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Heredity and Genetic Analysis

Heredity and Genetic Analysis.

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Heredity and Genetic Analysis

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  1. Heredity and Genetic Analysis When you look at the seeds below you see the results of gametogenesis and fertilization. They represent a fraction of this plants potential progeny. In this chapter we will learn how Gregor Mendel experimented with pea plants to develop one of the key principles of Biology.

  2. Unit 8: Key learnings • The heredity of genes follows mathematical laws and can be predicted using Punnett square analysis. • Contributions from both parents contribute equally to the probability of inheriting any given trait.

  3. Unit 8: Essential question How can the probability of a given trait's inheritance be predicted using Punnett square analysis?

  4. 4 Launch activity: • Find individuals in the classroom who demonstrate the following characteristics. • Complete the reading and class demonstration utilizing PTC testing paper _____ _____ _____ _____ _____ _____

  5. Unit 8: Concepts • Probability (C) • Mendel's work (I) • Monohybrid crosses (E) • Dihybrid crosses (C) • Special patterns of inheritance (I) • Environmental considerations (C)

  6. Essential question 1.1: How do sample size, the product rule and the sum rule affect the probabilities of calculated events? LAB TIME!

  7. LEQ 1 summary: • Using a large sample size reduces the effect of random chance on the results. • PRODUCT RULE: To determine the probability of two events occurring simultaneously(this AND that), multiply their individual results. • SUM RULE: To determine the probability of two events occurring interchangeably(this OR that), add their individual results.

  8. Unit 8: Concepts • Probability (C) • Mendel's work (I) • Monohybrid crosses (E) • Dihybrid crosses (C) • Special patterns of inheritance (I) • Environmental considerations (C)

  9. Essential question 2.1: How did Mendel prove that each parent contributes one copy of each gene to their offspring?

  10. I. The passing of genes from one generation to the next is called heredity. • In 1866, a monk named Gregor Mendel began experimenting on hereditable patterns in pea plants. • Mendel followed the work of a British farmer who noticed some strange patterns in the reproduction of peas. • Mendel varied his approach from his predecessors by counting every single plant and noting its result (quantitative analysis).

  11. II. Peas have several useful features that make their study very effective. • Contrasting traits. • Tall versus short plants. • Round peas versus wrinkled peas. • Male and female parts can be easily separated to control matings. • New generations of peas are easy to produce and yield lots of easily interpreted results. • Each mating produces hundreds of offspring. • Many physical characteristics are available for study.

  12. Manual transferof pollen

  13. Mendel’s Experimental design Parental generation (P) Purebred for contrasting traits F1 Generation – All Purple F2 Generation – 3:1 – Purple : White Click the flower to watch the video –Mendelian Inheritance: The Big Picture

  14. III. Mendel began with monohybridcrosses. (one trait at a time) • All of the plants he used were purebred. • When self pollination occurs, only one trait appears in the offspring. (example: Offspring always have purple flowers) • These purebred plants were used for the Parental generation (P). • Mendel cross pollinated two parental plants that had contrasting traits (white flowers with purple flowers) and produced an F1 generation.

  15. III. Continued… • Each of Mendel’s F1 plants showed only one form of the trait (the dominant trait). • He allowed each F1 plant to self pollinate and produce an F2 generation. • Each of Mendel’s F2 generations showed a 3:1 ratio of dominant to recessive traits (recessive is the trait that hides in the F1).

  16. 7 traits observed by Mendel

  17. Trait Studied Dominant Form Recessive Form F2 Dominant-to- Recessive Ratio SEED SHAPE 5,474 round 1,850 wrinkled 2.96:1 SEED COLOR 6,022 yellow 2,001 green 3.01:1 2.95:1 POD SHAPE 882 inflated 299 wrinkled 428 green 152 yellow 2.82:1 POD COLOR FLOWER COLOR 705 purple 224 white 3.15:1 FLOWER POSITION 651 long stem 207 at tip 3.14:1 STEM LENGTH 787 tall 277 dwarf 2.84:1

  18. Question: What is a purebred plant? • When self pollination occurs, the results are 100% predictable. • Example: Self pollinated white flowered plants yield only white flowered offspring.

