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OLGT: Solving Quadratic EquationsPowerPoint Presentation

OLGT: Solving Quadratic Equations

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OLGT: Solving Quadratic Equations

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OLGT: Solving Quadratic Equations

Do Now

Solve each equation. Decide whether each equation is an identity, a conditional or a contradiction.

-5(x+3) - 4x-5=-(9x-4)

-6(2x+1)-3(x-4)=-15+1

- A quadratic equation written in standard form is
- Ax2+bx+c = 0, where a, b, c are real numbers and a can not equal zero.
- You can solve them by using one of the three methods
- Zero-factor Property
- Square Root Property
- Quadratic Formula

- Solve 6x2+7x=3
- First put in standard form
- 6x2+7x-3=0
- Then factor
- (3x-1)(2x-3)=0

- Apply the zero-factor property
- 3x-1=0 or 2x+3=0
- 3x=12x=-3
- X=1/3x=-3/2
- Check
- 6(1/3)2+7(1/3)=3 and
- 6(-3/2)2+7(-3/2)=3

- Solve the quadratic equations
1. x2=172. (x-4)2=12

X=x-4 =

x=4 x=x=4

- -6x2+7x = -10
- -6x2+7x + 10 = 0
- -1(6x2-7x - 10)=0
- -1(6x+5)(x-2) =0
- 6x-5=0 or x-2 =0
- 6x=5
- X=5/6 or x=2

- (x-7)2=24
- X-7 =
- X =7
- X=7
- 7

- 1
- (x+4) (x-2) = 0
- X = -4 or x = 2
- ( 2x + 5) (x-3) = 0
- 2x+5 = 0 x-3=0
- X= -5/2x= 3

- x2+ 2x -8 = 0

- 2x2- x -15 = 0

1. X2 = 25

- X =

- X = 5

- 2. ( 3x-1) 2 =12
- 3x – 1 =
- 3x = 1
- x = 1
- 3

- Page 441 # 33-44