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20 cm

T real = T + 20 T c = 100 ºC. 10 cm. 20 cm. = 7830 kg/m 3 c p = 0.464 kW/(kg·K) k = 0.053 kW/(m·K). h = h conv. libre + h radiación h conv. libre = 0.01 kW/(m 2 ·K) h radiación = [(T+293) 4 – 293 4 ]/(T-0) = 5.67·10 -11 kW/ /(m 2 ·K),  = 1

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20 cm

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  1. Treal = T + 20 Tc = 100 ºC 10 cm 20 cm

  2. = 7830 kg/m3 cp = 0.464 kW/(kg·K) k = 0.053 kW/(m·K) • h = hconv. libre + hradiación • hconv. libre = 0.01 kW/(m2·K) • hradiación = [(T+293)4 – 2934]/(T-0) • = 5.67·10-11 kW/ /(m2·K),  = 1 T=20, hradiación = 0.04 kW/(m2·K) • a = 2S/V=2S/(S·espesor)=2/espesor ha = 0.1/espesor, espesor = 4 mm, ha = 25 kW/(m2·K) h1 = h2 = h3 = 0.05 kW/(m2·K)

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