  19. Question: What aspect of Mendel’s experiment allowed him to discover the pattern? (Hint: think probability lab.) • He used massive repetition to minimize the effect of random chance (a principle of probability). • He accurately counted and analyzed his numerical data to discover the trend (quantitative).

  20. Essential question 2.2: How do modern scientists explain the patterns of inheritance that Mendel observed?

  21. IV. Mendel’s work became a theory on inheritance. • Before Mendel, people thought that offspring were just a blend of their parents characteristics. • Mendel made four hypothesis about inheritance: • For each inherited trait, an individual has two copies of the gene - (homologous pair). • There are alternative versions of each gene (alleles). • When two different versions are expressed together, one will dominate the other and prevent it from being expressed (dominant and recessive versions). • When gametes form, the two alleles separate so that each gamete receives only one copy (meiotic division). • These hypothesis have since been proven and modern vocabulary added (in parenthesis).

  22. V. Mendel’s findings have been put in modern terms. • Each trait is given a letter to represent both of its different versions (‘F’ and ‘f’ for the freckle gene). (Typically the capital letter corresponds with the first letter of the dominant description) • If an individual has two of the same letter, they are said to be homozygous(FF or ff). • If an individual has two different letters, they are said to be heterozygous(Ff).

  23. V. continued… • The set of alleles that an organism has is known as its genotype (FF, Ff, or ff). • The result (physical manifestation) of that genotype is called the phenotype(Freckles or no freckles). • The dominant phenotype may be coded for by 2 genotypes (FF and Ff). • The recessive phenotype can only be reached by one genotype (ff).

  24. VI. Mendel’s ideas have been condensed into two laws of heredity. • The law of segregation states that alleles will separate during gamete formation. • The law of independent assortment states that the alleles for different traits will segregate(separate) without influencing each other. (Show video from folder) • Example: The alleles for pea height, will segregate without affecting the alleles for pea color. A plant is just as likely to be tall with green peas as it is tall with yellow peas.

  25. Click to watch the video - the law of segregation

  26. Unit 8: Concepts • Probability (C) • Mendel's work (I) • Monohybrid crosses (E) • Dihybrid crosses (C) • Special patterns of inheritance (I) • Environmental considerations (C)

  27. Essential question 3.1: What information can be learned from a Punnett square analysis of a parental cross?

  28. Example: If tallness is the dominant trait, how would we show the cross for a purebred tall pea plant with a purebred short pea plant? Mendel’s P cross (P x P) Click to watch video Mendelian Inheritance Punnett square: Beginning – 1:16

  29. I. A Punnettsquare is a diagram that predicts the outcome of a genetic cross. • There are 3 types that we’ll consider: • Monohybrid: one characteristic(4 blocks) • Dihybrid: two characteristics(16 blocks) • Trihybrid: three characteristics (64 blocks)

  30. I. Continued… • There are a few simple rules when using a Punnett square: • The cross must be written above the square (HH x Hh). • All possible parental gametes must be predicted (along the left and top of the Punnett square). • The results are EXPECTED outcomes for each genotype, NOT the actual number and type of offspring that WILL be born. • Answers must be written in the proper form: genotypesor phenotypes as requested.

  31. Mendel’s F1 cross (F1 x F1) F2 generation

  32. F1 X F1 example 2 Note that while neither parent exhibited the albino phenotype they both carried a masked gene for albinism that they transmitted to a portion of their offspring.

