1 / 9

Physics Practical Deflection of light through a glass block

Physics Practical Deflection of light through a glass block. It is important that the length is measured very accurately from the graph. Ruler ’ s precision is ± 1mm. Interval of 10 degrees No d.p. [1]. Correct reading; as θ increases, d increases. [1]

hien
Download Presentation

Physics Practical Deflection of light through a glass block

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Physics PracticalDeflection of light through a glass block

  2. It is important that the length is measured very accurately from the graph. Ruler’s precision is ± 1mm.

  3. Interval of 10 degrees • No d.p. • [1] • Correct reading; asθincreases, d increases. [1] • d ± 1 mm since it is read from a metre rule. [1]

  4. A – Axis labelled correctly with quantity / unit P – Points plotted accurately and with a neat x L – Line of best fit is drawn * equal distribution of points above and below the line, line is not too thick * follow trend instead of trying to pass through all the points S – Correct scale is used * more than ½ of the grid is used by the plotted points * no awkward scale like 3 cm rep 2 mm or 2 cm rep 3 degrees etc is used • Graph Plotting

  5. 12. Plot a graph of d (vertical axis) against θ (horizontal axis) on the grid provided in pg 3.

  6. 13. From your graph, what is the effect on d as θ increases? • As θ increases, d increases. 14. Determine the value of d from the graph when θ = 46o. • Working must be shown on the graph. • Answer must include unit. • d = 23.5 mm

  7. 15. When θ = 0o, the incident ray is normal to the glass surface. What would you expect the value of d to be? Explain your answer. • I expect d to be zero. • When θ = 0o, light enters the glass block perpendicularly and will not bend. Since there is no refraction, the incident and refracted ray is along the same line and d = 0.

  8. 16. If the glass block is replaced by a transparent block that has a higher refractive index than glass, predict how the shape of the graph would look like. Sketch the graph you predict on the grid and label it ‘P’. • When refractive index of the medium is higher, light will bend more hence for each θ, the d value will be larger. • The graph will thus be higher than the original graph.

  9. 17. What is the effect on the accuracy of the readings taken if the optical pins are replaced with toothpicks of the same height? Explain your answer. • The readings will be less accurate because the toothpick is thicker than optical pins [1] hence there is a larger range in position in which the toothpicks are aligned. [1] • Or • The toothpicks will make a larger hole on the paper [1] hence the accuracy of the line will decrease as it is harder to draw through the centre of the hole accurately. [1]

More Related