1 / 57

SOLUTIONS

SOLUTIONS. TOPICS. Solution Formation Solubility Solution concentration. STANDARDS ADDRESSED. 6. Solutions are homogeneous mixtures of two or more substances. As a basis for understanding this concept: a. Students know the definition of solute and solvent

ronli
Download Presentation

SOLUTIONS

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. SOLUTIONS

  2. TOPICS Solution Formation Solubility Solution concentration

  3. STANDARDS ADDRESSED 6. Solutions are homogeneous mixtures of two or more substances. As a basis for understanding this concept: a. Students know the definition of solute and solvent b. Students know how to describe the dissolving process at the molecular level by using the concept of random molecular motion c. Students know temperature, pressure, and surface area affect the dissolving process d. Students know how to calculate the concentration of a solute in terms of grams per liter, molarity, parts per million, and percent composition.

  4. OBJECTIVE • By the end of the lesson, the student will: • Understand the dissolving process at the molecular level. • Understand how the structure of the water molecule allows it to dissolve many substances • Know the factors which influence: • solubility and why • dissolving rate and why • Know how to calculate the concentration of a solution

  5. SOLUTION FORMATION Solution: a homogeneous mixture of two or more substances Solvent: a substance which dissolves another substance Solute: the dissolved particles; whatever is being dissolved

  6. Solution Formation Vocab: • Soluble: a substance that dissolves in a solvent • Insoluble: a substance that does not dissolve in a solvent

  7. Examples of Solutions • Gas in Liquid: • Carbonic Acid (carbonation): CO2 in H2O • Liquid in Liquid • Vinegar: Acetic Acid in water • Solid in Solid • Brass: copper and zinc

  8. Animation: Dissolving Process • http://www.youtube.com/watch?v=EBfGcTAJF4o(53 sec) • http://www.youtube.com/watch?v=CLHP4r0E7hg&feature=related (42 sec) • http://www.youtube.com/watch?v=xdedxfhcpWo&feature=related (1:35)

  9. The dissolving process at the molecular level:

  10. Let’s look at the structure of the water molecule

  11. The structure of the water molecule creates a polar molecule due to the differences in electronegativities of the oxygen and hydrogen atoms. • Partial negative charge on the oxygen attracts the partial positive charge on the neighboring molecule. Molecules arrange themselves so as to have opposite charges aligned, pulling it away from its ‘structure’, “one ion or molecule at a time”

  12. Dissolving Process

  13. DISSOLVING PROCESS: • Once released, the ions are surrounded by water molecules. • The dissolving process is reversible • The dissolved solute moves around in the solution and when it comes into contact with un-dissolved solute particles it re-crystallizes, meaning it returns to the solid state. And the process repeats itself. • NaCl Na+(aq) + Cl- (aq)

  14. Saturation When the rates of the dissolving and recrystallization become the same, the solution is saturated at that temperature. A dynamic equilibrium is reached, meaning the rate of the forward reaction is the same as the reverse reaction.

  15. FACTORS AFFECTING DISSOLVING RATE • Where does dissolving occur? • On the surface of a substance • To increase dissolving rate, contact between solvent and solute must increase • 3 common ways to increase the collisions between solute and solvent • Temperature • Amount of Surface Area Exposed • Agitation

  16. Temperature • Temperature: raising the temperature increases the kinetic energy of the particles, resulting in more frequent and forceful collisions.

  17. Amount of Surface Area Exposed • Amount of Surface Area Exposed: breaking the solute into smaller pieces increases its surface area. A greater surface area allows more collisions to occur and therefore, faster dissolving

  18. Agitation (mixing, stirring, etc.) • Agitation: stirring moves dissolved solute particles away from the contact surfaces more quickly and thereby allows new collisions between solute and solvent particles to occur. Without stirring, solvated particles move away from the contact areas slowly.

