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Projectile Motion. Velocity Vectors. Horizontal Projectiles. Angled Projectiles. Parts is Parts. Physics is Phun!. Parts is Parts. Velocity Vectors. Horizontal Projectiles. Angled Projectiles. Physics is Phun!. 5 pt. 5 pt. 5 pt. 5 pt. 5 pt. 10 pt. 10 pt. 10 pt. 10 pt. 10 pt.

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## Projectile Motion

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**Parts is Parts**Velocity Vectors Horizontal Projectiles Angled Projectiles Physics is Phun! 5 pt. 5 pt. 5 pt. 5 pt. 5 pt. 10 pt. 10 pt. 10 pt. 10 pt. 10 pt. 15 pt. 15 pt. 15 pt. 15 pt. 15 pt. 20 pt. 20 pt. 20 pt. 20 pt. 20 pt. 25 pt. 25 pt. 25 pt. 25 pt. 25 pt.**1-5**A boat moves normally through the water at a velocity of 5 mph. How fast will the boat be traveling, as seen from shore, going upstream in a river that moves at 3.5 mph? 5 pt.**1-5A**A boat moves normally through the water at a velocity of 5 mph. How fast will the boat be traveling, as seen from shore, going upstream in a river that moves at 3.5 mph? 1.5 mph 5 pt.**1-10**A plane wants to fly due West, but there is a strong crosswind from the South. Draw a vector diagram illustrating what direction the plane should aim to achieve its goal. Include all important vectors. 10 pt.**1-10A**A plane wants to fly due West, but there is a strong crosswind from the South. Draw a vector diagram illustrating what direction the plane should aim to achieve its goal. Include all important vectors. resultant wind plane 10 pt.**1-15**VR 2 1 3 Which way should the swimmer aim to get to the opposite shore the quickest? 15 pt.**1-15A**VR 2 1 3 Which way should the swimmer aim to get to the opposite shore the quickest? Path #2 15 pt.**1-20**A plane travels 100 km/hr due North in a strong crosswind headed 100 km/hr due East. How fast is the plane’s ground-speed? A) 0 km/hr B) 141 km/hr C) 200 km/hr D) not enough info 20 pt.**1-20A**A plane travels 100 km/hr due North in a strong crosswind headed 100 km/hr due East. How fast is the plane’s ground-speed? • 141 km/hr 20 pt.**1-25**A boat needs to move straight across a river. The boat moves at 25 mph relative to the water, and the river is moving at 16 mph as shown. How fast will the boat end up traveling across the river? River ? Boat 25 pt.**1-25A**A boat needs to move straight across a river. The boat moves at 25 mph relative to the water, and the river is moving at 16 mph as shown. How fast will the boat end up traveling across the river? 162 + V2 = 252 V2 = 252 - 162 V = sqrt(252 - 162) V = 19.2 mph 16 mph V 25 mph 25 pt.**2-5**A stone is thrown from the top of a cliff horizontally at a speed of 10 m/sec, while at the same time an identical stone is dropped from the cliff. Neglecting air drag, which one hits the ground first? 5 pt.**2-5A**A stone is thrown from the top of a cliff horizontally at a speed of 10 m/sec, while at the same time an identical stone is dropped from the cliff. Neglecting air drag, which one hits the ground first? They both hit at the same time 5 pt.**2-10**Fill in the Blanks: When an projectile is thrown horizontally, before it hits the ground its horizontal speed ______________ and its vertical speed ____________? 10 pt.**2-10A**Fill in the Blanks: When an projectile is thrown horizontally, before it hits the ground its horizontal speed ______________ and its vertical speed ____________? remains the same increases 10 pt.**2-15**A baseball thrown from the pitcher’s mound travels 145 kph before hitting the ground 1.5 sec later. How far (in meters) is it from the mound to where the ball hits? 15 pt.**2-15A**A baseball thrown from the pitcher’s mound travels 145 kph before hitting the ground 1.5 sec later. How far (in meters) is it from the mound to where the ball hits? v =145 km/hr (1000 m/km) (hr/3600 sec) = 40.3 m/sec d = v t = (40.3 m)(1.5 sec) = 60.4 meters 15 pt.**2-20**A dart is fired horizontally from a toy gun at a speed of 30 cm/sec from a height of 0.45 m. How much time passes before the dart hits the ground? 