Unit 9: Geometry – 6 th Grade

1 / 9

# Unit 9: Geometry – 6 th Grade - PowerPoint PPT Presentation

Unit 9: Geometry – 6 th Grade. Lesson 1: Area and perimeter. Cornell Notes Header. Vocabulary. perimeter – The distance around a figure, measured in linear units i.e. ft., in., m. area – The amount of surface a figure covers, measured in square units. Perimeter of a Rectangle.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'Unit 9: Geometry – 6 th Grade' - timothy-barber

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

### Unit 9: Geometry – 6th Grade

Lesson 1: Area and perimeter

Vocabulary
• perimeter –
• The distance around a figure, measured in linear units i.e. ft., in., m.
• area –
• The amount of surface a figure covers, measured in square units.
Perimeter of a Rectangle
• Perimeter of a Rectangle: P = 2l + 2w
• where l = length w = width
• Ex. A carnival is going to be held in your school’s parking lot. How much rope is needed to enclose the carnival if the parking lot is 200 ft. by 100 ft.?
• 200 ft.
• 100 ft. P = 2l + 2w
• = 2(200) + 2(100)
• = 400 + 200
• = 600 ft.
Area of a Rectangle
• Area of a Rectangle: A = lw
• where l = length w = width
• Ex. What is the area of the school’s parking lot?
• 200 ft.
• 100 ft. A = lw
• = 200(100)
• = 20,000 ft2
Perimeter of a Square
• Perimeter of a Square: P = 4s where s = length of side
• Ex. Find the perimeter of the softball diamond with a side length of 60 ft.
• 60 ft.
• 60 ft. P = 4s
• = 4(60)
• = 240 ft.
Area of a Square
• Area of a Square: A = s2where s = length of side
• Ex. Find the area of the softball diamond.
• 60 ft.
• 60 ft. A = s2
• = (60)2
• = 3,600 ft.2
Solving for an unknown dimension
• Write and solve an equation to find the width of a rectangle. Its area is 195 square meters and its length is 15 meters.
• A = lw
• 195 = 15w (Substitute in known values into the formula.)
• 195= 15w (Divide both sides by 15 to find the value of w.)
• 15 15
• 13 m = w The rectangle is 13 m wide.
The key to solving geometry problems
• Formula
• (write the formula for the perimeter, area, volume, etc. of the shape)
• Fill in
• (fill in the known values)
• Solve
• (solve for the unknown value)