- 427 Views
- Uploaded on

Download Presentation
## PowerPoint Slideshow about 'Chapter 5 Bipolar Junction Transistors' - Pat_Xavi

**An Image/Link below is provided (as is) to download presentation**

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript

Chapter Goals

- Explore the physical structure of bipolar transistor
- Study terminal characteristics of BJT.
- Explore differences between npn and pnp transistors.
- Develop the Transport Model for bipolar devices.
- Define four operation regions of the BJT.
- Explore model simplifications for the forward active region.
- Understand the origin and modeling of the Early effect.
- Present a PSPICE model for the bipolar transistor. Discuss bipolar current sources and the current mirror.

Physical Structure

- The BJT consists of 3 alternating layers of n- and p-type semiconductor called emitter (E), base (B) and collector (C).
- The majority of current enters collector, crosses the base region and exits through the emitter. A small current also enters the base terminal, crosses the base-emitter junction and exits through the emitter.
- Carrier transport in the active base region directly beneath the heavily doped (n+) emitter dominates the i-v characteristics of the BJT.

Transport Model for the npn Transistor

- Base-emitter voltage vBE and base-collector voltage vBC determine the currents in the transistor and are said to be positive when they forward-bias their respective pn junctions.
- The terminal currents are the collector current(iC ), the base current (iB) and the emitter current (iE).
- The primary difference between the BJT and the FET is that iB is significant, while iG = 0.

- The narrow width of the base region causes a coupling between the two back to back pn junctions.
- The emitter injects electrons into base region; almost all of them travel across narrow base and are removed by collector.

npn Transistor: Forward Characteristics

Base current is given by

Emitter current is given by

Forward transport current is

IS is saturation current

In this forward active operation region,

VT = kT/q =0.025 V at room temperature

npn Transistor: Reverse Characteristics

is reverse current gain

Base currents in forward and reverse modes are different due to asymmetric doping levels in the emitter and collector regions.

Emitter current is given by

Reverse transport current is

Base current is given by

npn Transistor: Complete Transport Model Equations for Any Bias

The first term in both the emitter and collector current expressions gives the current transported completely across the base region.

Symmetry exists between base-emitter and base-collector voltages in establishing the dominant current in the bipolar transistor.

pnp Transistor: Operation

- The voltages vEB and vCB are positive when they forward bias their respective pn junctions.
- Collector current and base current exit the transistor terminals and emitter current enters the device.

pnp Transistor: Forward Characteristics

Base current is given by:

Emitter current is given by:

Forward transport current is:

pnp Transistor: Reverse Characteristics

Base current is given by:

Emitter current is given by:

Reverse transport current is:

Circuit Representation for Transport Models

In the npn transistor (expressions analogous for the pnp transistors), total current traversing the base is modeled by a current source given by:

Diode currents correspond directly to the 2 components of base current.

i-v Characteristics Bipolar Transistor: Common-Emitter Output Characteristics

For iB=0, the transistor is cutoff. If iB >0, iC also increases.

For vCE > vBE, the npn transistor is in the forward active region, iC = bFiB is independent of vCE..

For vCE< vBE, the transistor is in saturation.

For vCE< 0, the roles of collector and emitter are reversed.

i-v Characteristics of Bipolar Transistor: Common-Emitter Transfer Characteristic

This characteristic defines the relation between collector current and base-emitter voltage of the transistor.

It is almost identical to the transfer characteristic of a pn junction diode.

Setting vBC =0 in the collector-current expression:

Junction Breakdown Voltages

- If reverse voltage across either of the two pn junctions in the transistor is too large, the corresponding diode will break down.
- The emitter is the most heavily doped region, and the collector is the most lightly doped region.
- Due to these doping differences, the base-emitter diode has a relatively low breakdown voltage (3 to 10 V). The collector-base diode is typically designed to break down at much larger voltages.
- Transistors must therefore be selected in accordance with the possible reverse voltages in circuit.

Simplified Forward-Active Region Model

In the forward-active region, the base-emitter junction is forward-biased and the base-collector junction is reverse-biased. vBE > 0, vBC < 0

If we assume that

then the transport model terminal current equations simplify to:

The BJT is often considered a current-controlled current source, although fundamental forward active behavior suggests a voltage-controlled current source.

Simplified Circuit Model for Forward-Active Region

- Current in the base-emitter diode is amplified by the common-emitter current gain bF and appears at the collector
- The base and collector currents are exponentially related to the base-emitter voltage.
- The base-emitter diode is often replaced by a constant voltage drop model (VBE = 0.7 V), since it is forward-biased in the forward-active region.

Simplified Forward-Active Region Model (Analysis Example)

- Problem: Find Q-point
- Given data: bF = 50, VBC =VB - VC= -9 V
- Assumptions: Forward-active region of operation, VBE = 0.7 V
- Analysis:

Biasing for BJT

- The goal of biasing is to establish a known Q-point, which in turn establishes the initial operating region of transistor.
- In BJT circuits, the Q-point is represented by (VCE, IC) for the npn transistor or (VEC, IC) for the pnp transistor.
- In general, during circuit analysis, we use a simplified mathematical relationships derived for the specified operation region of the transistor.
- The practical biasing circuits used with BJTs are:
- The Four-Resistor Bias network
- The Two-Resistor Bias network

Four-Resistor Bias Network for BJT (Check Analysis)

- All calculated currents > 0, VBC = VBE - VCE = 0.7 - 4.32 = - 3.62 V
- Hence, the base-collector junction is reverse-biased and the assumption of forward-active region operation is correct.
- The load-line for the circuit is:

The two points needed to plot the load line are (0, 12 V) and (314 mA, 0). The resulting load line is plotted on the common-emitter output characteristics for IB= 2.7 mA.