20 pt.**2-20A**A dart is fired horizontally from a toy gun at a speed of 30 cm/sec from a height of 0.45 m. How much time passes before the dart hits the ground? dy = (1/2)at2 ==> t = √[2 dy/a] t = √[(2*0.45m)/(9.8m/s2)] t = 0.30 seconds 20 pt.**2-25**A softball is tossed horizontally from a treehouse 4 meters tall, and the ball lands 20 meters from the treehouse. How fast was the ball thrown? 25 pt.**2-25A**A softball is tossed horizontally from a treehouse 4 meters tall, and the ball lands 20 meters from the treehouse. How fast was the ball thrown? dx = vxt and dy = (1/2)at2 ==> t = √(2 dy/a) where dy = 4 m t = √[2(4 m)/(10 m/s2] = 0.894 sec v = dx / t = 20m / 0.894 sec = 22.4 m/sec 25 pt.**3-5**A cannonball is launched at a speed of 25.2 m/sec upwards at an angle of 30º above the horizontal. What is the acceleration of the ball in the air? 5 pt.**3-5A**A cannonball is launched at a speed of 25.2 m/sec upwards at an angle of 30º above the horizontal. What is the acceleration of the ball in the air? 9.8 m/sec2 straight down 5 pt.**3-10**A water balloon is launched with a horizontal velocity of 10 m/s and a vertical velocity of 8 m/s. What is the velocity of the balloon at the top of its path? 10 pt.**3-10A**A water balloon is launched with a horizontal velocity of 10 m/s and a vertical velocity of 8 m/s. What is the velocity of the balloon at the top of its path? 10 m/s horizontally. Because the horizontal velocity of a projectile is constant 10 pt.**3-15**Your Team may wager from 0-50 pts. You must make your wager BEFORE the Daily Double is revealed!!! 15 pt.**3-15A**Daily Double Daily Double If an object is launched 24 m/s at an angle of 30o, how much time will it take before it reaches the top? vy = 24 m/s sin Ө = 12 m/s a = ∆v/t ==> t = (vf - vi)/a t = (12 m/s) / (10 m/s2) = 1.2 sec Daily Double**3-20**If a ball is launched upwards from the moving cup, as shown, where will it land relative to the cup? A) in front of the cup B) behind the cup C) inside the cup D) not enough info 20 pt.**3-20A**If a ball is launched upwards from the moving cup, as shown, where will it land relative to the cup? C) inside the cup 20 pt.**3-25**A water balloon is launched at 7.63 m/s at 58.4o above the horizontal. How far (horizontally) does it travel before hitting the ground? 25 pt.**3-25A**A water balloon is launched at 7.63 m/s at 58.4o above the horizontal. How far (horizontally) does it travel before hitting the ground? vix = vi cosӨ = 4 m/s viy = vi sinӨ = 6.5 m/s d = viy t + ½ at2 d = 0 a = -10 m/s2 t = 1.3 sec dx = vxt = (4 m/s)(1.3 sec) = 5.2 meters 25 pt.**4-5**What is the horizontal ‘part’ of an angled vector called? 5 pt.**4-5A**What is the horizontal ‘part’ of an angled vector called? The horizontal ‘component’ (x-component) 5 pt.**4-10**Draw this vector, then draw and label the component vectors. A 10 pt.**4-10A**Draw this vector, then draw and label the component vectors. Ax Ay A 10 pt.**4-15**How can you calculate the vertical component of vector B? 15 pt.**4-15A**How can you calculate the vertical component of vector B? By = Bsinθ 15 pt.**4-20**Vector C has a magnitude of 20 m/s and is at an angle of 30° from the horizontal. What is the vertical component of vector C? 20 pt.**4-20A**Vector C has a magnitude of 20 m/s and is at an angle of 30° from the horizontal. What is the vertical component of vector C? Cy = Csinθ Cy = (20m/s)sin(300) Cy = 10m/s 20 pt.**4-25**Vector D has a magnitude of 80 m and is at an angle of 30° from the vertical. What is the horizontal component of vector D? 25 pt.**4-25A**Vector D has a magnitude of 80 m and is at an angle of 30° from the vertical. What is the horizontal component of vector D? Dx = Dsinθ Dx = (80m/s)sin(300) Dx = 40 m 25 pt.**5-5**How many sides does a circle have? 5 pt.**5-5A**How many sides does a circle have? Two… the inside and the outside! 5 pt.**5-10**Name the character and movie that produced this famous quote: “Archaeology is the search for fact, not truth.” 10 pt.

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