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Physics: Chapter 3 Vector & Scalar Quantities

Physics: Chapter 3 Vector & Scalar Quantities. Ms. Goldamer Greenfield High School Copy everything into your notes. Characteristics of a Scalar Quantity. Only has magnitude Requires 2 things: 1. A value 2. Appropriate units Ex. Mass: 5kg Temp: 21 ° C Speed: 65 mph.

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Physics: Chapter 3 Vector & Scalar Quantities

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  1. Physics: Chapter 3Vector & Scalar Quantities Ms. Goldamer Greenfield High School Copy everything into your notes.

  2. Characteristics of a Scalar Quantity • Only has magnitude • Requires 2 things: 1. A value 2. Appropriate units Ex. Mass: 5kg Temp: 21° C Speed: 65 mph

  3. Characteristics of a Vector Quantity • Has magnitude & direction • Requires 3 things: 1. A value 2. Appropriate units 3. A direction! Ex. Acceleration: 9.8 m/s2 down Velocity: 25 mph West

  4. More about Vectors • A vector is represented on paper by an arrow 1. the length represents magnitude 2. the arrow faces the direction of motion 3. a vector can be “picked up” and moved on the paper as long as the length and direction its pointing does not change

  5. Graphical Representation of a Vector The goal is to draw a mini version of the vectors to give you an accurate picture of the magnitude and direction. To do so, you must: • Pick a scale to represent the vectors. Make it simple yet appropriate. • Draw the tip of the vector as an arrow pointing in the appropriate direction. • Use a ruler to draw arrows for accuracy. The angle is always measured from the horizontal or vertical. We don’t have protractors so make your best guess for angles.

  6. Understanding Vector Directions To accurately draw a given vector, start at the second direction and move the given degrees to the first direction. N 30° N of E W E Start on the East origin and turn 30° to the North S

  7. Graphical Representation Practice • 5.0 m/s East (suggested scale: 1 cm = 1 m/s) • 300 Newtons 60° South of East (suggested scale: 1 cm = 100 N) • 0.40 m 25° East of North (suggested scale: 5 cm = 0.1 m)

  8. Graphical Addition of Vectors Tip-To-Tail Method • Pick appropriate scale, write it down. • Use a ruler & protractor, draw 1st vector to scale in appropriate direction, label. • Start at tip of 1st vector, draw 2nd vector to scale, label. • Connect the vectors starting at the tail end of the 1st and ending with the tip of the last vector. This = sum of the original vectors, its called the resultant vector.

  9. Mathematical Addition of Vectors • Vectors in the same direction: Add the 2 magnitudes, keep the direction the same. Ex. + = 3m E 1m E 4m E

  10. Mathematical Addition of Vectors • Vectors in opposite directions Subtract the 2 magnitudes, direction is the same as the greater vector. Ex. 4m S + 2m N = 2m S

  11. Graphical Addition of Vectors (cont.) 5 Km Scale: 1 Km = 1 cm 3 Km Resultant Vector (red) = 6 cm, therefore its 6 km.

  12. Vector Addition Example #1 • Use a graphical representation to solve the following: Another hiker walks 2 km south and 4 km west. What is the sum of her distance (resultant vector) traveled using a graphical representation?

  13. Vector Addition Example #1 (cont.) Answer = ????????

  14. Vector Addition Example #3 • Use a graphical representation to solve the following: A hiker walks 1 km west, then 2 km south. What is the sum of his distance traveled using a graphical representation?

  15. Vector Addition Example #3 (cont.) Answer = ???????? Hint: Use Pythagorean Theorem for both triangles, and add your two resultant vectors in red.

  16. Mathematical Addition of Vectors • Vectors that meet at 90° Resultant vector will be hypotenuse of a right triangle. Use trig functions and Pythagorean Theorem.

  17. Mathematical Subtraction of Vectors • Subtraction of vectors is actually the addition of a negative vector. • The negative of a vector has the same magnitude, but in the 180° opposite direction. Ex. 8.0 N due East = 8.0 N due West 3.0 m/s 20° S of E = 3.0 m/s 20° N of W

  18. Subtraction of Vectors (cont.) • Subtraction used when trying to find a change in a quantity. • Equations to remember: ∆d = df – di or ∆v = vf – vi • Therefore, you add the second vector to the opposite of the first vector.

  19. Subtraction of Vectors (cont.) • Ex. = Vector #1: 5 km East Vector #2: 4 km North 5 km W (v1) 4 km N (v2)

  20. Practice Problems Adding and Subtracting Vectors(Due Fri. in Packet #4) • 1. A hiker walks 5 km west, then 4 km west. What is the sum of his distance traveled? • 2. A hiker walks 15 km west, then 12 km east. What is the sum of his distance? • 3. A hiker walks 34 km north, then 12 km south. What is the sum of his distance traveled? • 4. A hiker walks .5 km south, then 78.5 km south. What is the sum of his distance traveled? • A hiker walks 13 km east, then 2 km west. What is the sum of his distance traveled using a graphical representation?

  21. Practice Problems (Use Pythagorean Theorem) • 1. A hiker walks 9 km west, then 3 km south. What is the sum of his distance traveled using a graphical representation? • 2. A hiker walks 12 km north, then 3 km west. What is the sum of his distance traveled using a graphical representation? • 3. A hiker walks 4 km east, then 3 km south. What is the sum of his distance traveled using a graphical representation? • 4. A hiker walks 12 km east, then 9 km north. What is the sum of his distance traveled using a graphical representation? • 5. A hiker walks 4 km west, then 8 km south. What is the sum of his distance traveled using a graphical representation?

  22. Component Method of Vector Addition • Treat each vector separately: 1. To find the “X” component, you must: Ax = Acos Θ 2. To find the “Y” component, you must: Ay = Asin Θ 3. Repeat steps 2 & 3 for all vectors

  23. Component Method (cont.) 4. Add all the “X” components (Rx) 5. Add all the “Y” components (Ry) 6. The magnitude of the Resultant Vector is found by using Rx, Ry & the Pythagorean Theorem: RV2 = Rx2 + Ry2 7. To find direction: Tan Θ = Ry / Rx

  24. Component Method (cont.) Ex. #1 V1 = 2 m/s 30° N of E V2 = 3 m/s 40° N of W (this is easy!) Find: Magnitude & Direction Magnitude = 2.96 m/s Direction = 78° N of W

  25. Component Method (cont.) Ex. #2 F1 = 37N 54° N of E F2 = 50N 18° N of W F3 = 67 N 4° W of S (whoa, this is not so easy!) Find: Magnitude & Direction Magnitude =37.3 N Direction = 35° S of W

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