Breakout Question. Eg5 is a kinesin family member in Xenopus. To understand Eg5 function in vivo, cells are transfected with RNAi directed against this motor protein. The following images are obtained of mitotic cells. A) Describe the experiment.
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Eg5 is a kinesin family member in Xenopus. To understand Eg5 function in vivo, cells are transfected with RNAi directed against this motor protein. The following images are obtained of mitotic cells.
A) Describe the experiment.
B) What do the data tell you about the function of Eg5 in cells?
A) To determine the in vivo function of the kinesin protein Eg5 during metaphase, RNAi-mediated knockdown of Eg5 was performed and then DNA and microtubules were stained and assayed during metaphase. As a negative control, RNAi against a non-essential or non-expressed gene such as GFP is utilized.
B) Without Eg5, the microtubule spindle network is disorganized and chromosomes are no longer aligned at the middle of the cell. These data suggest that Eg5 plays a role in chromosome alignment and spindle orientation. Without proper spindle formation though, chromosomes will not align, thus this is likely the primary problem. More experiments need to be performed to distinguish primary or secondary nature of this effect.
(A) Explain wild type regulation of PDE and how the S-to-D mutation in PDE makes the cells insensitive to Adenylate Cyclase (AC) activation.
(B) Additionally, you observe that the levels of activated PKA are diminished in the mutant cells compared to wild type. Explain how the PDE mutation might affect PKA activation.
(A) Normally, when AC becomes active, it produces cAMP. The increased levels of cAMP induce activation of PKA. Active PKA phosphorylates multiple targets, one of which is PDE. The phosphorylation of PDE activates the enzyme, thus downregulating cAMP levels. Changing S-to-D mimics the phosphorylated form of PDE. The result of this mutation is the PDE enzyme will be perpetually active. When AC becomes active cAMP levels will increase, but the constitutively active PDE continually breaks it down.
(B) PKA activity is dependent on cAMP. Without cAMP, PKA will remain inactive. Constitutively active PDE will keep cAMP levels low, thus keeping PKA in an inactive form.
Sunburn acts upstream of receptor activation. The rationale for this conclusion is that activation of the Eph receptor can rescue the loss of sunburn, suggesting all downstream components of Eph RTK signaling are intact.
It is most likely the ligand for the Eph RTK
Double mutant genotypeIR-induced apoptosis (yes/no)
yin; Gain-of-function ced-9 (Bcl-2) No
yin; loss-of-function egl-1 (Bim, Bid) Yes
yang; gain-of-function ced-9 Yes
yang; loss-of-function egl-1 Yes
Based on the double mutant analysis, where in the apoptotic pathway are yin and yang?
yin is upstream of ced-9 as a ced-9 gain-of-function mutant prevents apoptosis in the yin mutant worms. yin is downstream or at the same level to egl-1 as a loss-of-function egl-1 mutant is rescued by the yin mutant.
yang must be downstream of egl-1 and ced-9 as IR-induced apoptosis is present regardless of the state of egl-1 or ced-9.