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OLGT: Solving Quadratic Equations

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OLGT: Solving Quadratic Equations

Do Now

Solve each equation. Decide whether each equation is an identity, a conditional or a contradiction.

5(x+3) + 4x-5=-(2x-4)

-6(2x+1)-3(x-4)=-15+1

- A quadratic equation written in standard form is
- Ax2+bx+c = 0, where a, b, c are real numbers and a can not equal zero.
- You can solve them by using one of the three methods
- Zero-factor Property
- Square Root Property
- Quadratic Formula

- Solve 6x2+7x=3
- First put in standard form
- 6x2+7x-3=0
- Then factor
- (3x-1)(2x-3)=0

- Apply the zero-factor property
- 3x-1=0 or 2x+3=0
- 3x=12x=-3
- X=1/3x=-3/2
- Check
- 6(1/3)2+7(1/3)=3 and
- 6(-3/2)2+7(-3/2)=3

- Solve the quadratic equations
x2=172. (x-4)2=12

X=x-4 =

x=4 x=x=4

- -6x2+7x =10
- -6x2+7x -10 = 0
- -1(6x2-7x +10)=0
- -1(6x+5)(x-2) =0
- 6x-5=0 or x-2 =0
- 6x=5
- X=5/6 or x=2

- (x-7)2=24
- X-7 =
- X =7
- X=7
- 7

- Page 441 # 33-44