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Chapter 5

Chapter 5 . 5-3 Medians and Altitudes of triangles. Objectives. Apply properties of medians of a triangle. Apply properties of altitudes of a triangle. Median of a triangle.

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Chapter 5

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  1. Chapter 5 5-3 Medians and Altitudes of triangles

  2. Objectives Apply properties of medians of a triangle. Apply properties of altitudes of a triangle.

  3. Median of a triangle • A median of a triangleis a segment whose endpoints are a vertex of the triangle and the midpoint of the opposite side.

  4. Median of a triangle • Every triangle has three medians, and the medians are concurrent. • The point of concurrency of the medians of a triangle is the centroid of the triangle. The centroid is always inside the triangle. The centroid is also called • the center of gravity because it is the point where a triangular region will balance.

  5. Centroid Theorem

  6. Example 1: Using the Centroid to Find Segment Lengths • In ∆LMN, RL = 21 and SQ =4. Find LS. LS = 14

  7. Example#2 • In ∆LMN, RL = 21 and SQ =4. Find NQ. NS + SQ = NQ 12 = NQ

  8. Example#3 • A sculptor is shaping a triangular piece of iron that will balance on the point of a cone. At what coordinates will the triangular region balance?

  9. Solution • 1.Understand the problem • The answer will be the coordinates of the centroid of the triangle. The important information is the location of the vertices, A(6, 6), B(10, 7), and C(8, 2). • 2. Make a plan • The centroid of the triangle is the point of intersection of the three medians. So write the equations for two medians and find their point of intersection.

  10. Solution • 3 Solve • Let M be the midpoint of AB and N be the midpoint of AC.

  11. solution • CM is vertical. Its equation is x = 8. BN has slope 1. Its equation is y = x – 3. The coordinates of the centroid are D(8, 5).

  12. Student guided practice • Do problems 3-6 in your book page 329

  13. Altitude of the triangle • An altitude of a triangle is a perpendicular segment from a vertex to the line containing the opposite side. • Every triangle has three altitudes. An altitude can be inside, outside, or on the triangle.

  14. Orthocenter of the triangle • In ΔQRS, altitude QY is inside the triangle, but RX and SZ are not. Notice that the lines containing the altitudes are concurrent at P. This point of concurrency is the orthocenter of the triangle.

  15. X Example • Find the orthocenter of ∆XYZ with vertices X(3, –2), Y(3, 6), and Z(7, 1). • Solution • Step 1 graph the triangle

  16. solution • Step 2 Find an equation of the line containing the altitude from Z to XY. • Since XY is vertical, the altitude is horizontal. The line containing it must pass through Z(7, 1) so the equation of the line is y = 1.

  17. Solution • Step 3 Find an equation of the line containing the altitude from Y to XZ. The slope of a line perpendicular to XZ is -4/3 . This line must pass through Y(3, 6).

  18. solution • Step 4 Solve the system to find the coordinates of the orthocenter. The coordinates of the orthocenter are (6.75, 1).

  19. Student guided practice • Do problems 8-10 in your book page 329

  20. Homework • Do problems 12-18 in your book page 330

  21. Closure • Today we learned about medians and altitudes of the triangle • Next class we are going to learned chapter5 section 4.

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