1 / 15

Solving Quadratic Equations

Solving Quadratic Equations. What does x = ?????. Solving Quadratic Equations What does x =?. Five different ways: By Graphing By Factoring By Square Root Method By Completing the Square By Quadratic Formula Number of Solutions:

cdunham
Download Presentation

Solving Quadratic Equations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Solving Quadratic Equations What does x = ?????

  2. Solving Quadratic EquationsWhat does x =? • Five different ways: • By Graphing • By Factoring • By Square Root Method • By Completing the Square • By Quadratic Formula • Number of Solutions: • There can be either 1 or 2 solutions to a quadratic equation.

  3. Classification of Solutions • Solutions to quadratic equations are called: • “Roots” of the equation • “Zeros” of the function • Solutions can be: • Real (Rational or Irrational) • Complex (Imaginary)

  4. Classifying Solutions • Solutions must be in simplified radical form • If no radicals left, answers are rational. • If radical left, answers are irrational. • Watch out! • If taking the square root of a negative number, answers are complex (imaginary)!!!!

  5. By Taking Square Root • First you must isolate the x² or (x-h)² term. • Then, take the square root of both sides. • You will use ± (plus/minus) for the answer.

  6. Examples

  7. Examples

  8. By Factoring • Place equation in standard form: ax² + bx + c = 0 • Factor the expression • Use the Principle of Zero Product Rule to solve for x. • To classify: • If the expression is factorable, the solutions are “rational” • (There will be either 1 or 2 solutions) • If the expression is prime (not factorable), the solutions may be irrational or complex – not enough info to decide!

  9. Solve Quadratic equation by factoring example • Example: • Put in standard form first: • Factor • Use principle of zero product rule (if multiplying two things together and =0, then one of those things must be 0.) • The GCF of 4 has no relevance to final answer.

  10. By Completing the Square • Complete the square, then isolate the (x-h)² term. • Solve by square root method.

  11. By Quadratic Formulaax² + bx + c = 0

  12. By Graphing • You have done this! • Graph one side of equation in Y1, other side in Y2. • 2nd Calc Intersect to find the intersection of the two functions. • Classify solutions: • If graphs intersect twice, there are 2 solutions. (2 real solutions) • If graphs intersect once, there is 1 solution (1 real solution) • If graphs never intersect, there are no “real” solutions, but there are 2 complex solutions

  13. Discriminant-used to classify solutions of quadratic equations • The discriminant is the radicand portion of the quadratic formula: Discriminant = b²-4ac If discriminant = 0, one rational solution If discriminant = perfect square number, 2 rational solutions If discriminant = non-perfect square number, 2 irrational solutions If discriminant = negative number, 2 complex solutions

  14. Solving Word Problems that are quadratic (area problems) • Draw a picture! • Find an expression for length and width in terms of a variable. • Find an expression for area in terms of the variable. • Set the actual number for area equal to the expression. • Put quadratic equation in standard form (set = 0) • Factor and solve by factoring.

  15. x m 3 x m x + 2 Word Problem Example • The dimensions of the original square are x by x m. • The dimensions of the new rectangle are (x + 2) by (x-3) • A square garden is increased by 2 on one side and decreased by 3 on the other, to form a rectangular garden. The area of the new garden is 50 m². Find the dimensions of the original garden. • Area of the new rectangle is (x + 2)(x – 3) or x² - x -6. x-3 The original dimensions of the square is 8 x 8. The new dimensions are 10 x 5

More Related