1 / 26

MAE 242 Dynamics – Section I Dr. Kostas Sierros

MAE 242 Dynamics – Section I Dr. Kostas Sierros. Quiz 1 results. Around 10 people asked for a make up quiz…. DEADLINE TO ASK FOR A MAKE UP QUIZ IS WEDNESDAY 12 SEPTEMBER 2007. Chapter 13: Objectives. State Newton’s laws of motion and gravitational attraction. Define mass and weight

Download Presentation

MAE 242 Dynamics – Section I Dr. Kostas Sierros

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. MAE 242 Dynamics – Section I Dr. Kostas Sierros

  2. Quiz 1 results Around 10 people asked for a make up quiz… DEADLINE TO ASK FOR A MAKE UP QUIZ IS WEDNESDAY 12 SEPTEMBER 2007

  3. Chapter 13: Objectives • State Newton’s laws of motion and gravitational attraction. Define mass and weight • To analyze the accelerated motion of a particle using the equation of motion with different coordinate systems

  4. Example Given:A crate of mass m is pulled by a cable attached to a truck. The coefficient of kinetic friction between the crate and road is mk. Find:Draw the free-body and kinetic diagrams of the crate. Plan:1) Define an inertial coordinate system. 2) Draw the crate’s free-body diagram, showing all external forces applied to the crate in the proper directions. 3) Draw the crate’s kinetic diagram, showing the inertial force vector main the proper direction.

  5. y W= mg The weight force (W) acts through the crate’s center of mass.Tis the tension force in the cable. The normal force(N) is perpendicular to the surface. The friction force (F= uKN) acts in a direction opposite to the motion of the crate. T x 30° F= uKN N ma Example (continued) Solution: 1) An inertial x-y frame can be defined as fixed to the ground. 2) Draw the free-body diagram of the crate: 3) Draw the kinetic diagram of the crate: The crate will be pulled to the right. The acceleration vector can be directed to the right if the truck is speeding up or to the left if it is slowing down.

  6. Problem 1

  7. Lecture 7 • Kinetics of a particle (Chapter 13) • -13.4-13.6

  8. Material covered • Kinetics of a particle • Equations of motion: Rectangular coordinate system • Equations of motion: n-t coordinates • Equations of motion:Cylindrical coordinates • …Next lecture…solving problems, Design Project and starting Ch. 14

  9. Today’s Objectives • Students should be able to: • Apply Newton’s second law to determine forces and accelerations for particles in rectilinear motion • Apply the equation of motion using normal and tangential coordinates • Analyze the kinetics of a particle using cylindrical coordinates

  10. Applications If a man is pushing a 100 lb crate, how large a force F must he exert to start moving the crate? Objects that move in any fluid have a drag force acting on them. This drag force is a function of velocity. If the ship has an initial velocity vo and the magnitude of the opposing drag force at any instant is half the velocity, how long it would take for the ship to come to a stop if its engines stop?

  11. Rectangular coordinates The equation of motion,F= ma,is best used when the problem requires finding forces (especially forces perpendicular to the path), accelerations, velocities or mass.Remember, unbalanced forces cause acceleration! Three scalar equationscan be written from thisvector equation. The equation of motion, being a vector equation, may be expressed in terms of its three components in theCartesian (rectangular) coordinate systemas: F=ma orFxi+ Fyj + Fzk= m(axi + ayj + azk) or, as scalar equations, Fx = max ,Fy = may , and Fz = maz

  12. Procedure of analysis I Free Body Diagram (FBD) Establish your coordinate system and draw the particle’s free body diagram showingonly external forces. These external forces usually include the weight, normal forces, friction forces, and applied forces. Show the ‘ma’vector (sometimes called the inertial force) on a separate diagram Make sure any friction forces act opposite to the direction of motion! If the particle is connected to an elastic spring, a spring force equal to ks should be included on the FBD

