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Satellites

Satellites. Universal Gravitational Constant Force due to Gravity Centripetal Force. F g = mg. Mass of the earth. F g = mg F g = G mm e r 2. Mass of the earth. F g = mg F g = G mm e r 2 mg = G mm e r 2. Mass of the earth. F g = mg

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Satellites

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  1. Satellites Universal Gravitational Constant Force due to Gravity Centripetal Force

  2. Fg = mg Mass of the earth

  3. Fg = mg Fg = Gmme r2 Mass of the earth

  4. Fg = mg Fg = Gmme r2 mg = G mme r2 Mass of the earth

  5. Fg = mg Fg = Gmme r2 mg = G mme r2 g = G me r2 Mass of the earth

  6. Fg = mg Fg = Gmme r2 mg = G mme r2 g = G me r2 gr2 = me G 9.8m/s2(6.38e6m)2=me 6.67e-11N m2/kg2 Mass of the earth

  7. Fg = mg Fg = Gmme r2 mg = G mme r2 g = G me r2 gr2 = me G 9.8m/s2(6.38e6m)2=me 6.67e-11N m2/kg2 Mass of the earth

  8. Fg = mg Fg = Gmme r2 mg = G mme r2 g = G me r2 gr2 = me G 9.8m/s2(6.38e6m)2=me 6.67e-11N m2/kg2 5.98e24= me Mass of the earth

  9. Fc= mv2 r Velocity of the moon with respect to the earth

  10. Fc= mv2 r Fg = Gmme r2 Velocity of the moon with respect to the earth

  11. Fc= mv2 r Fg = Gmme r2 mv2 = G mme r r2 Velocity of the moon with respect to the earth

  12. Fc= mv2 r Fg = Gmme r2 mv2 = G mme r r2 v2 = G me r r2 Velocity of the moon with respect to the earth

  13. Fc= mv2 r Fg = Gmme r2 mv2 = G mme r r2 v2 = G me r r2 v2 = G me r Velocity of the moon with respect to the earth

  14. Fc= mv2 r Fg = Gmme r2 mv2 = G mme r r2 v2 = G me r r2 v2 = G me r v= 6.67e-11(5.98e24kg) 3.84e8m Velocity of the moon with respect to the earth

  15. Fc= mv2 r Fg = Gmme r2 mv2 = G mme r r2 v2 = G me r r2 v2 = G me r v= 6.67e-11(5.98e24kg) 3.84e8m v=1019m/s Velocity of the moon with respect to the earth

  16. Geostationary Satellites

  17. Geostationary Satellities • Rotate around the earth in 24hr

  18. Geostationary Satellities • Rotate around the earth in 24hr • Therefore • t=

  19. Geostationary Satellities • Rotate around the earth in 24hr • Therefore t=24hr(60min)(60sec)=86400s

  20. Geostationary Satellities • Rotate around the earth in 24hr • Therefore t=24hr(60min)(60sec)=86400s • v= 2 P r • t

  21. Geostationary Satellities • Rotate around the earth in 24hr • Therefore t=24hr(60min)(60sec)=86400s • v= 2 P r Fg=Fc • t

  22. v=2 P r t Geostationary Satellite

  23. v=2 P r t v=2 P r 86400s Geostationary Satellite

  24. v=2 P r t v=2 P r 86400s Fc= mv2 r Geostationary Satellite

  25. v=2 P r t v=2 P r 86400s Fc= mv2 r Fg = Gmme r2 Geostationary Satellite

  26. v=2 P r t v=2 P r 86400s Fc= mv2 r Fg = Gmme r2 mv2 = G mme r r2 Geostationary Satellite

  27. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  28. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  29. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  30. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  31. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  32. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  33. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  34. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  35. mv2 = G mme r r2 v2 = G me r r2 v2 = G me r (2 P r )2 = G me (86400)2 r Geostationary Satellite 4P2 r2 = G me (86400)2 r 4P2 r3 = Gme (86400)2 r3 = (86400s)2 G(5.98e24kg) 4P2 G=6.67x10-11Nm2/kg2 r = r =4.22e7m

  36. r3 = (86400s)2 G(5.98e24kg) 4P2 3 r= (86400s)2 (6.67e-11Nm2/kg2)(5.98e24kg) 4P2 Geostationary Satellite

  37. 3 r=(86400s)2 (6.67e11Nm2/kg2 (5.98e24kg) 4P2 r =4.22e7m Geostationary Satellite

  38. Geostationary Satellite velocity with respect to the earth • V= 2pr =2 p ( 4.22e7m) 86400s 86400s v=3069m/s

  39. Geostationary Satellite velocity with respect to the earth • V= 2pr =2 p ( 4.22e7m) 86400s 86400s v=3069m/s

  40. Geostationary Satellite velocity with respect to the earth • V= 2pr =2 p ( 4.22e7m) 86400s 86400s v=3069m/s

  41. Fc= mev2 r Velocity of the earth with respect to the sun

  42. Fc= mev2 r Fg = Gmems r2 Velocity of the earth with respect to the sun

  43. Fc= mev2 r Fg = Gmems r2 mev2 = G m e ms r r2 Velocity of the earth with respect to the sun

  44. Fc= mev2 r Fg = Gmems r2 mev2 = G m e ms r r2 v2 = G ms r r2 Velocity of the earth with respect to the sun

  45. Fc= mev2 r Fg = Gmems r2 mev2 = G m e ms r r2 v2 = G ms r r2 v2 = G ms r Velocity of the earth with respect to the sun

  46. Fc= mev2 r Fg = Gmems r2 mev2 = G m e ms r r2 v2 = G ms r r2 v2 = G ms r v= 6.67e-11(1.99e30kg) 1.51e11m Velocity of the earth with respect to the sun

  47. Fc= mev2 r Fg = Gmems r2 mev2 = G m e ms r r2 v2 = G ms r r2 v2 = G ms r v= 6.67e-11(1.99e30kg) 1.51e11m v=29648 m/s Velocity of the earth with respect to the sun

  48. Fc= mmv2 r Fg = Gmmms r2 mmv2 = G m m ms r r2 v2 = G ms r r2 v2 = G ms r v= 6.67e-11(1.99e30kg) 1.51e11m v=29648 m/s Velocity of the moon with respect to the sun

  49. Fc= mgv2 r Fg = Gmgms r2 mgv2 = G m g ms r r2 v2 = G ms r r2 v2 = G ms r v= 6.67e-11(1.99e30kg) 1.51e11m v=29648 m/s Velocity of the Geostationary Satellite with respect to the sun

  50. Bipolar Star System Two stars 8x1010m apart rotate about a point 4x1010 m from each other in a circular path in 12.6 years. The two stars have the same mass. What is the velocity of the stars? What is the mass of the stars?

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