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Learn how to efficiently input and graph linear equations and inequalities on your calculator. This guide provides step-by-step instructions for solving various equations, such as y = 3x - 6 and y = -2x + 4, by using the graphing feature. You'll find tips on navigating the calculator functions, finding ordered pair solutions through intercepts, and interpreting the results for both equations and inequalities. Practice finding double shaded regions and points of intersection to strengthen your understanding.
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Calculator Skills 2 INPUT EACH EQUATION INTO YOUR CALCULATOR AND PRESS GRAPH THEN FIND THE ORDERED PAIR SOLUTION HOLD UP YOUR CACLULATOR WHEN YOU HAVE THE SOLUTION
y = 3x 6 y = 2x + 4 • INPUT INTO y1 AND y2 • GRAPH • 2ND • TRACE (CALC) • 5 (INTERCEPT) • ENTER, ENTER, ENTER
(2,0) • y1 = 3x 6 y2 = 2x + 4
4x – 2y = 8 y = 7x + 5 • INPUT INTO y1 AND y2 • GRAPH • 2ND • TRACE (CALC) • 5 (INTERCEPT) • ENTER, ENTER, ENTER
(1, –2) • y1 = (8 – 4x)/ – 2 y2 = 7x + 5
3x + 6y = 12 y 3 = 2(x 2) (1.2 , 1.4) • y1 = (12–3x)/6 • y2 = 2(x 2) + 3
y + 1 = 4(x 2) y = 6x 10 (.5 , –7) • y1 = 4(x 2) – 1 • y2 = 6x 10
5x – y = 2 – x + y = 2 (1 , 3) • y1 = (2– 5x)/ – 1 • y2 = (2 + x)/1
2x + 2y = 6 – 2x + 3y = –1 (2, 1) • y1 = (6 – 2x)/ 2 • y2 = (–1 + 2x)/ 3
– 2y – 2x = – 8 2y – 3x = – 2 LOOK AT WHERE THE “X” AND “Y” ARE LOCATED IN PROBLEM (2, 2) • y1 =( – 8 +2x )/–2y2 =( – 2 + 3x)/ 2
4y = 3x – 2 3x + 2y = – 10 (–2, –2) • y1 = (– 2+3x)/4 • y2 = (– 10 –3x)/2
4x + (–2y) + x = 2 6x + 2y = – 4 (-.181818, –1.454545) • y1= (2 – 4x –x)/ –2 • y2 = (– 4 – 6x)/2
2x + 2y ≤ 6 y ≥ x + 1 • FOR INEQALITIES INPUT EQ. INTO y1 AND y2 • USE LEFT SCROLL ARROW TO MOVER CURSER TO EXTREME LEFT • PRESS ENTER UNTIL YOU GET THE UP RIGHT TRIANGLE ( GREATER THAN) • OR PRESS ENTER UNTIL YOU GET THE DOWN RIGHT TRIANGLE (LESS THAN) • PRESS GRAPH • LOOK FOR DOUBLE SHADED REGION • FIND POINT OF INTERSECTION
Left double shaded with (1,2) intercept • y ≤ (6 – 2x)/2 • y ≥ x + 1
x ≥ – y + 2 y – 3x < 2 • REMEMBER TO REVERSE (OR FLIP ) THE INEQUALITY WHEN DIVIDING OR MULTIPLYING BY A NEGATIVE “–” NUMBER
SHADED LEF: (0,2) • y1 ≤ (x – 2)/ –1 • y2 < (3x+ 2)
3x + 2y > 6 y < 2(x – 2) SHADED RIGHT: (2,0) • y1 > (6 – 3x)/2 y2 < 2(x – 2)
y – 3 ≤ 2(x – 1) x > – 2(y – 1) Upper Right double shaded: (0,1) • y1 ≤ 2(x – 1) + 3 • y2 > (x – 2)/–2
2y ≥ – 2x + 4 – y – 3 > 2(x – 4) TOP LEFT DOUBLE SHADED:(3, – 1) • y1 ≥ (– 2x + 4)/2 • y2 < (2(x – 4) + 3)/ –1
– 3x + 2y ≤ 3 y > – 3 REMEMBER: SINCE NO “x” IN SECOND INEQALITY, JUST PLACE –3 INTO y2 TOP RIGHT DOUBLE SHADED:(–3, –3) • y1 ≤ (3 +3x)/2 • y2 > – 3