chapter 25 n.
Skip this Video
Loading SlideShow in 5 Seconds..
Chapter 25 PowerPoint Presentation
Download Presentation
Chapter 25

Loading in 2 Seconds...

play fullscreen
1 / 15

Chapter 25 - PowerPoint PPT Presentation

  • Uploaded on

Chapter 25. Capacitors. 25-2 Capacitor and Capacitance. A capacitor consists of two isolated conductors (the plates) with charges + q and - q. Its capacitance C is defined from q=CV Where V is the potential difference between the conductors. 25-3 Calculating the Capacitance.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
Download Presentation

PowerPoint Slideshow about 'Chapter 25' - ceana

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
chapter 25

Chapter 25


25 2 capacitor and capacitance
25-2 Capacitor and Capacitance
  • A capacitor consists of two isolated conductors (the plates) with charges + q and - q. Its capacitance C is defined from


Where V is the potential difference between the conductors.

25 3 calculating the capacitance
25-3 Calculating the Capacitance
  • To find the capacitance, we have to find the electric field E, then the potential difference V. Gauss Law is used

Parallel-Plate Capacitor

The plate area is A and the distance between the plates is d.


The Capacity of an Isolated Conductor

The isolated conductor is a sphere of conducting material which is isolated such that it keeps its charge. It is considered to be a spherical capacitor of an outer sphere with infinitely large radius b=∞

and substituting about b=infinity, and a=R, the radius of the inner sphere,we get


Sample Problem 25-1

In Fig. 25-7 a, switch S is closed to connect the uncharged capacitor of capacitance C =0.25 mF to the battery of potential difference V= 12V. The lower capacitor plate has thickness L=0.50 cm and face area A=2.0 x 10-4 m2, and it consists of copper, in which the density of conduction electrons is n= 8.49 x 1028 electrons/m3. From what depth d within the plate (Fig. 25-7b) must electrons move to the plate face as the capacitor becomes charged?


Sample Problem 25-2

  • Find the equivalent capacitance for the combination of capacitances shown in Fig a, across which potential difference V is applied. Assume C1 = 12.0 mF, C2 = 5.30 mF, and C3 = 4.50 mF.
  • The potential difference applied to the input terminals in Fig. a is V=12.5 V. What is the charge on C1?

Sample Problem 25-3

Capacitor 1, with C1 =3.55 mF, is charged to a potential difference Vo= 6.30 V using a 6.30 V battery. The battery is then removed, and the capacitor is connected as in the figure to an uncharged capacitor 2, with C2=8.95 mF When switch S is closed, charge flows between the capacitors. Find the charge on each capacitor when equilibrium is reached.

25 5 the energy stored in a capacitor
25-5 The Energy Stored in a Capacitor

The potential energy U stored in a capacitor due to holding the charge q, is given by


The energy density u

In case of the parallel plate capacitor, the potential energy per unit volume between the plates is given by


Sample Problem 25-5

  • An isolated conducting sphere whose radius R is 6.85 cm has a charge q = 1.25 nC.
  • How much potential energy is stored in the electric field of this charged conductor?
  • What is the energy density at the surface of the sphere?

The capacity of this spherical conductor is given by

and the potential energy is given by

The energy density u is given by