  33. Standard Mendelian Cross #1:If purple flower color is dominant, what phenotypes are expected if a purebred purple flowered plant is crossed with a purebred white flowered plant. WW x ww 100% Purple or 4/4 Purple

  34. Standard Mendelian Cross #2:If purple flower color is dominant, what genotypes are expected if a heterozygote is crossed with another heterozygote. Ww x Ww 1 WW: 2 Ww: 1 ww or ¼ WW: 2/4 Ww: ¼ ww or 1 homozygous dominant: 2 heterozygous: 1 homozygous recessive

  35. Sample quiz question:What genotypes and phenotypes are possible in the F1 and F2 when a homozygous dominant yellow plant is crossed with a green one? YY x yy F1 = 100% Yy, 100% yellow F2 = 1 YY: 2 Yy: 1 yy, 3 yellow: 1 green

  36. Essential question 3.2: How can the unknown genotypes of organisms be determined using a test cross?

  37. II. It is possible to determine the genotype of a dominant phenotype by performing a test cross with that individual. • A dominant phenotype may be eitherXX or Xx. • When this unknown genotype is crossed with a homozygous recessive individual (xx), the results will reflect the presence or absence of a recessive allele. • If the unknown individual produces any recessive phenotype offspring, it must havebeen a heterozygote (Xx). • If the unknown individual produces all dominant phenotype offspring, it is probably homozygous dominant (XX).

  38. 7.7If a normally pigmented alligator crossed with a white alligator produces some normally pigmented offspring and some white offspring, what can you conclude regarding this normally pigmented alligator? Since the white coloration is a recessive trait, offspring would have to receive a recessive white allele from both parents. Therefore, the normally pigmented alligator in question must be a heterozygote, possessing one allele for normal pigmentation and one allele for white pigmentation.

  39. Question: How would you show the test cross (show both possibilities)if a yellow pea plant was test crossed with a green one. Click to watch video – Mendelian Inheritance: Punnett square 1:16 – 2:43

  40. Essential question 3.3: How do the phenotypes of polygenic traits differ from those affected by only one gene?

  41. III. Most traits are not controlled by simple dominant-recessive single gene alleles. • Polygenic traits are influenced by many genotypes affecting the same phenotype. • The phenotypes of these traits demonstrate continuous variation. • Examples: height, weight, skin color, intelligence.

  42. Continuous variation in skin color

  43. Unit 8: Concepts • Probability (C) • Mendel's work (I) • Monohybrid crosses (E) • Dihybrid crosses (C) • Special patterns of inheritance (I) • Environmental considerations (C)

  44. Essential question 4.1: Why does the number of predicted possibilities increase when conducting a dihybrid cross?

  45. I. Dihybridcrosses involve two pairs of contrasting traits. • First consider how the four alleles from each parent can combine to form different gamete combinations. • XxYy can produce gametes with XY, Xy, xY, or xy • Set up a Punnett square with spaces for 16 offspring. • Be sure that each gamete combination has only one allele from each trait (2 total - one of each). • Be sure that each offspring predicted has two copies of each allele for both traits (4 total- two of each). • A standard Mendelian cross of parents holding contrasting homozygous genotypes will result in a 9:3:3:1 ratio of phenotypes in the F2 generation.

  46. Dihybridexample #1

  47. Example #2: List the gamete combinations possible for each of the genotypes listed below: AB, AB, aB and aB AaBB aB, aB, aB, and aB aaBB AB, Ab, aB, and ab AaBb

  48. Example #3 Concept IV - Summarizing - page 11 in your guided study: In horses, black color dominates chestnut color. The trotting gait dominates the pacing gait. A cross is made between a horse homozygous for black color and pacing gait, and a horse homozygous for chestnut color and the trotting gait. List the probable phenotypes of offspring in the F1 and F2 generations.

  49. Example #3: answer F1: 100% black color and trotting gait F2: 9 black/trotting:3 black/pacing: 3 chestnut/ trotting:1 chestnut/pacing

  50. Example 4:Concept IV – Reviewing #3 – Guided study page 12. 0% In certain breeds of dogs, black color is dominant and red color is recessive. Solid color is dominant and white spotting is recessive. A homozygous black and white spotted male is crossed with a red and white spotted female. What percent of the offspring will be solid black puppies? All offspring will be Bbcc Black and white spotted pups.

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