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How many bikes can be made from 100 bicycle wheels, 20 frames and 80 pedals?

How many bikes can be made from 100 bicycle wheels, 20 frames and 80 pedals? 100 wheels × 1 bike = 50 bikes 2 wheels 20 frames × 1 bike = 20 bikes 1 frame 80 pedals × 1 bike = 40 bikes 2 pedals. When given the reaction:

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How many bikes can be made from 100 bicycle wheels, 20 frames and 80 pedals?

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  1. How many bikes can be made from 100 bicycle wheels, 20 frames and 80 pedals? 100 wheels × 1 bike = 50 bikes 2 wheels 20 frames × 1 bike = 20 bikes 1 frame 80 pedals × 1 bike = 40 bikes 2 pedals

  2. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent?

  3. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 1

  4. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 4 mol S2Cl2 1 4 mol Cl2

  5. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 4 mol S2Cl2 × 135 g S2Cl2 1 4 mol Cl2 1 mol S2Cl2

  6. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 4 mol S2Cl2 × 135 g S2Cl2 = 675 g S2Cl2 1 4 mol Cl2 1 mol S2Cl2 2.0 mol S8 × 4 mol S2Cl2 × 135 g S2Cl2 = 1080 g S2Cl2 1 1 mol S8 1 mol S2Cl2

  7. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 100.0 g Cl2 reacts with 200 g S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? • Each group must create a complete solution and present part of the solution to the class. • You will be assigned one part of the solution half way through the class period. • Mr. Gouterman will decide who will write the solution and who will explain the answer.

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