  19. SOLUBILITY the maximum amount of solute that will dissolve in a given amount of solvent at a specified temperature and pressure

  20. 3 Types of Solutions Saturated solution Unsaturated solution Supersaturated solution

  21. Saturated solution: contains the maximum amount of solute. You cannot dissolve any more solute in the solvent.

  22. Unsaturated solution: contains less than the maximum amount of solute. You can dissolve more solute in the solvent.

  23. Supersaturated solution contains more than the normal maximum amount of solute. This is usually achieved by heating the solution in order to dissolve more solute, then the solution is cooled. This makes a supersaturated solution. (ie.Rock candy; hot mineral springs)

  24. Supersaturated Solutions STALAGMITES ROCK CANDY

  25. 3 Factors Affecting Solubility • 1. Temperature: many substances are more soluble at high temperatures than low temperatures. Exception: Gases

  26. Solubility of Gases with Increased Temperature Solubility of gases decreases As Temperature increases,

  27. Pressure affect on gases 2. Pressure: • affects the solubility of gaseous solutes. The solubility of a gas in any solvent increases as the pressure above the solution increases

  28. 3 Factors Affecting Solubility • 2. Pressure: affects the solubility of gaseous solutes. The solubility of a gas in any solvent increases as the pressure above the solution increases

  29. 3 Factors Affecting Solubility • 2. Pressure: affects the solubility of gaseous solutes. The solubility of a gas in any solvent increases as the pressure above the solution increases

  30. 3 Factors Affecting Solubility • 3. Intermolecular forces: “like dissolves like;” meaning polar substances dissolve polar substances and non-polar substances dissolve non-polar substances. • Miscibility: the ability to mix without separating into two phases

  31. Miscible: substances that mix togetherie. Vinegar and water Immiscible: substances that do not mix togetherie. Oil and water

  32. SOLUTION CONCENTRATION: the amount of solute in a solution Dilute solution: contains small amounts of solute (dissolved particles) Concentrated solution: contains large amounts of solute

  33. MASS PERCENT:the number of grams of solute per 100 grams of solution Mass Percent = mass of solute x 100% mass of solution

  34. EXAMPLE 1 • Calculate the mass percent of NaCl in a solution containing 15.3 g of NaCl and 155.0 g water. (8.98%NaCl)

  35. EXAMPLE 2 Calculate the mass percent of a solution containing 27.5 g of ethanol and 175 mL of water. The density of water is 1.0 g/mL.13.6%)

  36. Example 3 • You have 1,500 g of a bleach solution. The percent by mass of the solute sodium hypochlorite, NaOCl, is 3.62%. How many grams of NaOCl are in the solution? (54.3 g)

  37. MOLARITY (M): the number of moles of solute dissolved per liter of solution. Note: Here, volume refers to the total volume of the solution,not the volume of the solvent. • Molarity (M) = moles of solute liters of solution • M is pronounced “molar”

  38. EXAMPLE 1 Calculate the molarity if water is added to 2.0 mol of glucose to give 5.0 L of solution. (0.40 M)

  39. EXAMPLE 2 A solution contains 0.900 g of NaCl per 100 mL of solution. What is the molarity? (0.154 M)

  40. Example 3 • How many moles of Na2SO4 are needed to prepare 1.5L of 0.20 M Na2SO4? (0.30 moles solute)

  41. Example 4 How many grams of solute are contained in 250 mL of 3.0 M NaOH? (30. g NaOH)

  42. Example 5 • How would you prepare 250 mL of a 0.500 M NaCl solution? (7.31 g NaCl)

  43. Preparing a Solution from a Solid

  44. SOLUTION DILUTION: adding solvent to a concentrated (stock) solution to make a less concentrated (dilute)solution

  45. DILUTION

  46. Moles Before= Moles After • Number moles before dilution = number moles after dilution • Use the dilution equation • M1 x V1 = M2 x V2

  47. QUESTION 1 How many milliliters of 12.0 M HCl are needed to prepare 750. ml of 0.250 M HCl? (15.6 mL)

  48. QUESTION 2 How would you prepare 5.00 L of a 1.50 M KCl from a 12.0 M stock solution?(0.625 L)

  49. Making a dilute solution from a concentrated solution

  50. Example 3 • What is the molarity of the resulting solution when the following mixture is prepared? 150.0 mL of water is added to 55.0 mL of 6.50 M NaOH. (1.74 M)

More Related