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# Geometry of R 2 and R 3 - PowerPoint PPT Presentation

Geometry of R 2 and R 3. Lines and Planes. Point-Normal Form for a Plane. Let P be a point in R 3 and n a nonzero vector. Then the plane that contains P that is normal to the vector n is given by the equation n . ( x - p ) = 0. Standard Form for a Plane.

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## PowerPoint Slideshow about ' Geometry of R 2 and R 3' - baker-lynch

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### Geometry of R2 and R3

Lines and Planes

Let P be a point in R3 and n a nonzero vector. Then the plane that contains P that is normal to the vector n is given by the equation

n.(x - p) = 0

Let n = (a, b, c) and x = (x, y, z) in the point-normal form we get the standard form of the equation of the plane

ax + by + cz = d

• Find the equation of the plane through the point (1, 2, 3) with normal n = (-3, 0, 1).

• Convert the equation 4x – 3y + 6z = 12 of the plane to point-normal form.

If P, Q, and R are three non-collinear points in a plane, then

n = (q – p) x (r – p)

and the equation is again n.(x - p) = 0.

Find the equation of the plane through the points (-1, 2, -4), (2, -3, 4) and (2, 1, -3).

Let P be a point and v a nonzero vector in R3.

Then the p + tv is parallel and equal in length to the vector tv.

Then the endpoint of p + tv must lie on the line determined by P and the endpoint of p + v.

So for any point X on the line through P and parallel to v is the end point of a vector of the form p + tv. Thus x(t) = p + tv the line through P and parallel to the v.

• Find the point-parallel form of the line through the point (2, -1, 3), parallel to v = (-1, 4, 1).

• Find the point-parallel form of the line through (-2, 3, 0) and (3,-1,-2).

• Find the point-parallel form of the line through (-3,1) and parallel to v = (4, -3).

Recall:

x = p + tv the line through P and parallel to the v.

Let x = (x, y, z), p = (p1, p2, p3) and v = (v1, v2, v3).

Then the parametric equation of the above line is

x(t) = p1 + tv1; y(t) = p2 + tv2; z(t) = p3 + tv3

• Find the parametric form of the line through (2, -1, 3), parallel to v = (-1, 4, 1).

• Find the parametric form of the line through (2, 4, 5), perpendicular to the plane 5x – 5y – 10z = 2

The line through P and Q is given by

x(t) = (1 – t)p + tq

Note that x(0) = p and x(1) = q.