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Motors: a System Approach

Motors: a System Approach. Kurt Heinzmann DEKA Research & Development Corp. January 2007. General Topics Example problems Problem formulation and analysis Manufacturers' torque curves and specification sheets Temperature rise Power loss in battery, wires and other components Gear ratio

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Motors: a System Approach

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  1. Motors: a System Approach Kurt Heinzmann DEKA Research & Development Corp. January 2007

  2. General Topics Example problems Problem formulation and analysis Manufacturers' torque curves and specification sheets Temperature rise Power loss in battery, wires and other components Gear ratio Review of motors from a previous Kit of Parts

  3. Background • Energy • Power • Power loss • Analysis • Test

  4. Energy • Work is energy. • Example: “effort” times “displacement” • Force is effort • Distance is displacement Power • Power is how fast work gets done. • Example: “effort” times “speed”

  5. Power • Power is a measure of how fast work gets done. • POWER = EFFORT x FLOW (speed) “EFFORT” • force • torque • pressure • voltage • thinking • “FLOW” • travel speed • rotating speed • flow of fluid • flow of electrons • doing

  6. Power Loss in the Mechanism • Some power from the motor is lost due to friction in the mechanism • Gears, belts, cables • Bearings, guides • Tires, balls, or other deformable items • Damage • Contamination • Power loss is heat

  7. Power required at the motor • Power at the motor = power required at the point of use + power lost in the mechanism • Power loss is heat

  8. Power loss in the motor • Power is lost in the motor due to friction, damping, and electrical resistance • Power loss is heat. Overloading will cause excessive temperature rise. Use appropriate gear ratio.

  9. Analysis • Example problems • Important motor parameters • Motor model revised to include other losses (wires, battery, switches, fuses, etc.) • Gear ratio

  10. Basic Theory • Torque is rotating EFFORT, speed is rotating FLOW • Torque = force x radius • Voltage is electrical EFFORT, current is FLOW of electrons • Power = EFFORT x FLOW • Mechanical power P(mech) = torque x speed • Electrical power P(elec) = voltage x current

  11. International System (SI) of units Units, Conversions Prefixes: m = milli- = one thousandth (mm, mNm) k = kilo- = one thousand (km, kW)

  12. Why use SI units? • Fewer mistakes than when using U.S. Customary units • A motor converts electrical power to mechanical power. • If we express electrical power and mechanical power in the same units (watts), we know what’s happening at both ends of the motor, and inside it. • Many are named after famous scientists • Advice: Convert each parameter to SI units before doing any other calculation. • Consolation: you can always convert back to US customary units.

  13. Problem 1 Accelerate to a speed

  14. Problem 1 Mass: m = 150 lb. = 68 kg Speed: v = 6 ft./s = 1.8 m/s Acceleration: a = 1.8 m/s per second = 1.8 m/s2 Force = m x a = 68 kg x 1.8 m/s2 = 122 N Force from each wheel: F = 122 N / 2 = 61 N Power: P = F x v = 61 N x 1.8 m/s = 110 W

  15. Problem 2 Lift a weight a distance within a time

  16. Problem 2 Gravitational constant: g = 9.8 m/s2 Weight: W = 14 lb. = 61 N Force: F = W = 61 N Height: h = 6 ft. = 1.8 m Time: t = 4 s Speed: v = 1.8 m/ 4 s = 0.45 m/s Power: P = F x v = 61 N x 0.45 m/s = 28 W

  17. Basic Motor Theory

  18. Electrical Components

  19. Basic Motor Theory

  20. Basic Motor TheoryImportant motor parameters • Applied voltage ( V ) • Stall torque (stall ) • Stall current (istall ) • Free speed (free ) • Resistance ( R )

  21. Fisher-Price Motor

  22. Fisher-Price Motor (2005) From data sheet: stall = 0.65 Nm Stall torque Stall current Free speed Reference voltage V = 12 V istall = 148 A free = 2513 rad/s Calculate: Resistance R = 12 V /148 A = 0.081 

  23. Fisher-Price Motor – Current(For detailed analysis, see " Getting the Most From Your Motors" by Kurt Heinzmann, 2006)

