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PowerPoint Slideshow about 'Binomial Probability' - honorato-pearson


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slide2
Sixty percent of all computer monitors sold by a large computer retailer have a flat panel display and 40% have a CRT display. The type of monitor purchased by each of the next 12 customers will be noted. Find the probability that exactly 6 will purchase a flat panel display.
  • Define what a success is.
  • What is the probability of a success?

Binompdf(12,.6,6)=0.1766

slide3
Sixty percent of all computer monitors sold by a large computer retailer have a flat panel display and 40% have a CRT display. The type of monitor purchased by each of the next 12 customers will be noted. Find the probability that at most four will purchase a flat panel display.

Binomcdf(12,.6,4)=0.0573

slide4
Sixty percent of all computer monitors sold by a large computer retailer have a flat panel display and 40% have a CRT display. The type of monitor purchased by each of the next 12 customers will be noted. Find the probability that less than four.

Binomcdf(12,.6,3)=0.0153

slide5
Sixty percent of all computer monitors sold by a large computer retailer have a flat panel display and 40% have a CRT display. The type of monitor purchased by each of the next 12 customers will be noted. Find the probability that between 4 and 7 will purchase flat panel monitors . (inclusive)

Binomcdf(12,.6,7) - Binomcdf(12,.6,3)=0.5466

slide6
Sixty percent of all computer monitors sold by a large computer retailer have a flat panel display and 40% have a CRT display. The type of monitor purchased by each of the next 12 customers will be noted. Find the mean, variance and standard deviation of the number of people that purchase flat panel displays.

μ=7.2

σ2=2.9

σ=1.7

slide7
In recent years, homeowners have become increasingly security conscious. A Los Angeles Times poll reported that almost 20% of Southern California homeowners questioned had installed a home security system. Suppose that exactly 20% of all such homeowners have a system. Consider a random sample of 20 homeowners, find the probability that at least 8 have a security system.

1- Binomcdf(20,.2,7)=0.0321

slide8
Newsweek reported that one-third of all credit card users pay their bills in full each month. This figure is, of course, an average across different cards and issuers. Suppose that 30% of all individuals holding Visa cards issued by a certain bank pay in full each month. A random sample of 25 cardholders is to be selected. Find the mean, variance, and standard deviation of the number of cardholders that pay their bills in full each month.

μ=7.5

σ2=5.3

σ=2.3

slide9
Suppose that in a certain metropolitan area 9 out of 10 households have a VCR. Calculate the probability that in a group of four households, exactly two would have a VCR.

Binompdf(4,.9,2)=0.0486

slide10
Suppose that in a certain metropolitan area 9 out of 10 households have a VCR. Calculate the probability that in a group of four households all four would have a VCR.

Binompdf(4,.9,4)=0.6561

slide11
According to a Los Angeles Times survey, the activity preferred by 80% of airline passengers on flights is sleeping. If 50 airline passengers are interviewed, find the probability that 45 prefer sleeping.

Binompdf(50,.8,45)=0.0295

slide12
According to a Los Angeles Times survey, the activity preferred by 80% of airline passengers on flights is sleeping. If 50 airline passengers are interviewed, find the mean, variance, and standard deviation of the number that prefer sleeping.

μ=40

σ2=8

σ=2.8

slide13
According to a Los Angeles Times survey, the activity preferred by 80% of airline passengers on flights is sleeping. If 50 airline passengers are interviewed, find the probability that at least 40 prefer sleeping.

1-Binomcdf(50,.8,39)=0.5836

slide14
Twenty-five percent of the customers entering a grocery store between 5PM and 7PM use an express checkout. Consider ten randomly selected customers, and let x denote the number among the ten who use the express checkout.

Find P(x=2)

What is P(x≤3)

What is P(x≥4)

Binompdf(10,.25,2)=0.2816

Binomcdf(10,.25,3)=0.7759

1-Binomcdf(10,.25,3)=0.2241