1 / 9

CLASE 17

CLASE 17. EJERCITACIÓN VARIADA. OPERACIONES Y ECUACIONES EN. C. i es la unidad imaginaria. i. 1 2. •. C. 2. • i. R. 1 es la unidad real. • i. • 2+  i. • 1. • . • 0. • 1 + i. = – 1. • –0,3 + 5 i. Halla, si existen, todas las x  R. que satisfacen la igualdad:.

Download Presentation

CLASE 17

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. CLASE 17

  2. EJERCITACIÓN VARIADA. OPERACIONES Y ECUACIONES EN C

  3. i es la unidad imaginaria i 1 2 • C 2 •i R 1 es la unidad real •i •2+i •1 •  • 0 •1 + i = –1 •–0,3 + 5i .

  4. Halla, si existen, todas las xR que satisfacen la igualdad: x2–3x x2–3x x+ 2 1 x–3 1 x–3 +16i = 5 + 2 i x+ · x2–3x 4 = 2 2 (x–3) · : 16 5 = = x(x–3)+1=5(x–3) x2–3x+1=5x–15 4 = x2–3x x2–3x+1–5x+15=0 0 = x2–3x–4 x2–8x+16=0

  5. 0 = x2–3x–4 x2–8x+16 = 0 (x – 4)2=0 0 = (x – 4)(x + 1) x – 4=0 ó x + 1=0 x – 4 = 0 x = 4 ó x = –1 x = 4 El único número real x que satisface la igualdad es 4 . .

  6. Resuelve la siguiente ecuación en el conjunto de los números complejos: · x x4+ = x3+16 16 x x0 x5+16 = x4+16x : x5–x4–16x +16 = 0 x4(x – 1) 1 –1 0 0 –16 16 –16( )=0 x – 1 1 1 0 0 0 –16 (x – 1)(x4– 16) = 0 0 1 0 0 0 –16 (x – 1)(x2 – 4)(x2 + 4) = 0

  7. (x – 1)(x2 – 4)(x2+ 4) = 0 x=  4 x= –4 2 = 4i x– 1 = 0 x= 1 x = 1 x= 2 x2– 4 = 0 x = 2 x2 = 4 Cinco soluciones x =–2 x = 2i x = 2i x2+ 4 = 0 x =–2i x2 = –4 .

  8. C D= 16 x2+ 1 = 10 x ESTUDIO INDIVIDUAL a) Resuelve en el conjunto la ecuación: x=2 x=–1+2i x=–1–2i b) Determina los números reales x que satisfacen la igualdad: 2 log x+(x+2+x)i=log(x+2)+4i x=2 .

  9. . Efectúa: 4 . (2cis60o) cis90o 81 4 (1+i3 ) i . = = =1+3 8 cis150o =3  =(1) +(3) 2 2 = 1 4 81 3 1 = i = i 81 tan = 1+i3 i 8 cis150o 16 cis240o · cis90o 16 cis330o 8 cis150o 8 cis150o = –2 = 2 cis180o = 2 = cis 90o 20  = 60o 1

More Related