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Construction. Designed and compiled by. Sanjeev Kumar Taneja District maths coordinator ludhiana. Menu. Construction 1a Construct a triangle (ASA). Construction 1b Construct a triangle (SAS). Construction 2 Construct the bisector of an angle.

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Construction

Construction

Designed and compiled by

Sanjeev Kumar Taneja

District maths coordinator

ludhiana


Construction

Menu

Construction 1a Construct a triangle (ASA)

Construction 1b Construct a triangle (SAS)

Construction 2 Construct the bisector of an angle

Construction 3 Construct the perpendicular bisector

of a line segment.

Construction 4 Construct the circumcircle of a triangle.

Construction 5 Construct the incircle of a triangle.

Construction 6 Divide the line segment [ab] into three

equal parts.


Construct the triangle pqr where qr 8cm pqr 52 o and prq 46 o a s a
Construct the triangle PQR where |QR|=8cm, |  PQR|=52o and |PRQ|=46o (A S A)

  • At Q using a protractor mark and draw an angle of 52o.

  • Draw a line segment [QR] 8cm in length. Name the points and mark the length.

  • At R mark and draw an angle of 46o

  • Mark the point of intersection of the two angles.

  • This is the point P.

P

46°

52°

Quit

Q

R

|QR|=8cm

Menu

END OF CONSTRUCTION


Construct a triangle abc where ab 12cm bac 65 o and ac 9 cm s a s
Construct a triangle ABC where |AB| = 12cm, |  BAC|=65o and |AC| = 9 cm (S A S)

USE MOUSE CLICKS TO VIEW CONSTRUCTION

  • Draw a line segment 12cm in length. Name the points and mark the length.

  • Use a protractor to draw a line at 65o to |AB|.

  • Use a compass with A as centre and 9cm radius to draw an arc on this line.

  • Mark the point of intersection C.

  • Join C to B and complete labels.

C

|AC|=9cm

65°

Quit

A

b

|AB|=12cm

Menu

END OF CONSTRUCTION


Construct the bisector of an angle
Construct the bisector of an angle

  • Draw the angle AOB.

  • Using the vertex o as centre draw an arc to meet the arms of the angle at X and Y.

  • Using X as centre and the same radius draw a new arc.

  • Using Y as centre and the same radius draw an overlapping arc.

  • Mark the point where the arcs meet.

  • The bisector is the line from O to this point.

A

X

X

X

O

Quit

Y

Menu

B

END OF CONSTRUCTION


Construct the perpendicular bisector of a line segment
Construct the perpendicular bisector of a line segment

  • Using A as centre and a radius greater than half |AB| draw an arc.

  • Using B as centre and the same radius draw another arc.

  • Draw a line through the points where the arcs cross.

  • Draw the line segment

A

B

Quit

Menu

END OF CONSTRUCTION


Construct the circumcircle of a triangle
Construct the circumcircle of a triangle

A

O

C

B

  • Draw the triangle ABC

  • Construct the perpendicular bisector of [AB]

Quit

  • Construct the perpendicular bisector of [AC]

  • The bisectors meet at O the circumcentre of the triangle

  • Using O as centre and |OA| as radius construct the circumcircle of the triangle ABC

Menu

END OF CONSTRUCTION


Construct the incircle of a triangle
Construct the incircle of a triangle

A

O

O

X

O

  • Draw the triangle ABC

  • Construct the bisector of angle ABC as shown.

  • Construct the bisector of angle ACB as shown.

  • The bisectors meet at point O, the incentre of the triangle

  • Using O as centre construct the incircle of the triangle ABC

X

C

B

Quit

Menu

END OF CONSTRUCTION


Divide the line segment ab into three equal parts
Divide the line segment [AB] into three equal parts

  • Draw the line segment [AB].

  • Through A draw a line at an acute angle to [AB].

  • On this line use circle arcs of the same radius to mark off three segments of equal length [AR], [RS] and [ST].

  • Join T to B.

  • Through S and R draw line segments parallel to [TB] to meet [AB] at D and C.

  • Now |AC|=|CD|=|DB|

A

C

D

B

R

S

Quit

T

Menu

END OF CONSTRUCTION