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Chapter 5

Chapter 5. Relational Algebra and Relational Calculus. Introduction. Relational algebra & relational calculus formal languages associated with the relational model Relational algebra (high-level) procedural language Relational calculus non-procedural language.

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Chapter 5

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  1. Chapter 5 Relational Algebra and Relational Calculus

  2. Introduction • Relational algebra & relational calculus • formal languages associated with the relational model • Relational algebra • (high-level) procedural language • Relational calculus • non-procedural language. • A language that produces a relation that can be derived using relational calculus is relationally complete

  3. Relational Algebra • Relational algebra operations work on one or more relations to define another relation without changing original relations • Both operands and results are relations • Output from one operation can be input to another • Allows nested expressions • Closure property

  4. Relational Algebra • Five basic operations • Selection, Projection, Cartesian product, Union, and Set Difference • Perform most required data retrieval operations • Additional operators • Join, Intersection, and Division • Can be expressed in terms of 5 basic operations

  5. Selection (or Restriction) • predicate (R) • Works on single relation R • Defines relation that contains only tuples (rows) of R that satisfy specified condition (predicate)

  6. Example - Selection (or Restriction) • List all staff with a salary greater than £10,000. salary > 10000 (Staff)

  7. Projection • col1, . . . , coln(R) • Works on a single relation R • Defines relation that contains vertical subset of R • Extracts values of specified attributes • Eliminates duplicates

  8. Example - Projection • Produce a list of salaries for all staff, showing only staffNo, fName, lName, and salary details. staffNo, fName, lName, salary(Staff)

  9. Union • R  S • Defines relation that contains all tuples of R, or S, or both R and S • Duplicate tuples eliminated • R and S must be union-compatible • For relations R and S with I and J tuples, respectively • Union is concatenation of R & S into one relation with maximum of (I + J) tuples

  10. Example - Union • List all cities where there is either a branch office or a property for rent. city(Branch) city(PropertyForRent)

  11. Set Difference • R – S • Defines relation consisting of tuples in relation R, but not in S • R and S must be union-compatible

  12. Example - Set Difference • List all cities where there is a branch office but no properties for rent. city(Branch) – city(PropertyForRent)

  13. Intersection • R  S • Defines relation consisting of set of all tuples in both R and S • R and S must be union-compatible • Expressed using basic operations: R  S = R – (R – S)

  14. Example - Intersection • List all cities where there is both a branch office and at least one property for rent. city(Branch) city(PropertyForRent)

  15. Cartesian product • R X S • Binary operation • Defines relation that is concatenation of every tuple of relation R with every tuple of relation S

  16. Example - Cartesian product • List the names and comments of all clients who have viewed a property for rent. (clientNo, fName, lName(Client)) X (clientNo, propertyNo, comment (Viewing))

  17. Example - Cartesian product and Selection • Use selection operation to extract those tuples where Client.clientNo = Viewing.clientNo. sClient.clientNo = Viewing.clientNo((ÕclientNo,fName,lName(Client))  (ÕclientNo,propertyNo,comment(Viewing))) • Cartesian product and Selection can be reduced to single operation • Join

  18. Relational Algebra Operations

  19. Join Operations • Join - derivative of Cartesian product • Equivalent to performing Selection, using join predicate as selection formula, over Cartesian product of two operand relations • One of most difficult operations to implement efficiently in an RDBMS • One reason RDBMSs have intrinsic performance problems

  20. Join Operations • Various forms of join operation • Theta join • Equijoin (a particular type of Theta join) • Natural join • Outer join • Semijoin

  21. Theta join (-join) • R FS • Defines relation that contains tuples satisfying predicate F from Cartesian product of R and S • Predicate F is of the form R.ai S.bi where  may be comparison operators (<, , >, , =, )

  22. Theta join (-join) • Can rewrite Theta join using basic Selection and Cartesian product operations R FS = F(R  S) • Degree of a Theta join • Sum of degrees of operand relations R and S • If predicate F contains only equality (=) • Equijoin

  23. Example - Equijoin • List the names and comments of all clients who have viewed a property for rent. (clientNo, fName, lName(Client)) Client.clientNo = Viewing.clientNo (clientNo, propertyNo, comment(Viewing))

  24. Natural join • R S • Equijoin of relations R and S over all common attributes x • One occurrence of each common attribute eliminated from result

  25. Example - Natural join • List the names and comments of all clients who have viewed a property for rent. (clientNo, fName, lName(Client)) (clientNo, propertyNo, comment(Viewing))

  26. Outer join • Used to display rows in result that do not have matching values in join column • R S • (Left) outer join • Tuples from R that do not have matching values in common columns of S included in result relation

  27. Example - Left Outer join • Produce a status report on property viewings. propertyNo, street, city(PropertyForRent) Viewing

  28. Semijoin • R F S • Defines relation that contains tuples of R that participate in join of R with S • Can rewrite Semijoin using Projection and Join: • R F S = A(R F S)

  29. Example - Semijoin • List complete details of all staff who work at the branch in Glasgow. Staff Staff.branchNo=Branch.branchNo(city=‘Glasgow’(Branch))

  30. Division • R  S • Defines relation over attributes C that consists of set of tuples from R that match combination of every tuple in S • Expressed using basic operations: T1C(R) T2C((S X T1) – R) T  T1 – T2

  31. Example - Division • Identify all clients who have viewed all properties with three rooms. (clientNo, propertyNo(Viewing))  (propertyNo(rooms = 3 (PropertyForRent)))

  32. Relational Algebra Operations

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