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Final Jeopardy PowerPoint Presentation
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Final Jeopardy

Final Jeopardy

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Final Jeopardy

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  1. Final Jeopardy Freezing Point Depression

  2. Final Jeopardy 25g/58.5g/mol = .43 mol .43 mol/.250Kg = 1.7 m ∆T = 1.86oC/m x 1.7m x (2) = -6.3oC What is the freezing point of a solution made by dissolving 25 grams of NaCl in 250 mL of water?

  3. $200 Kinetic Molecular Theory This theory discusses the movement of molecules in their various states

  4. $400 Boyles Law The pressure and volume of a gas are inversely related

  5. $600 The atmosphere What is the SI unit for pressure?

  6. $800 The pressure will also increase Gay-Lussac would say as the temperature of a gas increases at constant volume

  7. $1000 Combined Gas Law PV = PV T T

  8. $200 Evaporation Process by which liquids change into a gas

  9. $400 Sublimation Phase change from a solid directly to a liquid

  10. $600 Gas In which state do the molecules have the greatest kinetic energy?

  11. $800 Temperature remains constant What happens to temperature during a phase change

  12. $1000 Triple Point Point at which all three states of matter can co-exist

  13. $200 Sand Sand, alloys, soda, which is not homogeneous?

  14. $400 Electrolyte A solution capable of conducting electricity

  15. $600 Compounds that are similar chemically dissolve other compounds that are alike What does “likes dissolve likes” refer to?

  16. $800 2 Molar 4 moles of a solute is dissolved in 2 Liters of solution, what is the Molarity

  17. $1000 PbCl2 Pb2+(aq) + 2 Cl-(aq) Write the equation for the dissolution of PbCl2(s) in water

  18. $200 supersaturated A solution in which no more solute can be dissolved

  19. $400 FP depression and BP elevation Name two colligative properties

  20. $600 Change in temp., molal constant, molality Using the equation ΔT = kf x m Explain the symbols

  21. $800 1 molal NaCl b/c it is an electrolyte and gives you two particles per mole Which would boil at a higher temperature and why? 1 molal glucose or 1 molal NaCl

  22. $1000 5 M, (.5 moles/.100L) Math Question: What is the molarity of 20 grams of NaOH dissolved in 100 mL of water

  23. $200 Base pH greater than 7

  24. $400 Acid [H+ ] > [OH-]

  25. $600 pH = - log [H+] What does pH equal

  26. $800 Sulfuric Acid What is the name of H2SO4

  27. $1000 1 x 10-7 Math Question: If pH = 7, then what is the [OH-]

  28. $200 Arrhenius Definition Bases produce OH- in water solutions

  29. $400 Whose definiton states that Acids are proton donors

  30. $600 8.7 What is pOH if pH = 5.3

  31. $800 pH = 10 [H+] = 1 x 10-10 What is the pH?

  32. $1000 pH = 9 [H+] = 1 x 10-9 so pH = 9 If [OH-] = 1 x 10-5 What is the pH?

  33. $400 Temperature Average kinetic energy of the molecules =

  34. $800 Specific Heat Amount of heat required to raise 1 gram of a substance 1oC

  35. $1200 Is equal to heat lost by the material In calorimetry experiments the heat gained by water

  36. $1600 J = 25g x 8 oC x 4.18 J/goC How much heat is required to raise 25 grams of water from 22oC to 30oC? Specific Heat of water = 4.18 J/goC

  37. $2000 Products should be higher than reactants Come to the board and draw a reaction that is endothermic

  38. $400 Low energy and high entropy In nature reactions tend to go towards what 2 directions?

  39. $800 Randomness or disorder What does entropy mean?

  40. $1200 Reaction mechanism A multistep process for a chemical reaction is called

  41. $1600 Activation energy The energy hump a reaction needs to overcome is called

  42. $2000 Temperature, surface area, catalyst, nature of reactants Name three (3) factors that affect reaction rate.

  43. $400 Rate of the Forward reaction equals the rate of the reverse reaction Define chemical equilibrium

  44. $800 Ka = [CH3COO-] [H3O+] [CH3COOH] Write the equilibrium expression for the following; CH3COOH(aq) + H2O(l) CH3COO-(aq) + H3O(aq)

  45. $1200 A large Ka value A strong acid will have what kind of value for it’s Ka ?

  46. $1600 Left N2(g) + 3 H2(g)  2 NH3(g) + 92 kJ If heat is added the reaction will shift?