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Prof. Abel Esteban Ortega Luna

CONGRUENCIA DE TRIÁNGULOS. Prof. Abel Esteban Ortega Luna. http://matematicaabelortega.blogspot.com/. B. E. A. C. D. F. CASOS DE CONGRUENCIA. PRIMER CASO:. LADO – ÁNGULO – LADO ( L – A – L ). . . B. D. E. C. A.

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Prof. Abel Esteban Ortega Luna

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  1. CONGRUENCIA DE TRIÁNGULOS Prof. Abel Esteban Ortega Luna http://matematicaabelortega.blogspot.com/

  2. B E A C D F CASOS DE CONGRUENCIA PRIMER CASO: LADO – ÁNGULO – LADO (L – A – L)  

  3. B D E C A 1) En la figura los triángulos ABC y BDE son equiláteros. Calcula CD, si AE = 3. 60º ABE BDC 60º x = 3 x 3

  4. 2x B 60º x A E D 2) En la figura, calcula el valor de “x”; si AB // CD; AB = DE y CD = AE C ABE DCE 60º x 3x = 60º x = 20º  

  5. B E A C D F SEGUNDO CASO: ÁNGULO – LADO – ÁNGULO (A – L – A)    

  6. B C P A Q 1)En la figura mostrada, si AB = BC; BP = 4 y PQ = 3. Calcula PC. + = 90º   ABQ BPC   4 x = 4 + 3  X x = 7 3 

  7. 5 2) En la figura, halla x/y E ABL EBC  x 2x = y C y x 1 = 2 y 2 3 y 3 B x x 2  L A

  8. B E A C D F TERCER CASO: LADO – LADO – LADO (L – L – L)

  9. 1) Encuentra “x”, si AB = BD, BC = BE, AE = DC B ABE BDC 50º + x 50º 50º A x C D 50º + 50º + x = 180º 100º + x = 180º x = 80º E

  10. 2) Halla “x” B ABM ALE 35º = 50º – x x = 50º – 35º x = 15º L 50º 35º A E 45º 50º x 50–X M

  11. B E A C D F CASO ESPECIAL: ÁNGULO – LADO – LADO MAYOR (A – L – Lm) LADO MAYOR LADO MAYOR  

  12. 1) En la figura, calcule “x” M ARO MOR (A – L – Lm) 3x 60º x = 60º – 3x 60–3x 4x = 60º x = 15º 120º+x R 60º 60º – x 60º 2x 120º+x x 60–2x A O

  13. En el gráfico, calcula “x”, si AB = CD y BC  AD B ABE CED (A – L – Lm) 3X 5x = 45º C x = 9º 2X 45º 45º 3X A D E

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