H 2 O P-T Phase Diagram

1 / 15

# H 2 O P-T Phase Diagram - PowerPoint PPT Presentation

H 2 O P-T Phase Diagram. For High T the Energy is Mostly Kinetic Energy and KE= ½ mu 2 (u=the molecular speed is high) (m=molecular mass ) [u]- meters per sec, ms -1 [m]- kilograms, kg [KE] - joules, J. PE. KE. • What is Temperature(T)? • What is pressure(P)? • What is volume(V)?

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'H 2 O P-T Phase Diagram' - leroy-lawrence

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
H2O P-T Phase Diagram

For High T the Energy

is Mostly Kinetic Energy

and KE= ½ mu2

(u=the molecular speed is high)

(m=molecular mass )

[u]- meters per sec, ms-1

[m]- kilograms, kg

[KE] - joules, J

PE

KE

• What is Temperature(T)?

• What is pressure(P)?

• What is volume(V)?

• N=number of particles(atoms/molecules)

• N/V= number density( number per unit volume)

Van der Waals

Potential Curves

E= KE + V(R)

For gases KE>> V(R)

e

s

Fig. 9-18, p. 392

Zero energy

turning point

Bond energy

Table 9-4, p. 392

Van der Waals

Potential Curves

E= KE + V(R)

For gases KE>> V(R)

e

s

Fig. 9-18, p. 392

H2O P-T Phase Diagram

For High T the Energy

is Mostly Kinetic Energy

and KE= ½ mu2

(u=molecular speed is high)

(m=molecular mass )

[u]- meters per sec, ms-1

[m]- kilograms, kg

[KE] - joules, J

PE

KE

Measuring the speed distribution in a gas

Effusion cell

Solid or

liquid sample

Fig. 9-19, p. 394

Effusive beam used to mDx/easure speed distribution

u=Dx/Dt

For He with u=500 ms-1

m= 4 amu

KE= ½ (4 amu)(500 ms-1)2

(1.66x10-27 kg)(500,000m2s-2)

KE=8.3 x10-22 J

Dx

Speed

Fig. 9-13, p. 383

=(8kBT/πm)1/2 average speed

=(3kBT/m) average square speed

urms= (3kBT/m)1/2 root mean square speed

ump = (2kBT/m)1/2 most probable spped

Fig. 9-14, p. 384

Van der Waals

Potential Curves

E= KE + V(R)

For gases KE>> V(R)

e

s

Fig. 9-18, p. 392

=(8kBT/πm)1/2 average speed

=(3kBT/m) average square speed

urms= (3kBT/m)1/2 root mean square speed

ump = (2kBT/m)1/2 most probable spped

Fig. 9-14, p. 384

Effusive beam used to mDx/easure speed distribution

u=Dx/Dt

For He with u=500 ms-1

m= 4 amu

KE= ½ (4 amu)(500 ms-1)2

(1.66x10-27 kg)(500,000m2s-2)

KE=8.3 x10-22 J

Dx

Speed

Fig. 9-13, p. 383