“Coupling” and “repulsion” - PowerPoint PPT Presentation

coupling and repulsion n.
Skip this Video
Loading SlideShow in 5 Seconds..
“Coupling” and “repulsion” PowerPoint Presentation
Download Presentation
“Coupling” and “repulsion”

Loading in 2 Seconds...

play fullscreen
1 / 57
Download Presentation
“Coupling” and “repulsion”
Download Presentation

“Coupling” and “repulsion”

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

  1. “Coupling” and “repulsion” http://www.ndsu.edu/instruct/mcclean/plsc431/linkage/linkage1.htm

  2. Back to Bateson and Punnett What is going on? What can explain this “repulsion and coupling”? Why are these two genes disobeying Mendel’s second law?

  3. Macular degeneration is a group of diseases characterized by a breakdown of the macula. The macula is the center portion of the retina that makes central vision and visual acuity possible. “Age-related maculopathy (ARM), also known as age-related macular degeneration (AMD), is the leading cause of irreversible vision loss in the elderly population in the USA and the Western world and a major public health issue. Affecting nearly 9% of the population over the age of 65, ARM becomes increasingly prevalent with age such that by age 75 and older nearly 28% of individuals are affected (1–6). As the proportion of the elderly in our population increases, the public health impact of ARM will become even more severe. Currently there is little that can be done to prevent or slow the progression of ARM (7).” http://hmg.oupjournals.org/cgi/content/full/9/9/1329#DDD140TB1

  4. How to screen for a polymorphism linked to, or directly causing, AMD? First, what’s the evidence that there is a genetic component to AMD? “Numerous studies have attempted to establish dietary and environmental risk factors that contribute to ARM; however, heredity has emerged as the primary determinant of ARM susceptibility (for a review see ref. 16). First-degree relatives of ARM patients are at between two and four times greater risk of developing ARM than the first-degree relatives of controls (17,18). Twin studies have consistently shown high levels of concordance of the disease among monozygous sibs and strongly support a genetic etiology (19–22).” http://hmg.oupjournals.org/cgi/content/full/9/9/1329#DDD140TB1

  5. How to screen for a polymorphism linked to, or directly causing, AMD? Second, how to find the locus? (aka “candidate region”) “We collected a set of 364 families (2129 individuals) containing relative pairs affected with ARM.” http://hmg.oupjournals.org/cgi/content/full/9/9/1329#DDD140TB1

  6. This effort led to chromosome 1q32

  7. Now what? Two SNPs showed the greatest linkage, and they lie in a 260 kb region. This stretch contains the complement H gene – CFH is a component of the innate immune system which regulates inflammation, which, in turn, is consistently implicated in AMD. “Resequencing revealed a polymorphism in linkage disequilibrium with the risk allele representing a tyrosine-histidine change at amino acid 402. This polymorphism is in a region of CFH that binds heparin and C-reactive protein. Individuals homozygous for the risk alleles have a 7.4-fold increased likelihood of AMD (95% CI 2.9 to 19).” Haines et al. Science 308: 419.

  8. Daiger Science 308: 362. Fig. 5.2

  9. Morgan Science 1911

  10. Morgan Science 1911

  11. Batrachoseps attenuatusCalifornia Slender Salamander

  12. F.A. Janssens

  13. Morgan’s observation of linkage One of these genes affects eye color (pr, purple, and pr+, red), and the other affects wing length (vg, vestigial, and vg+, normal). The wild-type alleles of both genes are dominant. Morgan crossed pr/pr · vg/vg flies with pr+/pr+ · vg+/vg+ and then testcrossed the doubly heterozygous F1 females: pr+/pr · vg+/vg × pr/pr · vg/vg .

  14. The data 1:1:1:1?! 

  15. These two loci do not follow Mendel’s second law because they are linked

  16. The data ?

  17. F.A. Janssens

  18. Recombination Frequency (Morgan’s data)

  19. Recombination frequency  a genetic map (Sturtevant’s data)

  20. Unit definition 1% recombinant progeny = 1 map unit = 1 centimorgan (cM) ~ 1 Mb (note: the latter applies to humans)

  21. Mapping By Recombination Frequency (Morgan’s data)

  22. The met protooncogene and the CFTR gene are 0.7 Mb apart on chr. 7. In 1000 meiotic events, how many gametes would you expect to find that have had a recombination event between the two genes?

  23. Problem 5.9 If the a and b loci are 20 m.u. apart in humans, and an AB/ab woman has a child with an ab/ab man, what is the probability that this child will be Ab/ab?

  24. If two genes, A and B, are 80 Mb apart on a human chromosome, what percentage recombinant gametes would you expect to be produced in an individual who is AB/ab?

  25. If genes are more than 50 map units apart, they behave as if they were unlinked.

  26. The chromosome as a “linkage group”

  27. Bridges (left) and Sturtevant in 1920.  G. Rubin and E. Lewis Science 287: 2216.

  28. Sturtevant 1961

  29. The three-point testcross From my perspective, the single most majestic epistemological accomplishment of “classical” genetics

  30. Reading Two chapters from Morgan’s book (III, on linkage, and V, on chromosomes). A short chapter from Sturtevant’s History of Genetics. Chapter 5, section 2.

  31. How to Map Genes Using a Three-Point Testcross • Cross two pure lines. • Obtain large number of progeny from F1. • Testcross to homozygous recessive tester. • Analyze large number of progeny from F2.

  32. v+/v+ · cv/cv · ct/ctv/v · cv+/cv+ · ct+/ct+.  v/v+ · cv/cv+ · ct/ct+  v/v · cv/cv · ct/ct.  P F1 Two Drosophila were mated: a red-eyed fly that lacked a cross-vein on the wings and had snipped wing edges to a vermilion-eyed, normally veined fly with regular wings. All the progeny were wild type. These were testcrossed to a fly with vermilion eyes, no cross-vein and snipped wings. 1448 progeny in 8 phenotypic classes were observed. Map the genes.

  33. 1. Rename and rewrite cross

  34. 2. Rewrite data Arrange in descending order, by frequency. NCOs DCOs

  35. 3. Determine gene order With the confusion cleared away, determine gene order by comparing most abundant classes (non-recombinant, NCO) with double-recombinant (least abundant, DCO), and figuring out, which one allele pair needs to be swapped between the parental chromosomes in order to get the DCO configuration. This one allele pair will be of the gene that is in the middle.

  36. 3b. Determine gene order

  37. 4. E and F

  38. 4b. F and N

  39. 4c. E and N

  40. 5. The map (ta-daaa!)