Given

1. p.244ex4 G SAS. Steps 1,3,4 E Reflex. Prop of Given H F Alt. Int. <s Thm. Given

2. J M p.246ex4 K L Reflex. Prop of ≅ Given Given SAS Steps 1,2,3 <JKL≅<MLK

3. p.244 ex 4 B C A D Given Given Alt. Int. <s Thm. SAS Steps 3,2,4 Reflexive Prop of ≅

4. p.247: 21 Given: <ZVY≅<WYV, <ZVW≅<WYZ,VW≅YZ V W Prove: X Y Z <ZVY≅<WYV, <ZVW≅<WYZ m <ZVY + m <ZVW = m <WYV + m <WYZ m <ZVY = m <WYV, m <ZVW = m <WYZ <WVY≅ <ZYV Given Def. of ≅ Def. of ≅ <Add. Post Given Reflex. Prop of ≅ <Add. Prop of = SAS, Steps 6,5,7 m<WVY = m<ZYV

5. Determine if you can use ASA to prove the triangles congruent. Explain. No, no included side

6. A p. 246:13 Given: B is the midpoint of D C B Given B is the mdpt of DC Given Def. Mdpt. SAS Steps 2,4,5 Reflex. Prop of ≅ <ABD and <ABC are right <s <ABD≅<ABC

7. X Determine if you can use ASA to prove ΔUVX≅ΔWVX. Explain. p.253ex2 W U V given Def. of Linear Pair <WVX ≅ <UVX <WVX is a right angle <UXV ≅ <WXV Reflex. Prop given

8. Given: What is the measure of y? l 1000 y m

9. p.253ex2 Determine if you can use ASA to prove ΔNKL≅ΔLMN. Explain. Reflex. Prop K L <KLN≅<MNL By Alt. Int. <s Thm, N M No other congruence relationships can be determined, so ASA cannot be applied.

10. p.255ex4 Determine is you can use the HL Congruence Theorem to prove the triangles congruent. If not, tell what else you need to know. Yes No, need the hyp ≅ Yes Seg. CB ≅ Seg. CB, by the Reflexive Prop. Since <ABC and <DCB are rt <s, ΔABC and ΔDCB are rt triangles. It is given that segment AC ≅ segment DB. ΔABC≅ΔDCB by HL.

11. L p.254ex3 Given: <G≅ <K, <J≅<M, HJ≅LM Prove: ΔGHJ≅ΔKLM H ΔGHJ ≅ ΔKLM K M G J Given Given ASA Steps 1,3,2 Third <s Thm <H ≅ <L <G ≅ <K, <J ≅ <M

12. p.254ex3 Use AAS to prove the triangles congruent. Given: <X ≅ <V, <YZW ≅ <YWZ, Y Prove: ΔXYZ≅ΔVYW X Z W V <X ≅ <V <YZX ≅ <YWV <YZW ≅ <YWZ Given AAS ≅XYZ ≅ ΔVYW ≅ Supps Thm Given Given Def. of Supp <s Def. of Supp <s <XZY is supp to <YZW <YWX is supp to <VWY

13. p. 257: 13 A F B Given: Prove: E C D Rt. < ≅Thm AAS Given Given Given

14. p.257:15 Given: E is a midpoint of Segments AD and BC Prove: Triangles ABE and DCE are congruent A B E C D <A and <D are rt angles Given Given HL Rt. <s Thm Def. Rt Δs Def. of mdpt E is mdpt of Segs AD, BC

15. p.258: 22 A B Given: Prove: E D C AAS Given Vert. <s Thm Alt. Int. <s Thm Given

16. p. 258: 23 J Given: K M Prove: L Given Rt.<s Thm Given Def. of Perpendicular AAS

17. B p.259q4 Given: D Prove: A C E F G Def. of Supp <s Given ASA Given <BAC is supp of <FAB; <DEC is supp of <GED ≅ Supp Thm

18. Given: Use CPCTC Prove: E D G F Converse of Alt. Int. <s Thm Given Reflex. Prop of ≅ Given CPCTC SAS Alt. Int. <s Thm

19. p.261ex3b N Given: O Use CPCTC Prove: M P Alt. Int. <s Thm. AAS CPCTC Conv. Alt. Int. <s Thm Reflex. Prop ≅ Given

20. C Given: Use CPCTC B Prove: A D Given SSS Reflex. Prop of ≅ CPCTC Def. of < Bisector

21. p.263: 8 Given: M is the midpoint of Q R Prove: Use CPCTC M P S Def. of mdpt CPCTC Given SAS Vert <s Thm

22. W p.263: 9 X Given: Use CPCTC Prove: Z Y CPCTC SSS Reflex. Prop ≅ Given

23. p.263: 10 Given: G is the midpoint of E G is the midpoint of Use CPCTC Through any 2 points there is exactly 1 line Prove: 1 2 Given ≅ Supp. Thm F H G SSS Reflex. Prop of ≅ CPCTC Draw Given Def. of ≅ Def. of mdpt FG = HG

24. p.263: 11 Given: L Use CPCTC Prove: M is the midpoint of J CPCTC K M Given Reflex. Prop of ≅ SAS Given Def. of < bisector M is the midpoint of Def. of mdpt

25. p.263:14 Given: ΔQRS is adjacent to ΔQTS. Prove: ΔQRS is adjacent to ΔQTS. Def. of bisect AAS Given CPCTC Def. of < bisect Reflex. Prop of ≅

26. p.263: 15 Given: with E the midpoint of Use CPCTC Prove: Conv. of Alt. Int. <s Thm SAS Given CPCTC Def. of mdpt Vert <s Thm E is the mdpt. of

27. p.264:19 P Q Given: PS = RQ, m<1 = m<4 3 4 Prove: m<3 = m<2 Use CPCTC 1 2 S Def. of Perpendicular R Reflex. Prop of ≅ Def. of rt triangle Def of ≅ m<1 = m<4 CPCTC PS = RQ m<3 = m <2 Given Given SAS Def. of ≅