The intersection of the corresponding characteristic with the load line determines the Q-point.

Four-Resistor Bias Network for BJT: Design Objectives

- From the BE loop analysis, we know that
- This will imply that IB << I2 so that I1 = I2 to good approximation in the base voltage divider. Then the base current doesn’t disturb the voltage divider action, and the Q-point will be approximately independent of base voltage divider current.
- Also, VEQ is designed to be large enough that small variations in the assumed value of VBE won’t have a significant effect on IB.
- Base voltage divider current is limited by choosing

This ensures that power dissipation in base bias resistors is < 17 % of the total quiescent power consumed by the circuit, while I2 >> IB.

for

Four-Resistor Bias Network for BJT: Design Guidelines

- Choose I2 = IC/5. This means that (R1+R2) = 5VCC/IC .
- Let ICRC =IERE = (VCC - VCE)/2. Then RC = (VCC - VCE)/2IC; RE =aFRC
- If REQ<<(bF+1)RE, then IERE = VEQ - VBE.
- Then (VCC - VCE)/2 = VEQ - VBE, or VEQ = (VCC - VCE + VBE)/2.
- Since VEQ = VCCR1/(R1 +R2) and (R1+R2) = 5VCC/IC,
- Then R2 = 5VCC/IC - R1.
- Check that REQ<<(bF+1)RE. If not, adjust bullets 1 and 2 above.
- Note: In the LabVIEW bias circuit design VI (NPNBias.vi), bullet 1 is called the “Base Margin” and bullet 2 is called the “C-E V(oltage) Drops”.

Two-Resistor Bias Network for BJT: Example

- Problem: Find the Q-point for the pnp transistor in the 2-resistor bias circuit shown below.
- Given data: bF = 50, VCC = 9 V
- Assumptions: Forward-active region operation with VEB = 0.7 V
- Analysis:

Q-point is : (6.01 mA, 2.87 V)

BJT PSPICE Model

- Besides the capacitances which are associated with the physical structure, additional model components are: diode current iS, capacitance CJS, related to the large area pn junction that isolates the collector from the substrate and one transistor from the next.
- RB is the resistance between external base contact and intrinsic base region.
- Collector current must pass through RC on its way to the active region of the collector-base junction.
- RE models any extrinsic emitter resistance in the device.

BJT PSPICE Model -- Typical Values

Saturation Current = 3 e-17 A

Forward current gain = 100

Reverse current gain = 0.5

Forward Early voltage = 75 V

Base resistance = 250 W

Collector Resistance = 50 W

Emitter Resistance = 1 W

Forward transit time = 0.15 ns

Reverse transit time = 15 ns

Minority Carrier Transport in Base Region

- With a narrow base region, minority carrier density decreases linearly across the base, and the Saturation Current (NPN) is:

where

NAB = the doping concentration in the base

ni2 = the intrinsic carrier concentration (1010/cm3)

nbo = ni2 / NAB

Dn = the diffusivity = (kT/q)mn

- Saturation current for the PNP transistor is:
- Due to the higher mobility (m) of electrons compared to holes, the npn transistor conducts higher current than the pnp for equivalent doping and applied voltages.

Diffusion Capacitance

- For vBE and hence iC to change, charge stored in the base region must also change.
- Diffusion capacitance in parallel with the forward-biased base-emitter diode produces a good model for the change in charge with vBE.
- Since transport current normally represents collector current in the forward-active region,

Early Effect and Early Voltage

- As reverse-bias across the collector-base junction increases, the width of the collector-base depletion layer increases and the effective width of base decreases. This is called “base-width modulation”.
- In a practical BJT, the output characteristics have a positive slope in the forward-active region, so that collector current is not independent of vCE.
- “Early” effect: When the output characteristics are extrapolated back to where the iC curves intersect at common point, vCE = -VA (Early voltage), which lies between 15 V and 150 V.
- Simplified F.A.R. equations, which include the Early effect, are:

BJT Current Mirror

- The collector terminal of a BJT in the forward-active region mimics the behavior of a current source.
- Output current is independent of VCC as long as VCC ≥ 0.8 V. This puts the BJT in the forward-active region, since VBC ≤ - 0.1 V.
- Q1 and Q2 are assumed to be a “matched” pair with identical IS, bFO, and VA,.

BJT Current Mirror (continued)

With an infinite bFO and VA (ideal device), the mirror ratio is unity. Finite current gain and Early voltage introduce a mismatch between the output and reference currents of the mirror.

BJT Current Mirror: Example

- Problem: Find output current for given current mirror
- Given data: bFO = 75, VA = 50 V
- Assumptions: Forward-active operation region, VBE = 0.7 V
- Analysis:

BJT Current Mirror: Altering the Mirror Ratio

where ISO is the saturation current of a BJT with one unit of emitter area: AE =1(A). The actual dimensions of A are technology-dependent.

The Mirror Ratio of a BJT current mirror can be changed by simply changing the relative sizes of the emitters in the transistors. For the “ideal” case, the Mirror Ratio is determined only by the ratio of the two emitter areas.

BJT Current Mirror: Output Resistance

- A current source using BJTs doesn’t have an output current that is completely independent of the terminal voltage across it, due to the finite value of Early voltage. The current source seems to have a resistive component in series with it.
- Ro is defined as the “small signal” output resistance of the current mirror.

Download Presentation

Connecting to Server..