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Welcome

Welcome. Subnetting. 192 . 168 . 10 .0/ 24 11 000000. 1 0 1 0 1 000.0000 1 0 1 0.00000000 11111111 . 11111111 . 11111111 .00000000 255.255.255.0. Host portion. Network portion. If you want to do subnetting you must answer these questions :. 1-How many networks I need?

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Welcome

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  1. Welcome

  2. Subnetting

  3. 192.168.10.0/24 11000000.10101000.00001010.00000000 11111111.11111111.11111111.00000000 255.255.255.0 Host portion Network portion

  4. If you want to do subnetting you must answer these questions : 1-How many networks I need? 2-How many hosts in each networks? 3-What are the broadcasts address? 4-What are the valid hosts in each subnets?

  5. 192.168.1.0/25 255.255.255.128 1-How many networks I need? 11111111.11111111.11111111.10000000 2^N = X 2^1 = 2 N = borrowed bits X = networks number

  6. 192.168.1.0/25 255.255.255.128 2-How many hosts in each networks? 11111111.11111111.11111111.10000000 2^N – 2 = X 2^7 – 2 = 128 – 2 = 126 N = 0’s X = Hosts

  7. 192.168.1.0/25 255.255.255.128 11111111.11111111.11111111.10000000 3- What are the valid subnets? 256 – 128 = 128 Network1 : 192.168.1.0 +128 Network2 : 192.168.1.128

  8. 192.168.1.0/25 255.255.255.128 11111111.11111111.11111111.10000000 3- What are the valid subnets? 256 – 128 = 128 Network1 : 192.168.1.0 +128 Network2 : 192.168.1.128

  9. 192.168.1.0/25 255.255.255.128 4-What is the broadcast address? 5- What the valid hosts in each subnet?

  10. 192.168.1.0 255.255.255.128 Is the same as 192.168.1.0/25 11111111.11111111.11111111.10000000

  11. 172.10.0.0/22 255.255.252.0 1-How many networks I need? 11111111.11111111.11111100.00000000 2^N = X 2^6 = 64 N = borrowed bits X = networks

  12. 172.10.0.0/22 255.255.252.0 2-How many hosts in each networks? 11111111.11111111.11111100.00000000 2^N – 2 = X 2^10 – 2 = 1024 – 2 = 1022 N = 0’s X = Hosts number

  13. 172.10.0.0/22 255.255.252.0 3- What are the valid subnets? 256 – 252= 4 Network1 : 172.10.0.0 +4 Network2 : 172.10.4.0 +4 Network3 : 172.10.8.0 to Network 64 : 172.10.252.0

  14. 172.10.0.0/22 255.255.252.0 4-What is the broadcast address? 5- What the valid hosts in each subnet?

  15. TO

  16. Please identify the right network mask for the following IP address:* 1- 192.168.0.1 /25. 255.255.255.128 2- 10.0.0.1 /18 . 255.255.192.0 3- 172.10.0.0 / 19. 255.255.224.0 4- 192.168.0.2 / 24. 255.255.255.0 *Please identify the host and the network portion of each IP address: 11111111.11111111.11111111.000000001- 192.168.0.1 /24 2- 10.0.0.5 /26 11111111.11111111.11111111.11000000 *Red 1 : Network portion *Black 0 : Host portion

  17.  *Please convert this IP address 192.168.12.3 / 23 to binary number and Identify the first host, last host, broadcast, and network? 192.168.12.3/23 IP address : 11000000.101010000.00001100.00000011 255.255.254.0 Subnet mask : 11111111.11111111.11111110.00000000 128Network : 2^7 = Hosts : 2^9 – 2 = 512 – 2 = 510

  18. *Create two sub-networks from this address 172.16.0.0 and each sub-network has only fourteen hosts? 172.16.0.0\28 11111111.11111111.11111111.11110000 255.255.255.240 Networks : 2^12= 4096 Hosts : 2^4 – 2 = 16 – 2 = 14

  19. 172.16.0.0\28 11111111.11111111.11111111.11110000 255.255.255.240 256 – 240 = 16 Networks : 1- 172.16.0.0 2- 172.16.0.16 To 4096 - 172.16.255.240

  20. 172.16.0.0\28 11111111.11111111.11111111.11110000 255.255.255.240

  21. Thanks for the attendance Preparing by Sayfuldeen & Abdulaziz

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