Chemical Equilibrium Calculation for the Reaction of PCl3 and Cl2 to Form PCl5
This document explores the equilibrium calculation for the chemical reaction between phosphorus trichloride (PCl3) and chlorine gas (Cl2) to produce phosphorus pentachloride (PCl5). Using the equilibrium constant (K = 0.0870), we derive expressions for the concentrations of the reactants and products at equilibrium. We discuss the changes in molar concentrations and solve for the values of X representing changes in concentration due to the shift in equilibrium. The final equilibrium concentrations for PCl3, Cl2, and PCl5 are calculated in terms of their atm values.
Chemical Equilibrium Calculation for the Reaction of PCl3 and Cl2 to Form PCl5
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Presentation Transcript
Q = PPCL5 = 0.10 = 0.5 PPCL3 * PCl2 0.30 * 0.60Q (0.58) > K (0.0870) therefore reverse PCl3(g) + Cl2(g) PCl5(g)
K = PPCL5 = (0.10-X) PPCL3 * PCl2 (0.30+X) (0.60+X)PCl3(g) + Cl2(g) PCl5(g)
0.0870= (0.10-X) (0.30+X) (0.60+X) (0.10-X) (0.18 + 0.90X + X2)
0.0870X2 + 0.0783X + 0.0157 = 0.10-X 0.0870X2 + 1.0783X - 0.0843 = 0 X= -1.0783 + (1.0783)2 -4(0.0870)(-0.0843) 2(0.0870)
X= -1.0783 + (1.0783)2 -4(0.0870)(-0.0843) 2(0.0870)X= -1.0783 + 1.0918 = 0.078 0.174PCL3 = 0.30 + 0.078 = 0.378 atmCl2 = 0.60 + 0.078 = 0.678 atmPCl3 = 0.10 – 0.078 = 0.022 atm