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What does a biologist study ? the earth the weather c . living things d . only animals. Susie decided to test the effectiveness of 3 new fertilizers on her tomato plants. She decided to divide her garden into sections and apply a different fertilizer to each section.
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c. living things
d. only animals
What part of Susie’s experiment would be the independent variable?
a. the growth of the plants
b. the amount of water
c. the amount of light given to each plant
d. the type of fertilizer given to each plant
dioxide, and water into
a. vacuoles. c. proteins
b. sugar d. fat
a. a cell membrane.
a. the reproduction of cells.
b. a state of biological balance.
c. the transport of proteins against a concentration gradient.
d. the process of molecules spreading out evenly across an environment.
a. the third phosphate group breaks off from an ATP molecule.
b. they break down sucrose to glucose and fructose.
c. a third phosphate group is bonded to an ADP molecule.
d. ions are released into the bloodstream
The cell shown is probably an animal cell because
it has mitochondria
it does not have a cell wall
it has a cell membrane
d. it does not have a nucleus
a. a plant cell placed in plain distilled water b. a plant cell placed in salty water c. a plant cell placed in water with the same salt concentration as the cell d. a plant cell placed in sugar water
a. the solution is isotonic.
b. the solution is hypotonic.
c. the solution is hypertonic.
d. the solution is isometric.
13. allows molecules to pass by diffusion - C
14. may help to identify the cell - A
c. alcoholic fermentation
d. lactic acid fermentation.
a. glucose. c. lactic acid.
b. ribose. d. deoxyribose.
fermentation has occurred in her muscles?
a. she is short of breath c. her muscles are sore
b. she is hungry d. she is thirsty
a. C + O2 + H2O CO2 + HOH
b. 6CO2 + 6H2O C6H12O6 + 6O2
c. 6C + 6H2O C6H12O6
d. C6H12O6 6CO2 + 6H2O
a. E,C,F,A,D,B c. D,B,F,C,E,A
b. A,B,C,D,E,F d. D,A,F,C,E,B
chromosomes, how many chromosomes would
each sex cell have?
a. 60 c. 15
b. 30 d. 120
a. body cells and sex cells. c. sex cells only.
b. body cells only. d. only body cells of prokaryotes.
that has the genotype Bb?
a. homozygous c. inbred
b. heterozygous d. all of these
a. mutation c. replication
b. transcription d. pedigree
sequence AGTTCCACTTGA, which of the following
would represent the DNA sequence of that same
side in a new molecule if the original one is
a. AGTTCCACTTGA c. UCAAGGUGAACU
b. AGUUCCACUUGA d. TCAAGGTGAACT
a. gene c. codon
b. amino acid d. DNA molecule
a. translation. c. cell division.
b. replication. d. transcription.
30. The vacuole in an animal cell is much larger than those of plant cells. F
31. In photosynthesis, light energy is used to break down water into hydrogen and oxygen. T
32. Plants require oxygen in order to perform photosynthesis. F
33. Individuals must exhibit a trait in order for it to appear in their offspring. F
a. inbreeding. c. codominance.
b. polygenic inheritance. d. incomplete dominance.
a. tRNA c. glucose
b. mRNA d. DNA
a. ribose c. deoxyribose
b. phosphate d. guanine
figure on the diagram labeled “x”?
a. phosphate c. thymine
b. uracil d. cytosine
a. multiple alleles. c. sex-linked genes.
b. codominant alleles. d. polygenic inheritance
absorb infrared radiation and trap heat are
a. ozone c. greenhouse gases
b. carbon offsets d. CFC’s
a. producers c. consumers
b. herbivores d. omnivores
a. a tundra c. an estuary
b. a coral reef d. a grassland
a. temperate forest c. grassland
b. taiga d. tropical rain forest
a. decreases. c. stays the same.
b. increases. d. is totally depleted.
a. coyotes to grasses. c. mice to cats.
b. cats to mice. d. coyotes to cats.
a. low temperatures and much vegetation.
b. low temperatures and little vegetation.
c. high temperature and much vegetation.
d. high temperature and little vegetation.
a. engines burning carbon-based fuels
b. volcanic eruptions
d nuclear power plants