  13. Procedure of analysis II Equations of Motion If the forces can be resolved directly from the free-body diagram (often the case in 2-D problems), use thescalar formof the equation of motion. In more complex cases (usually 3-D), a Cartesian vector is written for every force and avector analysisis often best A Cartesian vector formulation of the second law is: F= maor Fxi + Fyj+Fzk= m(axi +ayj +azk) Three scalar equations can be written from this vector equation. You may only need two equations if the motion is in 2-D

  14. Procedure of analysis III Kinematics!!! The second law only provides solutions for forces andaccelerations. Ifvelocityorpositionhave to be found,kinematics equationsare used once the acceleration is found from the equation of motion Any of the tools learned in Chapter 12 may be needed to solve a problem. Make sure you use consistent positive coordinate directions as used in the equation of motion part of the problem!

  15. Problem 2

  16. Problem 3

  17. n-t coordinates (13.5) When a particle moves along acurved path, it may be more convenient to write the equation of motion in terms ofnormal and tangential coordinates The normal direction (n)alwayspoints toward the path’scenter of curvature. In a circle, the center of curvature is the center of the circle The tangential direction (t) istangentto the path, usually set as positive in the direction of motion of the particle

  18. Equations of motion Since the equation of motion is avectorequation, F= ma, it may be written in terms of the n & t coordinates as; Ftut+ Fnun=mat+ man Here Ft & Fn are the sums of the force components acting in the t & n directions, respectively This vector equation will be satisfied provided the individual components on each side of the equation are equal, resulting in the twoscalarequations: Ft = mat and Fn = man Since there is no motion in the binormal (b) direction, we can also write Fb = 0

  19. dy dx [1 + ( )2]3/2 r = d2y dx2 Normal and tangential accelerations Thetangential acceleration, at = dv/dt, represents the time rate ofchange in the magnitude of the velocity. Depending on the direction of Ft, the particle’s speed will either be increasing or decreasing Thenormal acceleration, an = v2/r, represents the time rate ofchange in thedirection of the velocity vector. Remember, analways acts toward the path’s center of curvature. Thus, Fn will always be directed toward the center of the path Recall, if the path of motion is defined as y = f(x), theradius of curvatureat any point can be obtained from:

  20. Solving problems with n-t coordinates •Use n-t coordinates when a particle is moving along a known,curvedpath •Establish then-t coordinate systemon the particle •Drawfree-bodyandkinetic diagramsof the particle. Thenormal acceleration(an) always acts “inward” (the positive n-direction). Thetangential acceleration(at) may act in either the positive or negative t direction • Apply theequations of motionin scalar form and solve •It may be necessary to employ thekinematic relations: at = dv/dt = v dv/ds an = v2/r

  21. Some more theory…

  22. Cylindrical coordinates (13.6) This approach to solving problems has someexternal similarityto the normal & tangential method just studied. However, the path may be more complex or the problem may have other attributes that make it desirable to use cylindrical coordinates Equilibrium equations or “Equations of Motion” in cylindrical coordinates (using r, q , and z coordinates) may be expressed in scalar form as:  Fr = mar = m(r – rq2)  Fq = maq = m(rq – 2rq)  Fz = maz = mz

  23. Cylindrical coordinates (13.6) continued… If the particle is constrained to move only in the r – q plane (i.e., the z coordinate is constant), then only the first two equations are used (as shown below). The coordinate system in such a case becomes a polar coordinate system. In this case, the path is only a function of q.  Fr = mar = m(r – rq2)  Fq = maq = m(rq – 2rq) Note that a fixed coordinate system is used, not a “body-centered” system as used in the n – t approach

  24. Tangential and normal forces If a forcePcauses the particle to move along a path defined by r = f (q ), the normal forceNexerted by the path on the particle is always perpendicular to the path’s tangent. The frictional forceF always acts along the tangent in the opposite direction of motion. The directions ofNandFcan be specified relative to the radial coordinate by using the angle y

  25. r d r q y tan = = dr dr q d Determination of angle ψ The angle y, defined as the angle between the extended radial line and the tangent to the curve, can be required to solve some problems. It can be determined from the following relationship; If y is positive, it is measured counterclockwise from the radial line to the tangent. If it is negative, it is measured clockwise

More Related