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Lesson 6

Harold Vance Department of Petroleum Engineering. Drilling System - Pressure Loss Calculations . Read:MI Chapter 5Multimedia Program

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Lesson 6

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    1. Lesson 6 Drilling System - Pressure Loss Calculations

    2. Harold Vance Department of Petroleum Engineering Drilling System - Pressure Loss Calculations Read: MI Chapter 5 Multimedia Program # 3 & 4

    3. Harold Vance Department of Petroleum Engineering Drilling System - Pressure Loss Calculations Hydrostatics Buoyancy Flow through pipes and annuli Flow path Pressure loss calculations

    4. Harold Vance Department of Petroleum Engineering Hydrostatics Liquid columns Gas columns Complex Columns

    5. Harold Vance Department of Petroleum Engineering Hydrostatics in Liquid Columns 1 cu.ft. of water 62.4 lb/cuft Area = 12”x12” =144 sq.in 62.4 / 144 = .433 psi/ft .433psi/ft/8.333 ppg 0.051962 ~0.052 psi/ft/ppg HSP = 0.052 x MW x TVD

    6. Harold Vance Department of Petroleum Engineering Hydrostatics in Liquid Columns

    7. Harold Vance Department of Petroleum Engineering Hydrostatics in Gas columns

    8. Harold Vance Department of Petroleum Engineering Hydrostatics in Complex Columns

    9. Harold Vance Department of Petroleum Engineering Hydrostatics in Complex Columns

    10. Harold Vance Department of Petroleum Engineering Equivalent Density Concept EMW = Pressure/ (0.052 x TVD) Equivalent mud weight is the total pressure imposed at a given depth expressed in ppg equivalent e.g. 5946/ (0.052 x 10000) = 11.43 ppg

    11. Harold Vance Department of Petroleum Engineering Buoyancy The net effect of hydraulic pressure acting on a foreign material immersed in the well fluid.

    12. Harold Vance Department of Petroleum Engineering Buoyancy F1 = p1A = 0.052 x MW x D x A = Downward force F2 = p2A = 0.052 x MW (D + h)A = Upward Force The resultant buoyant force: Fbo = F2 - F1 = 0.052 x MW x A (D+h-D) = 0.052 x MW x A x h

    13. Harold Vance Department of Petroleum Engineering Buoyancy Fbo = Weight of a the fluid displaced. The effective weight of the submerged object is: We = W - Fbo = W[1-(rm/rs)]

    14. Harold Vance Department of Petroleum Engineering Flow through pipes and annuli

    15. Harold Vance Department of Petroleum Engineering Flow through pipes and annuli

    16. Harold Vance Department of Petroleum Engineering Flow path

    17. Harold Vance Department of Petroleum Engineering Pressure loss calculations

    18. Harold Vance Department of Petroleum Engineering Turbulence - Newtonian Onset of turbulence occurs at a Reynold’s number of 2100 Table 4.6 gives equations for Reynold’s number

    19. Harold Vance Department of Petroleum Engineering Friction Factor - Newtonian

    20. Harold Vance Department of Petroleum Engineering Turbulence -Bingham Plastic

    21. Harold Vance Department of Petroleum Engineering Turbulence - Power Law

    22. Harold Vance Department of Petroleum Engineering Velocity & Flow Behavior Parameters

    23. Harold Vance Department of Petroleum Engineering Turbulence Criteria

    24. Harold Vance Department of Petroleum Engineering Laminar Flow Frictional Pressure

    25. Harold Vance Department of Petroleum Engineering Turbulent Flow Frictional Pressure

    26. Harold Vance Department of Petroleum Engineering

    27. Harold Vance Department of Petroleum Engineering Example 4.21 Given: MW = 9.0 ppg Newtonian fluid Viscosity = 15 cp Depth = 10,000’ Hole size = 7” DP size = 5” q = 80 gpm Required: Static and circulating BHP (assume Laminar)

    28. Harold Vance Department of Petroleum Engineering Solution Static BHP 0.052 x 9 x 10,000 = 4680 psig

    29. Harold Vance Department of Petroleum Engineering Solution Frictional pressure

    30. Harold Vance Department of Petroleum Engineering Solution Circulating BHP = HSP + Friction = 4680 + 51 = 4731 psig.

    31. Harold Vance Department of Petroleum Engineering Turbulence? Critical Reynolds number = 2100 What is the critical velocity

    32. Harold Vance Department of Petroleum Engineering Critical Velocity?

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