132 Views

Download Presentation
##### C ollege A lgebra

**An Image/Link below is provided (as is) to download presentation**

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -

**University of Palestine**IT-College College Algebra Systems and Matrices(Chapter5) L:20 1**Use Cramer’s Rule to solve the system.**7x + 3y = 15 2x + 9y = 12 Find D first, since if D = 0, Cramer’s Rule does not apply. The solution set is {(3, 2)}. Example**Example continued**• Thus: • The solution set is**5.4**Properties of Matrices**Basic Definitions**• It is customary to use capital letters to name matrices. Also, subscript notation is often used to name elements of a matrix, as shown. • A n n matrix is a square matrix. • A matrix with just one row is a row matrix. • A matrix with just one column is a column matrix. • Two matrices are equal if they are the same size and if corresponding elements, position by position, are equal.**Example**• Find the values of the variables which makes the statement true. • From the definition of equality, the only way that the statement can be true is if a = 3, b = 4, x = 2 and y = 7.**Addition and Subtraction of Matrices**• To add two matrices of the same size, add corresponding elements. Only matrices of the same size can be added. • If A and B are two matrices of the same size, then A B = A + (B).**Examples**• Add and subtract the following. • AddSubtract**Examples continued**• Add or subtract, if possible. • a) • b) The matrices have different sizes so they cannot be added or subtracted.**Properties of Scalar Multiplication**• If A and B are matrices of the same size and c and d are scalars, then (c + d)A = cA + dAc(A)d = cd(A) c(A + B) = cA + cB (cd)A = c(dA) Example: Find the product.**Matrix Multiplication**• If the number of columns of an m n matrix A is the same as the number of rows of an n p matrix B (i.e., both n). The element cij of the product matrix C = AB is found as follows: • Matrix AB will be an m p matrix.**Example**• Suppose A is a 3 4 matrix, while B is a 4 2 matrix. • a) Can the product AB be calculated? • b) If AB can be calculated, what size is it? • c) Can BA be calculated? • d) If BA can be calculated, what size is it?**must match**Size of AB Solutions • a) AB can be calculated, because the number of columns of A is equal to the number of rows of B. 3 4 4 2 • b) The product is a 3 2 matrix. • c) BA cannot be calculated, the number of columns and rows do not match. • d) Since BA cannot be calculated we cannot determine the size.**Multiply the Matrices**• For find each of the following. a) AB b) BA c) AC**Solution AB**• A is a 2 3 matrix and Bis a 3 2 matrix, so ABwill be a 2 2 matrix.**Solution BA**• Bis a 3 2 matrix and A is a 2 3 matrix, so BA will be a 3 3 matrix.**Solution AC**• The product AC is not defined because the number of columns of A, 3, is not equal to the number of rows of C, 2. • Note that AB BA. Multiplication of matrices is generally not commutative.**Properties of Matrix Multiplication**• If A, B, and C are matrices such that all of the following products and sums exist, then • (AB)C = A(BC) • A(B + C) = AB + AC • (B + C)A = BA + CA.**A matrix with m rows and n columns is called an m by n**matrix.**Note that in order for two matrices to be combined with**addition or subtraction, they must have the same number of rows and columns.**If k is a real number and A is an m by n matrix, the matrix**kA is**Let A denote an m by r matrix and let B denote an r by n**matrix. The productAB is defined as the m by n matrix whose entry in row i, column j is the product of the ith row of A and the jth column of B.**5.6**Matrix Inverses**Identity Matrices**• By the identity property for real numbers, a 1 = a and 1 a = a for any real number a. If there is to be a multiplicative identity matrix I, such that AI = A and IA = A for any matrix A, then A and I must be square matrices of the same size.**Identity Matrices**2 2 Identity Matrix If I2 represents the 2 2 identity matrix, then**Stating and Verifying the 3 3 Identity Matrix**Example: Let Give the 3 3 identity matrix I and show that AI = A. Solution: By the definition of matrix multiplication,**Multiplicative Inverses**• If A is an n n matrix, then its multiplicative inverse, written A1, must satisfy both AA1 = In and A1A = In • This means that only a square matrix can have a multiplicative inverse. Caution: Although for any nonzero real number a, if A is matrix, .**Finding an Inverse Matrix**• To obtain A1 for any n n matrix A for which A1 exists, follow these steps. Step 1 Form the augmented matrix where Inis then nidentity matrix.. Step 2 Perform row transformations on to obtain a matrix of the Step 3 Matrix B is A1.**Example**Find A1 if A = Solution: Use row transformations as follows. Step 1 Write the augmented matrix Step 2 Since 1 is already in the upper left hand corner, we begin by using row transformation that will result in 0 for the first element in the second row.**The following is done to obtain 0 as the first element in**the third row. The following is done to obtain 1 as the third element in the third row. The following is done to obtain 0 for the third element in the first row. Example continued R2 2R1 R3 R3 R1 R3 R3 + R1**The following is done to obtain 0 for the third element in**the second row. Step 3The last transformation shows that the inverse is Example continued R2 R3**Solution of the Matrix Equation AX = B**• If A is an n n matrix with inverse A1, X is an n 1 matrix of variables, and B is an n 1 matrix, then the matrix equation AX = B has the solution GX = A1B.**Solving Systems of Equations Using Matrix Inverses**Example: 3x + 4y = 5 5x + 7y = 9 Solution: To represent the system as a matrix equation, use one matrix for the coefficients, one for the variables, and one for the constants, as follows The system can then be written in matrix form as the equation AX = B, since**Solving Systems of Equations Using Matrix Inverses continued**To solve the system, first find A1. Then find A1B. Since X = A1B, • The final matrix shows the solution set of the system is {(1, 2)}**Continue performing row operations on the augmented matrix**until the matrix on the left is the identity matrix.**If a matrix represents the coefficients of a linear system**of equations, the inverse matrix can be used to solve the system.