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Understanding Planetary Orbits and Newton's Law of Gravity

Learn about the motion of satellites and planets using Newton's theory of gravity. Discover the basic laws of planetary orbits and the geometric shape of orbits. Understand the value of gravity at different altitudes and explore Kepler's laws.

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Understanding Planetary Orbits and Newton's Law of Gravity

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  1. Chapter 13 The beautiful rings of Saturn consist of countless centimeter-sized ice crystals, all orbiting the planet under the influence of gravity. Goal: To use Newton’s theory of gravity to understand the motion of satellites and planets.

  2. Who discovered the basic laws of planetary orbits? • Newton • Kepler • Faraday • Einstein • Copernicus

  3. What is geometric shape of a planetary or satellite orbit? • Circle • Hyperbola • Sphere • Parabola • Ellipse

  4. The value of g at the height of the space shuttle’s orbit is • 9.8 m/s2. • slightly less than 9.8 m/s2. • much less than 9.8 m/s2. • exactly zero.

  5. Newton’s Universal “Law” of Gravity Newton proposed that every object in the universe attracts every other object. The Law: Any pair of objects in the Universe attract each other with a force that is proportional to the products of their masses and inversely proportional to the square of their distance

  6. Newton’s Universal “Law” of Gravity “Big” G is the Universal Gravitational Constant G = 6.673 x 10-11 Nm2 / kg2 Two 1 Kg particles, 1 meter away Fg= 6.67 x 10-11 N (About 39 orders of magnitude weaker than the electromagnetic force.) The force points along the line connecting the two objects.

  7. Newton’s Universal “Law” of Gravity You have three 1 kg masses, 1 at the origin, 2 at (1m, 0) and 3 at (0, 1m). What would be the Net gravitational force on object 1 by objects 2 & 3? G = 6.673 x 10-11 Nm2 / kg2 Two 1 Kg particles, 1 meter away Fg= 6.67 x 10-11 N Each single force points along the line connecting two objects. Fg=9.4 x 10-11 N along diagonal

  8. Motion Under Gravitational Force • Equation of Motion • If M >> m then there are two classic solutions that depend on the initial r and v • Elliptical and hyperbolic paths

  9. Anatomy of an ellipse • a: Semimajor axis • b: Semiminor axis • c: Semi-focal length • a2 =b2+c2 • Eccentricity e = c/a If e = 0, then a circle Most planetary orbits are close to circular.

  10. A little history • Kepler’s laws, as we call them today, state that 1. Planets move in elliptical orbits, with the sun at one focus of the ellipse. 2. A line drawn between the sun and a planet sweeps out equal areas during equal intervals of time. 3. The square of a planet’s orbital period is proportional to the cube of the semimajor-axis length. Focus Focus

  11. Kepler’s 2nd Law • The radius vector from the sun to a planet sweeps out equal areas in equal time intervals (consequence of angular momentum conservation). • Why?

  12. Conservation of angular momentum • Area of a parallelogram = base x height • L is constant (no torque)

  13. Kepler’s 3rd Law • Square of the orbital period of any planet is proportional to the cube of semimajor axis a.

  14. Little g and Big G Suppose an object of mass m is on the surface of a planet of mass M and radius R. The local gravitational force may be written as where we have used a local constant acceleration: On Earth, near sea level, it can be shown that gsurface ≈ 9.8 m/s2.

  15. Cavendish’s Experiment F = m1 g = G m1 m1 / r2 g = G m2 / r2 If we know big G, little g and r then will can find the mass of the Earth!!!

  16. Orbiting satellites vt = (gr)½ Net Force: ma = mg = mvt2 / r gr = vt2vt = (gr)½The only difference is that g is less because you are further from the Earth’s center!

  17. Geostationary orbit

  18. Geostationary orbit • The radius of the Earth is ~6000 km but at 36000 km you are ~42000 km from the center of the earth. • Fgravity is proportional to 1/r2 and so little g is now ~10 m/s2 / 50 • vT = (0.20 * 42000000)½ m/s = 3000 m/s • At 3000 m/s, period T = 2p r / vT = 2p 42000000 / 3000 sec = = 90000 sec = 90000 s/ 3600 s/hr = 24 hrs • Orbit affected by the moon and also the Earth’s mass is inhomogeneous (not perfectly geostationary) • Great for communication satellites (1st pointed out by Arthur C. Clarke)

  19. Tuesday • All of Chapter 13

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