Max. velocity using Chezy equation, C=70. Max. flow rate

  5. Max. Velocity

  6. Example 4 Trapezoidal open channel as shown Q=10m3/s, velocity =1.5m/s, for most economic section. find wetted parameter, and the bed slope n=0.014.

  7. To calculate bed Slope

  8. Example 5 Determine the critical depth if the flow is 1.33m3/s. the channel width is 2.4m

  9. Example 6 Rectangular channel , Q=25m3/s, bed slope =0.006, determine the channel width with critical flow using manning n=0.016

  10. Example 7 A 3-m wide rectangular channel carries 15 m3/s of water at a 0.7 m depth before entering a jump. Compute the downstrem water depth and the critical depth

  11. d2 d1=dn Example 8 dn = Depth can calculated from manning equation

  12. d2 d1=dn a) b)

  13. d2 d1=dn c)

  14. Example 9 A trapezoidal channel with a bottom width of 5m, side slope of 1H: 1V, and a Manning n of 0.013 carries a discharge of 50m3/s at a slope of 0.0004. Compute by the direct step method the backwater profile created by a dam that backs up the water to a depth of 6 m immediately behind the dam. The upstream end of the profile is assumed at a depth equal to 1% greater than the normal depth.

  15. determine normal depth, Yn By trial and error, Yn = 2.87 m

  16. determine critical depth, Yc By trial and error, Yc = 1.90 m Control depth = 1.01*2.87 =2.90m

More Related