  24. Fisher-Price Motor - Speed

  25. Fisher-Price Motor - Power output

  26. Fisher-Price Motor - Input Power

  27. Fisher-Price Motor - Power loss

  28. Fisher-Price Motor - Efficiency

  29. Motor performance based on data sheet Peak power occurs when torque = stall/ 2, and when speed = free/ 2

  30. Real World: Power loss 14 AWG wire: 3.0 m/ft. 12 AWG wire: 1.9 m/ft. 10 AWG wire: 1.2 m/ft. 6 AWG wire: 0.5 m/ft. (Copper at 65 °C)

  31. Resistance of electrical system components

  32. Simplified electrical system model

  33. System model Additional resistance reduces stall torque proportionally. Divide the stall torque on the torque/speed diagram by the factor Rsystem/Rmotor(nominal) Fisher-Price: stall= 0.65 Nm/2.3 = 0.28 Nm

  34. Performance of the system compared with motor performance based on data sheet

  35. CIM motor (also known as Chiaphua and Atwood)

  36. CIM motor data and curves Stall torque stall = 347 oz-in = 2.45 Nm Stall current istall = 114 A Free speed free = 5342 rpm = 560 rad/s Free current ifree= 2.4 A Rsystem/Rmotor(nominal) = 2.1

  37. Comparison of power available from Fisher-Price Motor and CIM motor

  38. Mechanical Components Gear ratio Ng = in/ out Gear efficiency ηg= Pout/Pin out= in/ Ng; out = ηg x Ng x in

  39. "Gear" ratio: Mechanical power transmission efficiency is important • Spur gears: 90% per pair • Worm and gear: 10%-60% • Nut on a screw: 10%-60% • Twist cables: 30%-90% • Chain: 85%-95% • Wire rope (cables): up to 98% • Rack and pinion 50%-80%

  40. System with gearbox

  41. Gear ratio example Fisher-Price motor with gear reduction • Given: • Gear ratio Ng = 4.6:1 • Gear efficiency ηg= 90% • Calculate: • Output torque out = ηg x Ng x in = 4.14 x in • Output speed out = motor/ Ng = 0.217 x motor

  42. Is the little motor/gearbox combination the same as the big motor?

  43. The big (CIM) motor will not heat up as fast as the small motor, because it contains more material.

  44. Problem 1( v = 1.8 m/s; F = 61 N) Motor speed: motor = free /2 = 559 rad/s/2 = 280 rad/s We wish to try 8" wheels: Rwheel = 4" = 0.1 m Wheel speed: motor = v / Rwheel = (1.8 m/s)/(0.1 m) = 18 rad/s Gear ratio: Ng = motor /wheel = (280 rad/s)/(18 rad/s) = 16 Check torque and propulsion force: Usual limit per stage is 5:1 - need two stages. Gear efficiency: ηg = 0.9 x 0.9 = 0.81 Wheel torque: wheel = ηg xNg x stall /2 = 0.81 x 16 x 1.2 Nm/2 = 7.8 Nm Force: F = wheel /Rwheel = (7.8 Nm)/(0.1 m) = 78 N (OK)

  45. Just right

  46. Problem 2 ( v = 0.45 m/s; F = 61 N) We wish to try a screw with Fisher-Price motor. Screw speed = motor speed: screw = free / 2 = 2513 rad/s/2 = 1256 rad/s screw =(1256 rad/s)/(2π rad/revolution) = 200 rev./s Screw pitch: p = v/screw = (0.45 m/s)/(200 rev./s) = 0.00225 m/rev. = 0.00036 m/rad (11 threads per inch). Check torque and force: Assume screw efficiency = 20% Torque: screw = motor = stall / 2 = 0.28 Nm/2 = 0.14 Nm Force: F = ηg xscrew / p = (0.2 x 0.14 Nm)/(0.00036 m/rad) = 78 N (OK)

  47. Summary of motors in the 2005 Kit of Partssorted by peak output power

  48. Comparison of motors in the 2005 Kit of Parts

  49. Keep batteries charged. Delivered capacity was only one third of rated capacity.

  50. Conclusion • Proper motor selection, good wiring, an appropriate gear ratio, aligned mechanical components, and a full battery will keep you alive in the heat of the battle. • Power loss is often a significant fraction of the power used to do work. Include all losses in analysis. • Analyze, but test, too! • Have fun

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