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How to Figure a Bill of Materials. Materials Being Used. Spacing = 16”oc. 45. 30. Floor . Materials 2x12x16’s ¾” Plywood Equations Distance x 12/Spacing + 1 Area/32 End Caps . 45. 30. Floor . 2x12x16’s Distance x 12/spacing + 1 45x12/16+1= 34.75 = 35

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## How to Figure a Bill of Materials

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**Spacing = 16”oc**45 30**Floor**• Materials • 2x12x16’s • ¾” Plywood • Equations • Distance x 12/Spacing + 1 • Area/32 • End Caps 45 30**Floor**• 2x12x16’s • Distance x 12/spacing + 1 • 45x12/16+1= • 34.75 = 35 • But a 16’ Board will not reach 30’ • 35 x 2= 70 • End Caps • Length x 2/board length • 45x2/16 • 5.63 = 6 • Plywood • Area/32 • 45 x 30/32 • 42.2 = 43 45 30**Walls**• Materials • 2x4x8 Studs • 2x4x16 • ½” OSB • Equations • Distance x 12/Spacing + 1 • Area/32 • Sills/Top Plate 45 30**Wall**• 2x4x8 Studs • Distance x 12/spacing +1 • 45x12/16+1 • 34.75 = 35x 2= 70 • 30x12/16+1 • 23.5= 24x2= 48 • 2x4x16 • (Length x 2/ Board length)x3 • (45+30)x2/16 • 9.4 = 10 x3= 30 45 30**Wall**• OSB • Area/ 32 • Wall Height • 45x8/32 • 11.25= 12 x 2 = 24 • 30x8/32 • 7.5 = 8 x 2 = 16 • Total Sheets • 24+16= 40 45 30**Roof**• Materials • Trusses • Equations • Distance x 12/Spacing + 1 • Trusses • 45x12/16+1 • 35 45 30**Roof**• Materials • ½” OSB • Shingles • Equations • Pythagorean Theorem • Area/32 • Area/100 Height= 8’ 36’**Roofing**• OSB • Pythagorean Theorem • (8x8)+(18x18)=(CxC) • 64+324 • 388 • 19.7= 20 • Area/32 • 20x45/32 • 28.1= 29 x2=28 Height= 8’ 36’**Roofing**• Shingles • 45 x 20/100 • 9 x 2 • 18 Bundles • Shingles are sold in bundles that cover 10’ x 10’ Height= 8’ 36’**Drywall**• Materials • 4x12 Drywall • Equations • Area/48 • Problem • 45x8/48 • 7.5 = 8 • 30x8/48 • 5 • 45x30/48 • 28.2= 29 • 29+5+8= 45 30**Tile**• Materials • 12” Tile • 10 Tile/Box • Equations • Area/ Coverage Area • 45x30/1 • 1350 • 1350/10 • 135 Boxes 45 30

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