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Find the center of the circle that circumscribes XYZ . PowerPoint Presentation
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Find the center of the circle that circumscribes XYZ . - PowerPoint PPT Presentation


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Find the center of the circle that circumscribes XYZ . Because X has coordinates (1, 1) and Y has coordinates (1, 7), XY lies on the vertical line x = 1. The perpendicular bisector of XY is the horizontal line that passes through (1, ) or (1, 4), so the equation

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Presentation Transcript
slide1

Find the center of the circle that circumscribes XYZ.

Because X has coordinates (1, 1) and Y has

coordinates (1, 7), XY lies on the vertical line x = 1.

The perpendicular bisector of XY is the horizontal line

that passes through (1, ) or (1, 4), so the equation

of the perpendicular bisector of XY is y = 4.

1 + 7

2

Because X has coordinates (1, 1) and Z has coordinates (5, 1), XZ lies on

the horizontal line y = 1. The perpendicular bisector of XZ is the vertical line

that passes through ( , 1) or (3, 1), so the equation of the perpendicular

bisector of XZ is x = 3.

1 + 5

2

Concurrent Lines, Medians, and Altitudes

LESSON 5-3

Additional Examples

slide2

The lines y = 4 and x = 3 intersect at the point (3, 4).

This point is the center of the circle that circumscribes XYZ.

Concurrent Lines, Medians, and Altitudes

LESSON 5-3

Additional Examples

(continued)

Quick Check

slide3

The roads form a triangle around the park.

Concurrent Lines, Medians, and Altitudes

LESSON 5-3

Additional Examples

City planners want to locate a fountain equidistant from three straight roads that enclose a park. Explain how they can find the location.

Theorem 5-7 states that the bisectors of the

angles of a triangle are concurrent at a point

equidistant from the sides.

The city planners should find the point of concurrency of the angle

bisectors of the triangle formed by the three roads and locate the

fountain there.

Quick Check

slide4

M is the centroid of WOR, and WM = 16. Find WX.

2

3

Because M is the centroid of WOR, WM = WX.

2

3

WM = WXTheorem 5-8

2

3

16 = WXSubstitute 16 for WM.

3

2

24 = WXMultiply each side by .

Concurrent Lines, Medians, and Altitudes

LESSON 5-3

Additional Examples

The centroid is the point of concurrency of the

medians of a triangle.

The medians of a triangle are concurrent at a

point that is two thirds the distance from each

vertex to the midpoint of the opposite side.

(Theorem 5-8)

Quick Check

slide5

Is KX a median, an altitude, neither, or both?

Because LX = XM, point X is the midpoint of LM, and KX is a median

of KLM.

Because KX is perpendicular to LM at point X, KX is an altitude.

So KX is both a median and an altitude.

Concurrent Lines, Medians, and Altitudes

LESSON 5-3

Additional Examples

Quick Check